diff b1f9bc4..6fbd3ac nearby_lagrangian_counterexample_v2.txt
diff --git a/nearby_lagrangian_counterexample_v2.txt b/nearby_lagrangian_counterexample_v2.txt
index eaa8306..1115035 100644
--- a/nearby_lagrangian_counterexample_v2.txt
+++ b/nearby_lagrangian_counterexample_v2.txt
@@ -177,7 +177,7 @@ SECTION 2. THE MAIN THEOREM
is even and at least some explicit bound (below, N = 2m with
m >= 20 and with a further open condition m leaves room of at least
ten dimensions; the construction is stable in m). No reader should
- worry about the exact value of N; every inequality we use has
+ worry about the exact value of N; every ineuality we use has
plenty of slack.
The proof will proceed in the order of the plan of Section 1.4. We
@@ -522,7 +522,7 @@ SECTION 3. STABLE TUBE DATA AND A NONZERO CLASS
QED.
Why this class really is nonzero. The only fact that matters
- numerically is the strict inequality
+ numerically is the strict ineuality
|image(partial)| <= 4 < 32 = |pi_9(H^s(*))_(2)|.
@@ -594,7 +594,7 @@ SECTION 3. STABLE TUBE DATA AND A NONZERO CLASS
is positive on the compact set B x S^(2m-1). It therefore has a
positive minimum c and a finite maximum C. Using the polar gradient
formula grad g_b(r u) = r (2 h_b(u) u + grad_S h_b(u)) from Section
- 3.1, we get the first inequality c|w| <= |grad_w g_b(w)| <= C|w| for
+ 3.1, we get the first ineuality c|w| <= |grad_w g_b(w)| <= C|w| for
all w = r u. The extension at w = 0 is continuous with value zero
because both sides vanish at w = 0.
@@ -736,7 +736,7 @@ SECTION 4. A FAMILY WITH ONE CRITICAL POINT HAS ZERO TUBE CLASS
df_b(d/dr) = 2 f_b / r < 0 (since f_b < 0 on the negative side there).
The conditions "gradient points so that f_b decreases" and "radial
- outward near r = R_0" are strict linear inequalities in the field;
+ outward near r = R_0" are strict linear ineualities in the field;
convex combinations preserve them, so we can interpolate smoothly and
also uniformly over b. The flow of this field cannot exit through
{ f_b = -delta } (it strictly decreases f_b) and must reach the sphere
@@ -1102,8 +1102,8 @@ SECTION 5. THE ZERO-LEVEL COBORDISM ARGUMENT
need ds_b(V) = +-epsilon |grad h|^2 > 0, which holds because dh is
nonzero near h = 0 (zero is a regular value). Away from the prescribed
regions, use strict descent/ascent for f_b. All the conditions are strict
- linear inequalities in the field; convex patching (partition of unity)
- preserves every applicable inequality and keeps the displayed
+ linear ineualities in the field; convex patching (partition of unity)
+ preserves every applicable ineuality and keeps the displayed
prescription on smaller end collars. Everything is smooth in the compact
parameter space. QED.