diff 3ff9228..b34550f spin_one_periodic_haldane_v2.txt
diff --git a/spin_one_periodic_haldane_v2.txt b/spin_one_periodic_haldane_v2.txt
index 1f7f60a..b2fff58 100644
--- a/spin_one_periodic_haldane_v2.txt
+++ b/spin_one_periodic_haldane_v2.txt
@@ -1,75 +1,75 @@
-\documentclass[11pt]{article}
-\usepackage[T1]{fontenc}
-\usepackage{lmodern}
-\usepackage[margin=1in]{geometry}
-\usepackage{amsmath,amssymb,amsthm,mathtools}
-\usepackage{microtype,booktabs,array,longtable}
-\usepackage{xcolor}
-\usepackage[colorlinks=true,linkcolor=blue!50!black,citecolor=blue!50!black,urlcolor=blue!50!black]{hyperref}
-\newtheorem{theorem}{Theorem}[section]
-\newtheorem{lemma}[theorem]{Lemma}
-\newtheorem{proposition}[theorem]{Proposition}
-\newtheorem{corollary}[theorem]{Corollary}
-\theoremstyle{definition}
-\newtheorem{definition}[theorem]{Definition}
-\theoremstyle{remark}
-\newtheorem{remark}[theorem]{Remark}
-\newcommand{\C}{\mathbb C}
-\newcommand{\R}{\mathbb R}
-\newcommand{\Z}{\mathbb Z}
-\newcommand{\cH}{\mathcal H}
-\DeclareMathOperator{\Tr}{Tr}
-\DeclareMathOperator{\spec}{spec}
-\newcommand{\norm}[1]{\lVert #1\rVert}
-\numberwithin{equation}{section}
-\setlength{\emergencystretch}{5em}
-\title{The periodic spin-one Haldane gap}
-
-\begin{document}
+
+
+
+
+
+
+
+
+
+
+
+
+
+
+
+
+
+
+
+
+
+
+
+
+
+# The periodic spin-one Haldane gap
+
+
 \maketitle
-\begin{abstract}
+Abstract: 
 We prove a uniform positive spectral gap for the antiferromagnetic
 spin-one Heisenberg chain on even periodic rings, in the
-$\liminf$ (even-periodic) formulation of the spin-one Haldane
+$liminf$ (even-periodic) formulation of the spin-one Haldane
 conjecture.  The proof combines a spatial transfer operator, a
 purity bootstrap that doubles length and inverse temperature
 together, and two finite, exactly verified initial data sets.
-\end{abstract}
 
-\section{Introduction}\label{sec:introduction}
+
+# Introduction
 
 Haldane predicted that antiferromagnetic Heisenberg chains behave
 differently for integer and half-odd-integer spin
-\cite{Haldane1981,Haldane1983PRL,Haldane1983PLA}.  For spin one the
+[cite].  For spin one the
 prediction is a positive gap above the ground energy.  We prove this
 for the pure bilinear model on even periodic rings, with bounds that
 are uniform in the ring length.
 
-\begin{theorem}\label{thm:main}
+
 Let $S^x,S^y,S^z\in M_3(\C)$ be self-adjoint spin-one matrices with
 \[
- [S^\alpha,S^\beta]=i\textstyle\sum_\eta\varepsilon_{\alpha\beta\eta}S^\eta,
+ [S^\alpha,S^\beta]=i\textstyle\sum_\etaε_{\alpha\beta\eta}S^\eta,
  \qquad \sum_\alpha(S^\alpha)^2=2I_3 .
 \]
-For even $L\ge4$ put $\cH_L=(\C^3)^{\otimes L}$, and on it
-\begin{equation}\label{eq:main-H}
+For even $L\ge4$ put $\cH_L=(\C^3)^{ ⊗  L}$, and on it
+
  H_L=\sum_{j=0}^{L-1}\sum_{\alpha=x,y,z}S_j^\alpha S_{j+1}^\alpha,
  \qquad S_L^\alpha=S_0^\alpha .
-\end{equation}
+
 Let $E_0(L)$ be the least energy, $E_1(L)$ the next distinct energy,
-$\gamma_L=E_1(L)-E_0(L)$, and $\Delta_1=\liminf_{L\to\infty,
-L\text{ even}}\gamma_L$.  Then the ground state of $H_L$ is unique
+$\gamma_L=E_1(L)-E_0(L)$, and $\Delta_1=liminf_{L\to∞,
+L even}\gamma_L$.  Then the ground state of $H_L$ is unique
 for every even $L\ge60$, and
-\begin{align}
- \gamma_L&>\frac4{105}\log\frac{80}{79} && (L\ge60\text{ even}),
- \label{eq:gap60}\\
- \gamma_L&>\frac{\log 20}{784} && (L\ge2304\text{ even}),
- \label{eq:gap2304}
-\end{align}
+
+ \gamma_L&>\frac4{105}\log(80)/(79) && (L\ge60 even),
+ \\
+ \gamma_L&>(\log 20)/(784) && (L\ge2304 even),
+ 
+
 so $\Delta_1\ge\log(20)/784>0$.  The same conclusions hold for any
 simultaneously similar spin-one realization satisfying the same
 commutator and Casimir normalizations.
-\end{theorem}
+
 
 The next distinct energy always exists: in the $S^z$ basis the
 all-zero and all-$+1$ product vectors have energy expectations $0$
@@ -77,26 +77,26 @@ and $L$, so $H_L$ is not scalar.  Because $H_L$ is self-adjoint and
 non-scalar in finite dimension, its full spectrum has a unique least
 eigenvalue and a next distinct one; $\gamma_L$ is the difference.
 
-\subsection*{How the proof works}
+## How the proof works
 
 A shifted partition function $Z_L(b)=\Tr e^{-b(H_L+aLI)}$ can be
 read in two ways at once.  Physically it is a sum of positive Gibbs
 weights, one per physical eigenvector.  Spatially
-(Section~\ref{sec:transfer}) it is a moment $\Tr(X_b^L)$ of a
+(Section~sec:transfer) it is a moment $\Tr(X_b^L)$ of a
 self-adjoint, Hilbert--Schmidt operator $X_b$; for even $L$ this is a
 sum of nonnegative weights, one per spatial eigenvalue.  One object,
 two probability distributions.
 
 For a probability distribution $(p_i)$ call $\sum_i p_i^2$ its
-\emph{purity}; purity near one means one weight carries almost all
+purity; purity near one means one weight carries almost all
 the mass.  Squaring and renormalizing the weights turns purity defect
-$1-P$ into roughly its square (Lemma~\ref{lem:purity}).  Squaring
+$1-P$ into roughly its square (Lemma~lem:purity).  Squaring
 physical weights doubles the inverse temperature, while squaring
 spatial weights doubles the length.  Exact cancellation identities
-couple the two improvements (Lemma~\ref{lem:rounded-update}), so
+couple the two improvements (Lemma~lem:rounded-update), so
 starting from two finite purity bounds both defects decay doubly
 exponentially as length and inverse temperature double together
-(Proposition~\ref{prop:bootstrap}).  Moment inequalities fill in
+(Proposition~prop:bootstrap).  Moment inequalities fill in
 every intermediate even length.  Finally, purity of the physical
 Gibbs distribution bounds each excited-to-ground weight ratio, hence
 the energy gap.
@@ -105,27 +105,27 @@ Two finite initializations supply the seeds.  One begins at length
 $60$ and inverse temperature $105/4$, the other at length $2304$ and
 inverse temperature $784$ with a smaller defect, giving the stronger
 bound.  Both rest on short-chain thermal traces
-(Appendices~\ref{sec:thermal120}--\ref{sec:thermal72}) and one
+(Appendices~sec:thermal120--sec:thermal72) and one
 explicit family of periodic matrix-product trial vectors
-(Appendix~\ref{sec:trials}).  Every finite step is an exact integer or
+(Appendix~sec:trials).  Every finite step is an exact integer or
 rational computation with stated truncation errors; no floating-point
 eigenvalue estimate is a premise.
 
-\subsection*{Historical context}
+## Historical context
 
 The half-odd-integer side has a rigorous obstruction in the
 low-energy bound of Lieb, Schultz and Mattis
 \cite[Appendix~B, Theorem~2]{LiebSchultzMattis1961}, extended by
-Affleck and Lieb \cite{AffleckLieb1986}; possible ground-state
+Affleck and Lieb [cite]; possible ground-state
 degeneracy is part of that picture.  Integer spin admits a unique
 gapped state, but this distinction alone does not prove a gap for a
 given interaction.
 
 The Affleck--Kennedy--Lieb--Tasaki construction gave a rigorous
 gapped spin-one chain with biquadratic interactions
-\cite{AKLT1987,AKLT1988}.  Its bond interaction is $h+\tfrac13h^2$ up
+[cite].  Its bond interaction is $h+\tfrac13h^2$ up
 to a scalar, with $h=\mathbf S_j\cdot\mathbf S_{j+1}$, whereas
-\eqref{eq:main-H} uses $h$ itself.  Yarotsky proved that a unique
+(eq:main-H) uses $h$ itself.  Yarotsky proved that a unique
 ground state and a uniform
 periodic gap persist under sufficiently small translation-invariant
 finite-range perturbations of the AKLT point
@@ -134,10 +134,10 @@ neighborhood, not a gapped path to the pure bilinear point.
 
 For the pure chain, White and Huse's DMRG study estimated a bulk gap
 of $0.41050(2)$ and effective spin-one-half end modes
-\cite{WhiteHuse1993}; neutron scattering found experimental evidence
+[cite]; neutron scattering found experimental evidence
 in the nearly one-dimensional spin-one antiferromagnet
-$\mathrm{CsNiCl}_3$ \cite{Buyers1986}.  Batista and Ortiz proposed a
-spin--fermion proof \cite{BatistaOrtiz2001}; its gap step uses a
+$CsNiCl_3$ [cite].  Batista and Ortiz proposed a
+spin--fermion proof [cite]; its gap step uses a
 first-order perturbative reduction without a uniform remainder, so it
 does not close the argument.  Tasaki proved a nontrivial
 infinite-chain topological index for the model under a gap assumption
@@ -147,26 +147,26 @@ hypotheses require an argument separate from the even-periodic
 estimates here.
 
 Finite-volume gap criteria include those of Knabe and Nachtergaele
-for frustration-free chains \cite{Knabe1988,Nachtergaele1996}, and the
-sharper thresholds of Gosset and Mozgunov \cite{GossetMozgunov2016}.
+for frustration-free chains [cite], and the
+sharper thresholds of Gosset and Mozgunov [cite].
 Banerjee, Guo and Chowdhury use semidefinite methods to bound string
 correlators
 \cite[Eqs.~(2),~(13), and Figure~4]{BanerjeeGuoChowdhury2026}, a
 different quantity from the uniform spectral gap studied here.
 Our finite inputs are thermal traces of small twisted chains and
 energies of periodic matrix-product vectors
-\cite{FNW1992,PerezGarcia2007}.  The traces are rigorous enclosures of
+[cite].  The traces are rigorous enclosures of
 matrix-exponential traces; validated matrix exponentiation is
-classical \cite{BochevMarkov1989,GoldsztejnNeumaier2014}, and the
+classical [cite], and the
 conditioned Poisson polynomial uses the Fox--Glynn estimate
 \cite[Proposition~1]{FoxGlynn1988}.
 
-The transfer-matrix idea goes back to Suzuki \cite{Suzuki1985}; our
+The transfer-matrix idea goes back to Suzuki [cite]; our
 ordered bond expansion follows Aizenman and Nachtergaele
 \cite[arXiv v1, Section~2.2]{AizenmanNachtergaele1994}, followed by a
 direct operator construction on bond histories.
 
-\section{The model and its twisted partition functions}\label{sec:model}
+# The model and its twisted partition functions
 
 A single object will carry the whole proof: a shifted partition
 function that is simultaneously a physical Gibbs trace and a spatial
@@ -175,77 +175,77 @@ energy bound used to control the finite exponential computations.
 We use self-adjoint spin-one matrices throughout; the non-self-adjoint
 case reduces to this by the next lemma.
 
-\begin{lemma}[Representation]\label{lem:representation}
+[Representation]
 Let $S^x,S^y,S^z\in M_3(\C)$ satisfy
 \[
- [S^\alpha,S^\beta]=i\textstyle\sum_\gamma\varepsilon_{\alpha\beta\gamma}S^\gamma,
+ [S^\alpha,S^\beta]=i\textstyle\sum_\gammaε_{\alpha\beta\gamma}S^\gamma,
  \qquad \sum_\alpha(S^\alpha)^2=2I .
 \]
 They are simultaneously similar to the standard self-adjoint spin-one
 matrices; if they are already self-adjoint, the similarity is unitary.
 The tensor-power similarity preserves the full spectrum of every
 periodic $H_n$.
-\end{lemma}
 
-\begin{proof}
+
+Proof. 
 Put $S^\pm=S^x\pm iS^y$.  The assumptions give
-\begin{equation}\label{eq:ladder-identities}
+
  [S^z,S^\pm]=\pm S^\pm,\qquad
  S^-S^+=2I-(S^z)^2-S^z,\qquad S^+S^-=2I-(S^z)^2+S^z .
-\end{equation}
+
 Take an $S^z$-eigenvector $v$ of eigenvalue $m$ with maximal real part.
 Then $S^+v=0$, so $m=1$ or $m=-2$.  The case $m=-2$ would permit
 indefinite lowering: a last nonzero lowered vector $w$ has weight
 $-2-k$, while $S^+S^-w=0$ forces weight $-1$ or $2$, contradicting
 finite dimension.  Hence $m=1$.
 The vectors $v$, $S^-v/\sqrt2$, $(S^-)^2v/2$ are nonzero by
-\eqref{eq:ladder-identities} and have distinct weights $1,0,-1$; they
+(eq:ladder-identities) and have distinct weights $1,0,-1$; they
 form a basis, and there is no weight $-2$, so they are the whole
 standard spin-one module with ladder coefficients $\sqrt2$.  When the
 matrices are self-adjoint and $\norm v=1$ the vectors are orthonormal.
 Conjugating each tensor factor conjugates every term of $H_n$, so the
 spectrum is unchanged.
-\end{proof}
 
-In the weight basis $|s\rangle$, $s\in\{-1,0,1\}$, the generator is
-$S^z|s\rangle=s|s\rangle$ with ladder entries $\sqrt2$.  In the
+
+In the weight basis $|s>$, $s\in\{-1,0,1\}$, the generator is
+$S^z|s>=s|s>$ with ladder entries $\sqrt2$.  In the
 Cartesian basis indexed by axes, the real matrices
 \[
- (S^\alpha)_{ij}=-i\varepsilon_{\alpha i j},\qquad G_\alpha=iS^\alpha
+ (S^\alpha)_{ij}=-iε_{\alpha i j},\qquad G_\alpha=iS^\alpha
 \]
 obey the same relations; each $G_\alpha$ is real of operator norm one.
-For $h=\sum_\alpha S^\alpha\otimes S^\alpha$ contraction of the epsilon
+For $h=\sum_\alpha S^\alpha ⊗  S^\alpha$ contraction of the epsilon
 tensors gives
-\begin{equation}\label{eq:cartesian-bond}
- -h=\sum_\alpha G_\alpha\otimes G_\alpha,\qquad
- h=F-|\Omega\rangle\langle\Omega|,\quad
- \Omega=\sum_{i=1}^3|ii\rangle,
-\end{equation}
-where $F(u\otimes v)=v\otimes u$.  Hence $h$ has eigenvalues
+
+ -h=\sum_\alpha G_\alpha ⊗  G_\alpha,\qquad
+ h=F-|Ω><Ω|,\quad
+ Ω=\sum_{i=1}^3|ii>,
+
+where $F(u ⊗  v)=v ⊗  u$.  Hence $h$ has eigenvalues
 $-2,-1,1$ and $h\le I$.
 
-\subsection{Twists and partition functions}
+## Twists and partition functions
 
-Number the sites $0,\dots,n-1$ with $n\ge4$.  A proper rotation
+Number the sites $0,...,n-1$ with $n\ge4$.  A proper rotation
 $g\in SO(3)$ is unitary on $\C^3$.  Define
-\begin{equation}\label{eq:twisted-hamiltonian}
+
  H_n(g)=\sum_{j=0}^{n-2}h_{j,j+1}+h_{n-1,0}(g),\qquad
  h_{n-1,0}(g)=\sum_\alpha S_{n-1}^\alpha\,(gS^\alpha g^{-1})_0 ,
-\end{equation}
+
 so only the last bond is conjugated, on its site-$0$ factor; $H_n(g)$
 is self-adjoint and $H_n(I)=H_n$.  With the shift
-\begin{equation}\label{eq:shift}
- a=\frac{700741}{500000},\qquad
+
+ a=(700741)/(500000),\qquad
  Z_n(b,g)=\Tr\exp[-b(H_n(g)+anI)],\qquad Z_n(b)=Z_n(b,I),
-\end{equation}
+
 all $Z_n(b,g)$ are strictly positive, and the scalar shift $an$ will
 cancel from every purity ratio and from the final gap.
 
 We need the diagonal rotations
 \[
- P_x=\operatorname{diag}(1,-1,-1),\quad
- P_y=\operatorname{diag}(-1,1,-1),\quad
- P_z=\operatorname{diag}(-1,-1,1),
+ P_x=diag(1,-1,-1),\quad
+ P_y=diag(-1,1,-1),\quad
+ P_z=diag(-1,-1,1),
 \]
 $D_2=\{I,P_x,P_y,P_z\}$, and the cyclic rotation
 $C:e_x\mapsto e_y\mapsto e_z\mapsto e_x$; write $P=P_x$.  By a global
@@ -254,41 +254,41 @@ partition functions.  After a global rotation and a change to the
 weight basis, $P$ and $C$ act as $\exp(-i\theta S^z)$ with
 $\theta=\pi$ and $\theta=2\pi/3$.
 
-For later use with explicit matrices, a word $x=(x_0,\dots,x_{n-1})$
+For later use with explicit matrices, a word $x=(x_0,...,x_{n-1})$
 in the weight basis has diagonal entry $\sum_j x_{j-1}x_j$ (indices
 mod $n$); each allowed step changing two neighboring letters by
 opposite units contributes $1$, and a seam step from column $y$ to row
 $x$ contributes the phase
-\begin{equation}\label{eq:seam-phase}
- \exp\!\bigl(i\theta(y_0-x_0)\bigr),
-\end{equation}
+
+ \exp\!(i\theta(y_0-x_0)),
+
 since $gS^\pm g^{-1}=e^{\mp i\theta}S^\pm$.  These formulas tie the
 finite matrices below to the physical $H_n(g)$ in
-\eqref{eq:twisted-hamiltonian}.
+(eq:twisted-hamiltonian).
 
-\subsection{A uniform energy bound}
+## A uniform energy bound
 
-\begin{lemma}[Energy bounds]\label{lem:energy}
-For every $n\ge4$ and $g\in SO(3)$, $-\tfrac{3n}{2}I\le H_n(g)\le nI$.
-\end{lemma}
+[Energy bounds]
+For every $n\ge4$ and $g\in SO(3)$, $-(3n)/(2)I\le H_n(g)\le nI$.
 
-\begin{proof}
+
+Proof. 
 The upper bound is $h\le I$ plus unitary conjugation of the seam.  For
 the lower bound consider $T=-h_{12}-h_{23}$ on three open sites in
-Cartesian coordinates.  By \eqref{eq:cartesian-bond} an unequal pair
+Cartesian coordinates.  By (eq:cartesian-bond) an unequal pair
 swaps with coefficient $-1$, an equal pair changes to either other equal
 pair with coefficient $1$, and there are no diagonal terms.  Give each
 three-letter word a positive weight $q$ according to its equality
 pattern:
-\begin{center}
-\begin{tabular}{c|c|c}
+
+{c|c|c}
 word type & $q$ & absolute weighted row sum\\ \hline
 $aaa$ & $4$ & $3+3+3+3=12$\\
 $aab$ or $abb$ & $3$ & $4+3+2=9$\\
 $aba$ & $2$ & $3+3=6$\\
 $abc$ & $2$ & $2+2=4$
-\end{tabular}
-\end{center}
+
+
 Every row sum is at most $3q$.  With $D$ the diagonal of these weights,
 $D^{-1}TD$ has absolute row sums at most three, hence spectral radius
 at most three; since $T$ is self-adjoint and similar to this matrix,
@@ -299,61 +299,61 @@ untwisted triad (delete the seam bond and rotate all sites on one side,
 using rotation invariance of the internal interaction), so the bound
 holds for every consecutive pair of bonds of $H_n(g)$.  Summing the $n$
 triad inequalities counts each bond twice and gives
-$H_n(g)\ge-\tfrac{3n}{2}I$.
-\end{proof}
+$H_n(g)\ge-(3n)/(2)I$.
+
 
-The trial inputs of Appendix~\ref{sec:trials} give $E_0(n)+an<0$ at
+The trial inputs of Appendix~sec:trials give $E_0(n)+an<0$ at
 $n=72,120$, hence $Z_n(b)>1$ for every $b>0$; those lower bounds are
-paired with finite thermal upper bounds in Section~\ref{sec:initialization}.
+paired with finite thermal upper bounds in Section~sec:initialization.
 
-\section{Partition functions as spatial moments}\label{sec:transfer}
+# Partition functions as spatial moments
 
 We now construct a self-adjoint spatial operator whose $L$th moment is
-the physical partition function \eqref{eq:shift}.  This is what turns
+the physical partition function (eq:shift).  This is what turns
 even spatial powers into positive weights.  The operator itself need
 not be positive.
 
 Let $\mathcal G\subset SO(3)$ be the group of proper signed permutation
 matrices (it contains $D_2$ and $C$).  For $g\in\mathcal G$ write
 \[
- g e_\alpha=\epsilon_g(\alpha)e_{\sigma_g(\alpha)},
- \qquad \epsilon_g(\alpha)\in\{-1,1\}.
+ g e_\alpha=ε_g(\alpha)e_{\sigma_g(\alpha)},
+ \qquad ε_g(\alpha)\in\{-1,1\}.
 \]
 Rotation covariance of the Cartesian matrices gives
-\begin{equation}\label{eq:rotation-covariance}
- gG_\alpha g^{-1}=\epsilon_g(\alpha)G_{\sigma_g(\alpha)} .
-\end{equation}
 
-\begin{proposition}[Spatial transfer]\label{prop:transfer}
+ gG_\alpha g^{-1}=ε_g(\alpha)G_{\sigma_g(\alpha)} .
+
+
+[Spatial transfer]
 For each $b>0$ there are a Hilbert space $\mathcal K_b$, a compact
 self-adjoint operator $X_b$, and a unitary representation
 $g\mapsto U_g$ of $\mathcal G$ commuting with $X_b$, such that
-\begin{equation}\label{eq:spatial-trace}
+
  Z_n(b,g)=\Tr(X_b^nU_g)\qquad(n\ge4,\ g\in\mathcal G).
-\end{equation}
+
 Both $X_b$ and the representation commute with complex conjugation, and
 $X_b$ is Hilbert--Schmidt, so $X_b^k$ is trace class for every integer
 $k\ge2$.  If $\lambda_i(b)$ are the nonzero eigenvalues, counted with
 multiplicity, then
-\begin{equation}\label{eq:spatial-moments}
- \sum_i|\lambda_i(b)|^k<\infty\ (k\ge2),\qquad
+
+ \sum_i|\lambda_i(b)|^k<∞\ (k\ge2),\qquad
  Z_n(b)=\sum_i\lambda_i(b)^n\ (n\ge4).
-\end{equation}
-\end{proposition}
 
-\begin{proof}
-\emph{Histories and kernel.}  A bond history is a finite ordered list
+
+
+Proof. 
+Histories and kernel.  A bond history is a finite ordered list
 \[
- x=((t_1,\alpha_1),\dots,(t_k,\alpha_k)),\quad
- 0<t_1<\dots<t_k<b,\ \alpha_j\in\{x,y,z\},
+ x=((t_1,\alpha_1),...,(t_k,\alpha_k)),\quad
+ 0<t_1<...<t_k<b,\ \alpha_j\in\{x,y,z\},
 \]
-including the empty list.  Let $\Omega_b$ be the disjoint union of
+including the empty list.  Let $Ω_b$ be the disjoint union of
 these labeled simplexes, with Lebesgue measure on each and unit mass on
 the empty history.  The measure is finite:
-\begin{equation}\label{eq:history-mass}
- \mu(\Omega_b)=\sum_{k\ge0}\frac{3^kb^k}{k!}=e^{3b},
- \qquad \mathcal K_b=L^2(\Omega_b,\mu;\C).
-\end{equation}
+
+ \mu(Ω_b)=\sum_{k\ge0}(3^kb^k)/(k!)=e^{3b},
+ \qquad \mathcal K_b=L^2(Ω_b,\mu;\C).
+
 For two histories $x,y$, merge their labeled times increasingly and let
 $k_b(x,y)$ be the trace of the resulting time-ordered product of the
 $G_\alpha$ (empty pair: the identity, trace three; time collisions: a
@@ -361,90 +361,90 @@ null event, set kernel zero).  Since $\norm{G_\alpha}=1$ the kernel is
 real with $|k_b(x,y)|\le3$, and exchanging $x,y$ keeps the merged
 product unchanged, so $k_b(y,x)=k_b(x,y)$.  The integral operator
 $K_b$ is thus self-adjoint and Hilbert--Schmidt with
-$\norm{K_b}_{\mathrm{HS}}^2\le9e^{6b}$.  Set $X_b=e^{-ab}K_b$; compact
+$\norm{K_b}_{HS}^2\le9e^{6b}$.  Set $X_b=e^{-ab}K_b$; compact
 self-adjoint spectral theory gives real square-summable eigenvalues,
-and boundedness gives $\sum_i|\lambda_i|^k<\infty$ for $k\ge2$.
+and boundedness gives $\sum_i|\lambda_i|^k<∞$ for $k\ge2$.
 
-\emph{Rotations.}  The permutation $\sigma_g$ acts on labels preserving
-times and measure.  Put $s_g(x)=\prod_{\alpha\in x}\epsilon_g(\alpha)$
+Rotations.  The permutation $\sigma_g$ acts on labels preserving
+times and measure.  Put $s_g(x)=\prod_{\alpha\in x}ε_g(\alpha)$
 and $(U_g f)(x)=s_g(\sigma_g^{-1}x)f(\sigma_g^{-1}x)$.  The cocycle rule
 $s_{gh}(x)=s_g(\sigma_hx)s_h(x)$ shows these real unitaries form a
 representation.  Rotating every matrix inside a site trace, via
-\eqref{eq:rotation-covariance}, gives
+(eq:rotation-covariance), gives
 $k_b(\sigma_gx,\sigma_gy)=s_g(x)s_g(y)k_b(x,y)$, so $U_g$ commutes with
 $K_b$, $X_b$; the kernel of $K_bU_g$ is
-\begin{equation}\label{eq:twisted-kernel}
+
  (K_bU_g)(x,y)=k_b(x,\sigma_gy)s_g(y).
-\end{equation}
 
-\emph{The cycle trace.}  For $n\ge2$ both $K_b^{n-1}$ and $K_bU_g$ are
+
+The cycle trace.  For $n\ge2$ both $K_b^{n-1}$ and $K_bU_g$ are
 Hilbert--Schmidt (the iterated kernel of $K_b^{n-1}$ is bounded because
 $k_b$ is bounded and $\mu$ finite).  The Hilbert--Schmidt product trace
 identity $\Tr(AB)=\int a(x,y)b(y,x)\,d\mu x\,d\mu y$ and
-\eqref{eq:twisted-kernel} give
-\begin{equation}\label{eq:cycle-integral}
- \Tr(K_b^nU_g)=\int_{\Omega_b^n}\Bigl(\prod_{j=0}^{n-2}k_b(x_j,x_{j+1})\Bigr)
+(eq:twisted-kernel) give
+
+ \Tr(K_b^nU_g)=\int_{Ω_b^n}(\prod_{j=0}^{n-2}k_b(x_j,x_{j+1}))
  k_b(x_{n-1},\sigma_gx_0)s_g(x_0)\,d\mu^n ,
-\end{equation}
+
 with all iterated integrals absolutely integrable, so no diagonal
 formula for $K_b$ is needed.
 
-\emph{Identification.}  Expand $\exp[-bH_n(g)]$ in its ordered-time
-series.  By \eqref{eq:cartesian-bond} each event picks a bond and one of
+Identification.  Expand $\exp[-bH_n(g)]$ in its ordered-time
+series.  By (eq:cartesian-bond) each event picks a bond and one of
 three labels and inserts the corresponding two $G$ factors; at the seam
 the site-$0$ factor is rotated.  At total degree $k$ there are $(3n)^k$
 choices each of tensor norm at most one, so absolute convergence holds:
-\begin{equation}\label{eq:history-absolute}
- 3^n\sum_{k\ge0}\frac{(3nb)^k}{k!}=3^ne^{3nb}.
-\end{equation}
+
+ 3^n\sum_{k\ge0}((3nb)^k)/(k!)=3^ne^{3nb}.
+
 We may regroup by bond; interleavings of bond histories partition the
 global time simplex up to null collisions, and at each site the tensor
 trace is the kernel on the two incident histories in their original
 chronological order.  For an explicit seam check, call its history
-$e_0$ and the others $e_1,\dots,e_{n-1}$ around the ring.  The physical
+$e_0$ and the others $e_1,...,e_{n-1}$ around the ring.  The physical
 integrand is
 \[
- s_g(e_0)k_b(\sigma_ge_0,e_1)k_b(e_1,e_2)\cdots k_b(e_{n-1},e_0),
+ s_g(e_0)k_b(\sigma_ge_0,e_1)k_b(e_1,e_2)... k_b(e_{n-1},e_0),
 \]
-which equals the right side of \eqref{eq:cycle-integral} after setting
-$x_0=e_0,x_1=e_{n-1},\dots,x_{n-1}=e_1$ (spatial enumeration reversed,
+which equals the right side of (eq:cycle-integral) after setting
+$x_0=e_0,x_1=e_{n-1},...,x_{n-1}=e_1$ (spatial enumeration reversed,
 chronological products untouched).  Thus
 $\Tr e^{-bH_n(g)}=\Tr(K_b^nU_g)$, and multiplying by $e^{-abn}$ gives
-\eqref{eq:spatial-trace}; the compact trace formula gives
-\eqref{eq:spatial-moments}.
-\end{proof}
+(eq:spatial-trace); the compact trace formula gives
+(eq:spatial-moments).
 
-For even $n\ge4$, \eqref{eq:spatial-trace} supplies the probabilities
-\begin{equation}\label{eq:spatial-probabilities}
- p_i=\frac{|\lambda_i(b)|^n}{Z_n(b)},\qquad
+
+For even $n\ge4$, (eq:spatial-trace) supplies the probabilities
+
+ p_i=(|\lambda_i(b)|^n)/(Z_n(b)),\qquad
  \sum_i p_i=1,\qquad
  \sum_i p_i^2=\frac{Z_{2n}(b)}{Z_n(b)^2}.
-\end{equation}
+
 Odd moments are also useful for polynomial estimates, but evenness is
 essential here.  The spatial eigenvalues are distinct from the physical
 energies of $H_n$.
 
-\subsection{Rotation sectors}
+## Rotation sectors
 
 Small twisted partition functions split the spatial spectrum into a few
 lists with known multiplicities; this later isolates a dominant weight.
 
-\begin{lemma}[Sector moments]\label{lem:sectors}
-Fix $b>0$ and let $X_b,U_g$ be as in Proposition~\ref{prop:transfer}.
+[Sector moments]
+Fix $b>0$ and let $X_b,U_g$ be as in Proposition~prop:transfer.
 There are real eigenvalue lists (with multiplicity) whose integer
 moments $I_k,O_k,N_k$ converge absolutely for $k\ge2$, with
-\begin{align}
- Z_n(b)&=I_n+2O_n+3N_n,\label{eq:sector-total}\\
- Z_n(b,P)&=I_n+2O_n-N_n,\label{eq:sector-pi}\\
- Z_n(b,C)&=I_n-O_n\qquad(n\ge4).\label{eq:sector-cyclic}
-\end{align}
+
+ Z_n(b)&=I_n+2O_n+3N_n,\\
+ Z_n(b,P)&=I_n+2O_n-N_n,\\
+ Z_n(b,C)&=I_n-O_n\qquad(n\ge4).
+
 The $I$ list is the restriction to the joint invariant subspace of
 $D_2$ and $C$; the $O$ list occurs twice and the $N$ list three times
 in the full spatial list.  All three moments are nonnegative at even
 order, and $J_n=I_n+2O_n$ is the moment on the $D_2$-invariant subspace.
-\end{lemma}
 
-\begin{proof}
+
+Proof. 
 The four $D_2$ characters define orthogonal projections
 $\Pi_\chi=\frac14\sum_{g\in D_2}\chi(g)U_g$ commuting with $X_b$ and
 summing to the identity.  Conjugation by $U_C$ permutes the three
@@ -455,171 +455,171 @@ of $U_C$ ($\omega=e^{2\pi i/3}$); these reduce $X_b$, complex
 conjugation exchanges the last two spaces and preserves each real
 eigenvalue of $X_b$ with multiplicity, so their common moment is $O_k$
 and the first space gives $I_k$.  Absolute convergence is
-\eqref{eq:spatial-moments}.
+(eq:spatial-moments).
 
-The decomposition gives \eqref{eq:sector-total}.  On the three
+The decomposition gives (eq:sector-total).  On the three
 nontrivial spaces a fixed $U_P$ has signs $+1,-1,-1$ and is the identity
-on the trivial space, giving \eqref{eq:sector-pi}.  The operator $U_C$
+on the trivial space, giving (eq:sector-pi).  The operator $U_C$
 permutes the nontrivial spaces (zero contribution) and has coefficients
 $1,\omega,\bar\omega$ on the remaining three with
-$\omega+\bar\omega=-1$, giving \eqref{eq:sector-cyclic}.  The $J_n$
+$\omega+\bar\omega=-1$, giving (eq:sector-cyclic).  The $J_n$
 identity is the decomposition of the trivial space, with nonnegativity
 at even order.
-\end{proof}
+
 
 The invariant $I$ space need not be one-dimensional; the point is that
 every weight outside it occurs at least twice in the full list, which
 identifies a unique largest weight without discarding any sector.
 
-\section{From two purities to a uniform gap}\label{sec:bootstrap}
+# From two purities to a uniform gap
 
-The spatial and physical descriptions of the \emph{same} partition
+The spatial and physical descriptions of the same partition
 function give two ways to concentrate its weights.  This section turns
 two initial concentration estimates into a gap at every larger even
 length; the initial estimates are supplied in
-Section~\ref{sec:initialization}.
+Section~sec:initialization.
 
-By Proposition~\ref{prop:transfer}, each partition function is both a
+By Proposition~prop:transfer, each partition function is both a
 physical Gibbs trace (counting every physical eigenvector with
 multiplicity) and, at even lengths, a nonnegative spatial moment
 (counting absolute powers of every spatial eigenvalue).  Define, for
 even $n\ge4$,
-\begin{equation}\label{eq:purities}
+
  S(n,b)=\frac{Z_{2n}(b)}{Z_n(b)^2},\qquad
- T(n,b)=\frac{Z_n(2b)}{Z_n(b)^2}.
-\end{equation}
+ T(n,b)=(Z_n(2b))/(Z_n(b)^2).
+
 The shift $aL$ cancels from both ratios.  First, the inequality behind
 their improvement under squaring.
 
-\begin{lemma}[Squaring probabilities]\label{lem:purity}
+[Squaring probabilities]
 Let $(w_i)$ be a finite or countable family of nonnegative numbers
 with $\sum_iw_i=1$ and purity $P=\sum_iw_i^2\in(0,1]$.  The normalized
 squares $w_i^2/P$ have purity $P'$ with
-\begin{equation}\label{eq:purity-square}
- 1-P'\le f(1-P),\qquad f(u)=\frac{u^2}{2(1-u)^2}\ \ (0\le u<1),
-\end{equation}
+
+ 1-P'\le f(1-P),\qquad f(u)=(u^2)/(2(1-u)^2)\ \ (0\le u<1),
+
 and $f$ is increasing.  Consequently
-\begin{equation}\label{eq:two-squarings}
+
  0<S(n,b),T(n,b)\le1,\quad
  1-S(2n,b)\le f(1-S(n,b)),\quad
  1-T(n,2b)\le f(1-T(n,b)).
-\end{equation}
-\end{lemma}
 
-\begin{proof}
+
+
+Proof. 
 Some weight is positive, so $P>0$, and $w_i^2\le w_i$ gives $P\le1$.
 Nonnegativity allows rearrangement of all countable sums, so
 \[
  1-P'=\frac{2\sum_{i<j}w_i^2w_j^2}{P^2}
- \le\frac{2\bigl(\sum_{i<j}w_iw_j\bigr)^2}{P^2}
- =\frac{(1-P)^2}{2P^2},
+ \le\frac{2(\sum_{i<j}w_iw_j)^2}{P^2}
+ =((1-P)^2)/(2P^2),
 \]
 and $f'(u)=u/(1-u)^3\ge0$.  For $S(n,b)$ use the spatial
 probabilities $|\lambda_i(b)|^n/Z_n(b)$ of
-\eqref{eq:spatial-probabilities}: squaring them changes $n$ to $2n$.
-For $T(n,b)$ list all physical eigenvalues $\varepsilon_k(n)$ with
+(eq:spatial-probabilities): squaring them changes $n$ to $2n$.
+For $T(n,b)$ list all physical eigenvalues $ε_k(n)$ with
 multiplicity and use
-\begin{equation}\label{eq:gibbs-weights}
- w_k(n,b)=\frac{e^{-b(\varepsilon_k(n)+an)}}{Z_n(b)} .
-\end{equation}
+
+ w_k(n,b)=\frac{e^{-b(ε_k(n)+an)}}{Z_n(b)} .
+
 Their purity is $T(n,b)$, and squaring them changes $b$ to $2b$.
-\end{proof}
 
-\subsection{The coupled update}
+
+## The coupled update
 
 The two purities constrain one another because they share partition
 functions; direct cancellation gives
-\begin{align}
- S(n,2b)&=S(n,b)^2\frac{T(2n,b)}{T(n,b)^2},
-   \label{eq:space-time-cancel}\\
- T(4n,b)&=T(2n,b)^2\frac{S(2n,2b)}{S(2n,b)^2}.
-   \label{eq:time-space-cancel}
-\end{align}
+
+ S(n,2b)&=S(n,b)^2(T(2n,b))/(T(n,b)^2),
+   \\
+ T(4n,b)&=T(2n,b)^2(S(2n,2b))/(S(2n,b)^2).
+   
+
 Both denominators are at most one, and the following form lets the two
 initial bounds differ and be rounded upward.
 
-\begin{lemma}[Coupled update]\label{lem:rounded-update}
+[Coupled update]
 Suppose $n\ge4$ even, $b>0$, and $p,q\in[0,1)$ with
 $1-S(n,b)\le p$, $1-T(2n,b)\le q$.  If $p_+,q_+\in[0,1)$ obey
-\begin{equation}\label{eq:rounded-update}
- p_+\ge f\bigl(1-(1-p)^2(1-q)\bigr),\qquad
- q_+\ge f\bigl(1-(1-q)^2(1-p_+)\bigr),
-\end{equation}
+
+ p_+\ge f(1-(1-p)^2(1-q)),\qquad
+ q_+\ge f(1-(1-q)^2(1-p_+)),
+
 then $1-S(2n,2b)\le p_+$ and $1-T(4n,2b)\le q_+$.
-\end{lemma}
 
-\begin{proof}
-Equation \eqref{eq:space-time-cancel} gives
-$S(n,2b)\ge(1-p)^2(1-q)$; spatial squaring in Lemma~\ref{lem:purity}
+
+Proof. 
+Equation (eq:space-time-cancel) gives
+$S(n,2b)\ge(1-p)^2(1-q)$; spatial squaring in Lemma~lem:purity
 and monotonicity of $f$ prove the first bound.  Next
-\eqref{eq:time-space-cancel} gives $T(4n,b)\ge(1-q)^2(1-p_+)$, and
+(eq:time-space-cancel) gives $T(4n,b)\ge(1-q)^2(1-p_+)$, and
 temporal squaring proves the second.  Every input of $f$ lies in $[0,1)$
 because the product subtracted from one is positive and at most one.
-\end{proof}
+
 
 In words: round the first output up, feed it into the second, round
 that up.  The pair based at $(n,b)$ becomes a pair based at $(2n,2b)$
 whose physical member sits at length $4n$; neither bound has to
 decrease.
 
-\subsection{Quadratic decay and intermediate lengths}
+## Quadratic decay and intermediate lengths
 
 Once both defects are small one common bound suffices.  Set
-\begin{equation}\label{eq:bootstrap-coefficient}
- G(u)=\frac12\Bigl((1-u)^{-1}+(1-u)^{-2}+(1-u)^{-3}\Bigr)^2,
-\end{equation}
+
+ G(u)=\frac12((1-u)^{-1}+(1-u)^{-2}+(1-u)^{-3})^2,
+
 increasing on $[0,1)$, with
-\begin{equation}\label{eq:bootstrap-factorization}
- f\bigl(1-(1-u)^3\bigr)=G(u)u^2 .
-\end{equation}
 
-\begin{proposition}[Uniform gap from two initial purities]
-\label{prop:bootstrap}
+ f(1-(1-u)^3)=G(u)u^2 .
+
+
+[Uniform gap from two initial purities]
+
 For every even $L\ge4$ let $H_L$ be a non-scalar finite-dimensional
 self-adjoint Hamiltonian, and suppose that $a\in\R$ and, for each
 $b>0$, a real finite or countable list $(\lambda_i(b))$ satisfy
 \[
- \sum_i|\lambda_i(b)|^4<\infty,\qquad
+ \sum_i|\lambda_i(b)|^4<∞,\qquad
  Z_L(b):=\Tr e^{-b(H_L+aLI)}=\sum_i|\lambda_i(b)|^L
- \quad(L\ge4\text{ even}).
+ \quad(L\ge4 even).
 \]
-Define $S,T$ by \eqref{eq:purities} and $G$ by
-\eqref{eq:bootstrap-coefficient}.  Let $n_0\ge4$ even, $b_0>0$, and let
+Define $S,T$ by (eq:purities) and $G$ by
+(eq:bootstrap-coefficient).  Let $n_0\ge4$ even, $b_0>0$, and let
 $u_0,C$ satisfy
-\begin{equation}\label{eq:bootstrap-hypotheses}
+
  0<u_0<\tfrac16,\quad G(u_0)\le C,\quad r:=Cu_0<1,\quad C(1-3u_0)>3,
-\end{equation}
+
 with seeds
-\begin{equation}\label{eq:bootstrap-seeds}
+
  S(n_0,b_0)\ge1-u_0,\qquad T(2n_0,b_0)\ge1-u_0 .
-\end{equation}
+
 For $j\ge0$ set
-\begin{equation}\label{eq:dyadic-parameters}
+
  n_j=2^jn_0,\quad b_j=2^jb_0,\quad u_j=C^{-1}r^{2^j}.
-\end{equation}
+
 Then
-\begin{equation}\label{eq:dyadic-purities}
+
  S(n_j,b_j)\ge1-u_j,\qquad T(2n_j,b_j)\ge1-u_j,
-\end{equation}
+
 and for every even $L\ge n_0$ the physical ground state is unique with
 gap
-\begin{equation}\label{eq:bootstrap-gap}
- \gamma_L>\frac{\log(1/r)}{b_0}.
-\end{equation}
-\end{proposition}
 
-\begin{proof}
-\emph{Doubling.}  By definition $u_{j+1}=Cu_j^2$, $0<u_{j+1}<u_j\le
+ \gamma_L>(\log(1/r))/(b_0).
+
+
+
+Proof. 
+Doubling.  By definition $u_{j+1}=Cu_j^2$, $0<u_{j+1}<u_j\le
 u_0$.  Suppose both defects at $(n_j,b_j)$ are at most $u=u_j$.  The
-first bound in Lemma~\ref{lem:rounded-update} is at most
+first bound in Lemma~lem:rounded-update is at most
 \[
- f\bigl(1-(1-u)^3\bigr)=G(u)u^2\le Cu^2=u_{j+1}\le u .
+ f(1-(1-u)^3)=G(u)u^2\le Cu^2=u_{j+1}\le u .
 \]
 Use $p_+=u_{j+1}$ in the second update; its input is at most
 $1-(1-u)^3$, so its output is also at most $Cu^2=u_{j+1}$.  Induction
-gives \eqref{eq:dyadic-purities}.
+gives (eq:dyadic-purities).
 
-\emph{Intermediate even lengths.}  For a nonnegative list $(a_i)$ with
+Intermediate even lengths.  For a nonnegative list $(a_i)$ with
 finite positive $p$th-power sum and $q\ge p>0$, normalization gives
 $\sum a_i^q\le(\sum a_i^p)^{q/p}$ (the normalized $p$th powers are
 probabilities, whose $q/p$ powers sum to at most one).  Applied at the
@@ -629,63 +629,63 @@ two temperatures, whenever $n\le L\le2n$ with both even,
  Z_L(2b)\ge Z_{2n}(2b)^{L/(2n)},
 \]
 which combine to
-\begin{equation}\label{eq:purity-interpolation}
- T(L,b)\ge\bigl[T(2n,b)S(n,b)^2\bigr]^{L/(2n)} .
-\end{equation}
+
+ T(L,b)\ge[T(2n,b)S(n,b)^2]^{L/(2n)} .
+
 The bracket lies in $(0,1]$ and the exponent in $[1/2,1]$.  For
 $n=n_j$, $b=b_j$:
-\begin{equation}\label{eq:intermediate-purity}
+
  T(L,b_j)\ge(1-u_j)^3\ge1-3u_j>\tfrac12
- \qquad(n_j\le L\le2n_j,\ L\text{ even}).
-\end{equation}
+ \qquad(n_j\le L\le2n_j,\ L even).
+
 
-\emph{The physical spectrum.}  The largest weight in
-\eqref{eq:gibbs-weights} is at least its purity, since
+The physical spectrum.  The largest weight in
+(eq:gibbs-weights) is at least its purity, since
 $\sum_kw_k^2\le(\max_kw_k)\sum_kw_k$, hence $>1/2$.  These weights count
 all physical eigenvectors, so two ground-state eigenvectors would give
 two equal maximal weights, impossible: the ground state is unique.
 Since $H_L$ is non-scalar and self-adjoint in finite dimension, a next
 distinct energy exists.  Let $w_0$ be the ground weight and $w_1$ the
 weight of an eigenvector at that next energy.  Then
-\begin{align}
+
  e^{-b_j\gamma_L}
- =\frac{w_1}{w_0}
- \le\frac{1-w_0}{w_0}
- \le\frac{3u_j}{1-3u_j}
- \le\frac{3}{C(1-3u_0)}r^{2^j}
+ =(w_1)/(w_0)
+ \le(1-w_0)/(w_0)
+ \le(3u_j)/(1-3u_j)
+ \le(3)/(C(1-3u_0))r^{2^j}
  <r^{2^j},
- \label{eq:gap-ratio}
-\end{align}
-using the shift cancellation and \eqref{eq:bootstrap-hypotheses}.
-Taking logarithms and $b_j=2^jb_0$ gives \eqref{eq:bootstrap-gap} on
+ 
+
+using the shift cancellation and (eq:bootstrap-hypotheses).
+Taking logarithms and $b_j=2^jb_0$ gives (eq:bootstrap-gap) on
 $n_j\le L\le2n_j$; the dyadic intervals cover every even $L\ge n_0$.
-\end{proof}
 
-\subsection{The two parameter choices}
 
-We will prove the seeds \eqref{eq:bootstrap-seeds} for
-\begin{equation}\label{eq:bootstrap-parameters}
-\begin{array}{c|c|c|c|c}
+## The two parameter choices
+
+We will prove the seeds (eq:bootstrap-seeds) for
+
+{c|c|c|c|c}
  n_0&b_0&u_0&C&r=Cu_0\\ \hline
  60&105/4&1/8&79/10&79/80\\
  2304&784&1/100&5&1/20
-\end{array}
-\end{equation}
+
+
 The scalar hypotheses are checked directly.  For the first row,
 $G(1/8)=913952/117649<79/10$ and
 $3/[C(1-3u_0)]=48/79<1$.  For the second, $1-(1-u)^3\le3u$ gives for
 $0<u\le1/100$
 \[
- G(u)\le\frac9{2(1-3u)^2}\le\frac{45000}{9409}<5,\qquad
- \frac3{C(1-3u_0)}=\frac{60}{97}<1 .
+ G(u)\le\frac9{2(1-3u)^2}\le(45000)/(9409)<5,\qquad
+ \frac3{C(1-3u_0)}=(60)/(97)<1 .
 \]
 So the two rows give the bounds $(4/105)\log(80/79)$ and $(\log20)/784$
-of \eqref{eq:bootstrap-gap}, once their seeds hold.  The second row will
-come from six applications of Lemma~\ref{lem:rounded-update} to bounds
+of (eq:bootstrap-gap), once their seeds hold.  The second row will
+come from six applications of Lemma~lem:rounded-update to bounds
 based at $(36,49/4)$.  Everything left is finite: establish the two seed
 inequalities without losing the margins these updates need.
 
-\section{Two finite initializations}\label{sec:initialization}
+# Two finite initializations
 
 The bootstrap needs a spatial purity at length $n$ and a physical
 purity at length $2n$, at the same inverse temperature.  We build two
@@ -693,35 +693,35 @@ such seed pairs.  The first starts at length $60$; the second reaches
 length $2304$ and gives the stronger eventual gap.  Each seed rests on
 a few short-chain partition functions and one periodic trial vector.
 
-\subsection{Thermal data and moment bounds}
+## Thermal data and moment bounds
 
 Write $J_n=I_n+2O_n$ for the $D_2$-invariant moment, $I_n$ for the
 moment also fixed by $C$, and $N_n$ for one nontrivial $D_2$ sector
-(Lemma~\ref{lem:sectors}).  Since each $O_n$ occurs twice and each
+(Lemma~lem:sectors).  Since each $O_n$ occurs twice and each
 $N_n$ three times,
-\begin{equation}\label{eq:sector-inversion}
-\begin{aligned}
+
+
  J_n&=\frac{Z_n+3Z_n(P)}4,& N_n&=\frac{Z_n-Z_n(P)}4,\\
- I_n&=\frac{Z_n+3Z_n(P)+8Z_n(C)}{12},&
- O_n&=\frac{Z_n+3Z_n(P)-4Z_n(C)}{12},
-\end{aligned}
-\end{equation}
+ I_n&=(Z_n+3Z_n(P)+8Z_n(C))/(12),&
+ O_n&=(Z_n+3Z_n(P)-4Z_n(C))/(12),
+
+
 all at one common inverse temperature.
 
-\begin{lemma}[Finite thermal inputs]\label{lem:thermal-inputs}
+[Finite thermal inputs]
 For $a=700741/500000$ the tables below give centers of the shifted
 $Z_n(b,g)$ in units $10^{-6}$, with absolute error below $10^{-5}$ at
 $b=21/2$ and below $30\cdot10^{-6}$ at $b=49/4$:
 \[
-\begin{array}{c|rrr}
+{c|rrr}
  &\multicolumn{3}{c}{b=21/2}\\
  n&g=1&g=P&g=C\\ \hline
  6&8945303&346734&939987\\
  8&3741281&567167&984108\\
  10&2327547&721090&1002613
-\end{array}
+
 \qquad
-\begin{array}{c|rr}
+{c|rr}
  &\multicolumn{2}{c}{b=49/4}\\
  n&g=1&g=P\\ \hline
  4&124885379&65757\\
@@ -733,81 +733,81 @@ $b=21/2$ and below $30\cdot10^{-6}$ at $b=49/4$:
  10&2654823&675419\\
  11&377629&1314544\\
  12&1900547&787405
-\end{array}
+
 \]
-\end{lemma}
 
-Appendices~\ref{sec:thermal120} and~\ref{sec:thermal72} prove these
+
+Appendices~sec:thermal120 and~sec:thermal72 prove these
 tables by rational enclosures of the physical matrix exponentials with
 explicit error bounds; they are rigorous, not numerical estimates.  The
-other finite input is Lemma~\ref{lem:trial-inputs}:
-\begin{equation}\label{eq:trial-thermal-consequence}
+other finite input is Lemma~lem:trial-inputs:
+
  E_0(72)<-72a,\qquad E_0(120)<-120a,
-\end{equation}
+
 so $Z_{72}(b)>1$ and $Z_{120}(b)>1$ for every $b>0$ (one Boltzmann
 factor already exceeds one).
 
 Two elementary lemmas convert the tables into spectral bounds.
 
-\begin{lemma}[Capped masses]\label{lem:cappedmass}
+[Capped masses]
 Let $(t_i)$ be finite or countable with $0\le t_i\le h$ and
 $\sum_it_i\le m$, where $h>0, m\ge0$.  For $r\ge1$ put
-\begin{equation}\label{eq:capped-function}
+
  \mathcal C(m,h,r)=qh^r+(m-qh)^r,\qquad q=\lfloor m/h\rfloor.
-\end{equation}
+
 Then $\sum_it_i^r\le\mathcal C(m,h,r)$; without the cap,
 $\sum_it_i^r\le m^r$.
-\end{lemma}
 
-\begin{proof}
+
+Proof. 
 For a finite family at fixed total mass, move mass from the smaller of
 two coordinates in $(0,h)$ to the larger until one reaches $0$ or $h$;
 convexity of $x\mapsto x^r$ shows the sum of $r$th powers does not
 decrease.  Repetition leaves at most one coordinate in $(0,h)$, giving
-\eqref{eq:capped-function} at the actual mass; the right side is
+(eq:capped-function) at the actual mass; the right side is
 continuous and nondecreasing in the mass, so bounded by its value at
 $m$.  Take increasing unions of finite subfamilies for the countable
 case.  The uncapped bound follows from $t_i^r\le t_i(\sum_jt_j)^{r-1}$.
-\end{proof}
 
-\begin{lemma}[Polynomial filter]\label{lem:polynomial-filter}
-Let $\epsilon\ge0$, $v>0$, and let $(\lambda_i)$ be a real eigenvalue
+
+[Polynomial filter]
+Let $ε\ge0$, $v>0$, and let $(\lambda_i)$ be a real eigenvalue
 list with moments $M_j=\sum_i\lambda_i^j$ converging absolutely, and
-$|M_j-c_j|\le\epsilon$ for the exponents occurring in a polynomial
+$|M_j-c_j|\leε$ for the exponents occurring in a polynomial
 $F(x)=\sum_jf_jx^j\ge0$ on $\R$.  If
 \[
- B=\sum_jf_jc_j+\epsilon\sum_j|f_j|
- \quad\text{and}\quad F(x)>B\ \text{for }|x|\ge v,
+ B=\sum_jf_jc_j+ε\sum_j|f_j|
+ \quadand\quad F(x)>B\ for |x|\ge v,
 \]
 then every $|\lambda_i|<v$.
-\end{lemma}
 
-\begin{proof}
+
+Proof. 
 Absolute convergence gives $\sum_iF(\lambda_i)\le B$; nonnegativity
 means a single $|\lambda_i|\ge v$ would contradict this.
-\end{proof}
 
-All moments converge by Proposition~\ref{prop:transfer}, and the
-coefficient sums in \eqref{eq:sector-inversion} are at most one in
+
+All moments converge by Proposition~prop:transfer, and the
+coefficient sums in (eq:sector-inversion) are at most one in
 absolute value, so the thermal error bound also bounds each sector
 moment error (odd moments included, with signs kept in the filter).
 
-\subsection{The initialization at length sixty}
+## The initialization at length sixty
+
 
-\begin{proposition}\label{prop:seed60}
 At inverse temperature $b=105/4$, $S(60,b)>7/8$ and $T(120,b)>7/8$.
-\end{proposition}
 
-\begin{proof}
+
+Proof. 
 Work at $b_0=21/2$.  From the $b_0=21/2$ table and
-\eqref{eq:sector-inversion} the tenth moments obey
+(eq:sector-inversion) the tenth moments obey
 \[
- m_I=\frac{1042655}{10^6},\quad m_O=\frac{40041}{10^6},\quad
- m_N=\frac{401625}{10^6},
+ m_I=(1042655)/(10^6),\quad m_O=(40041)/(10^6),\quad
+ m_N=(401625)/(10^6),
 \]
 with margins $19/(12\cdot10^6)$, $7/(12\cdot10^6)$,
 $3/(4\cdot10^6)$ over centers plus $10^{-5}$.  Apply
-Lemma~\ref{lem:polynomial-filter} to
+Lemma~lem:polynomial-filter to
 \[
  F_I(x)=x^6(-2+10x^2)^2,\qquad F_N(x)=x^6(-25+100x^2)^2 .
 \]
@@ -815,51 +815,51 @@ For a filter $x^6(c_0+c_1x^2)^2$ the summed upper bound is the centered
 combination of moments $6,8,10$ with coefficients $c_0^2,2c_0c_1,c_1^2$
 plus $10^{-5}(|c_0|+|c_1|)^2$.  Rational evaluation gives
 \[
- |\lambda|<U:=\frac{100245}{100000}\ (I\text{ sector}),\qquad
- |\lambda|<V:=\frac{88643}{100000}\ (N\text{ sector}),
+ |\lambda|<U:=(100245)/(100000)\ (I sector),\qquad
+ |\lambda|<V:=(88643)/(100000)\ (N sector),
 \]
 since the filter at the endpoint exceeds its bound by more than
 $0.0301$ ($I$) and $0.3463$ ($N$), and each filter increases with $|x|$
 beyond its endpoint ($c_1>0$, $c_0+c_1x^2>0$ there).
 
 The inequalities $U^{10}<m_I<2U^{10}$ and $V^{10}<m_N<2V^{10}$ allow the
-two-piece \eqref{eq:capped-function}.  For $k=30,120$ set
+two-piece (eq:capped-function).  For $k=30,120$ set
 \[
  A_k=U^k+(m_I-U^{10})^{k/10},\quad B_k=m_O^{k/10},\quad
  C_k=V^k+(m_N-V^{10})^{k/10},
 \]
 bounding $I_k,O_k,N_k$.  These are even moments, hence nonnegative, so
-\begin{equation}\label{eq:short-moment-upper}
+
  Z_k(b_0)\le A_k+2B_k+3C_k,\qquad
  Z_k(b_0,P),Z_k(b_0,C)\le A_k+2B_k .
-\end{equation}
+
 Put $m=A_{30}+2B_{30}+3C_{30}$, $p=A_{30}+2B_{30}$,
 $q=A_{120}+2B_{120}+3C_{120}$, and
 \[
- D=\frac{1450}{1000},\quad E=\frac{1202}{1000},\quad
- \tau=\frac{1225}{1000},\quad\tau_0=\frac{1264}{1000},\quad
- R_q=\frac{684}{10000}.
+ D=(1450)/(1000),\quad E=(1202)/(1000),\quad
+ \tau=(1225)/(1000),\quad\tau_0=(1264)/(1000),\quad
+ R_q=(684)/(10000).
 \]
 The scalar estimates are
-\begin{equation}\label{eq:seed60-scalars}
+
  m^5<D^2,\quad p^5<E^2,\quad q\ge1,\quad (q-1)^5<R_q^2,\quad
- \frac{D+11E}{12}\le\tau,\quad \frac{D+3E}{4}\le\tau_0,
-\end{equation}
+ (D+11E)/(12)\le\tau,\quad (D+3E)/(4)\le\tau_0,
+
 with positive margins exceeding $0.001068$, $0.000433$,
 $0.0000472$ in the first, second and fourth strict inequalities; all
 numbers are rational and stated above.
 
 Raise the inverse temperature to $b=(5/2)b_0$.  For positive Boltzmann
 factors $z_i$, $\sum_i z_i^{5/2}\le(\sum_iz_i)^{5/2}$, so
-\eqref{eq:short-moment-upper}--\eqref{eq:seed60-scalars} give
+(eq:short-moment-upper)--(eq:seed60-scalars) give
 \[
  Z_{30}(b)\le D,\qquad Z_{30}(b,P),Z_{30}(b,C)\le E ;
 \]
-by \eqref{eq:sector-inversion} the $I$ and $J$ portions of the thirtieth
+by (eq:sector-inversion) the $I$ and $J$ portions of the thirtieth
 spatial moment are at most $\tau$ and $\tau_0$.
 
 Let $w_i=|\lambda_i(X_b)|^{30}$, so $\sum_iw_i\le D$, while
-\eqref{eq:trial-thermal-consequence} gives $\sum_iw_i^4=Z_{120}(b)>1$.
+(eq:trial-thermal-consequence) gives $\sum_iw_i^4=Z_{120}(b)>1$.
 Since $D(0.88)^3<1$, some $w_0>0.88$ exists, and it is unique because
 $2(0.88)>D$.  It lies in $I$: an $O$ weight occurs at least twice and an
 $N$ weight at least three times (counting multiplicities, including
@@ -875,18 +875,18 @@ mass; their squared weights sum to at most $x^2+y^2/2+z^2/3$ with
 The divisors use identical repeated lists.  Since $D>\tau_0$ the last
 bound is nonnegative on the whole polygon, and the convex quadratic
 $x^2+y^2/2+(D-t-x-y)^2/3$ attains its maximum at a vertex:
-\begin{equation}\label{eq:residual-R}
+
  R(t)=\max_{(x,y)\in\mathcal V_t}
- \Bigl(x^2+\tfrac{y^2}{2}+\tfrac{(D-t-x-y)^2}{3}\Bigr),\quad
+ (x^2+(y^2)/(2)+((D-t-x-y)^2)/(3)),\quad
  \mathcal V_t=\{(0,0),(\tau-t,0),(\tau-t,\tau_0-\tau),(0,\tau_0-t)\}.
-\end{equation}
+
 Thus the remaining squared weights sum to at most $R(t)$, their fourth
 powers to at most $R(t)^2$.  Exact evaluation gives
 \[
-\begin{array}{c|ccc}
+{c|ccc}
  t&0.88&0.99&0.998\\ \hline
  R(t)&0.1359&0.0721&0.068404
-\end{array}
+
 \]
 and
 \[
@@ -897,8 +897,8 @@ If $w_0\le0.99$ the first would contradict $\sum_iw_i^4>1$, and the
 second then excludes $w_0\le0.998$.  Keeping the dominant contribution
 in the fourth moment,
 \[
- S(60,b)=\frac{\sum_iw_i^4}{(\sum_iw_i^2)^2}
- \ge\Bigl(1+\frac{R(0.998)}{0.998^2}\Bigr)^{-2}>0.8756>\frac78 .
+ S(60,b)=(\sum_iw_i^4)/((\sum_iw_i^2)^2)
+ \ge(1+(R(0.998))/(0.998^2))^{-2}>0.8756>\frac78 .
 \]
 
 For the physical purity at length $120$, at temperature $b_0$: the
@@ -911,31 +911,31 @@ so
 \]
 This last step concerns physical Boltzmann factors, separate from the
 spatial weights used for $S$.
-\end{proof}
 
-\subsection{The initialization giving the stronger gap}
 
-\begin{proposition}\label{prop:seed2304}
+## The initialization giving the stronger gap
+
+
 At inverse temperature $b=784$,
 \[
- 1-S(2304,b)\le\frac{84513}{10^7}<\frac1{100},\qquad
- 1-T(4608,b)\le\frac{27493}{5\cdot10^6}<\frac1{100}.
+ 1-S(2304,b)\le(84513)/(10^7)<\frac1{100},\qquad
+ 1-T(4608,b)\le(27493)/(5\cdot10^6)<\frac1{100}.
 \]
-\end{proposition}
 
-\begin{proof}
+
+Proof. 
 We isolate one large $J$ eigenvalue, bound the rest, get seeds at
 length $36$, then apply six rounded updates to reach $2304$.
 
 Start at $b_0=49/4$; the $b_0=49/4$ table gives centers for $J_n,N_n$
-via \eqref{eq:sector-inversion} with error at most $\epsilon=30\cdot10^{-6}$.
+via (eq:sector-inversion) with error at most $ε=30\cdot10^{-6}$.
 Use
 \[
  F_J(x)=x^4(7+17x-280x^2-185x^3+1000x^4)^2,\quad
  F_N(x)=x^4(12-394x^2+1000x^4)^2,
 \]
 of degree $12$, so the table supplies every needed moment.  The summed
-upper bounds of Lemma~\ref{lem:polynomial-filter} are
+upper bounds of Lemma~lem:polynomial-filter are
 \[
  B_J=318604.54848175,\qquad B_N=48169.880699 .
 \]
@@ -947,10 +947,10 @@ Set $v_J=100139/100000$, $v_N=872/1000$.  Direct comparison gives
 To cover the whole exterior rays, write $Q(x)=7+17x-280x^2-185x^3+1000x^4$;
 for $y\ge0$,
 \[
- \begin{aligned}
+ 
  Q(1+y)&=559+2902y+5165y^2+3815y^3+1000y^4,\\
  Q(-1-y)&=895+3978y+6275y^2+4185y^3+1000y^4.
- \end{aligned}
+ 
 \]
 both positive and increasing.  Likewise $12-394r^2+1000r^4$ is positive
 and increasing for $r\ge v_N$ (value at $v_N$ positive, derivative
@@ -959,39 +959,39 @@ $v_J$ and every $N$ eigenvalue below $v_N$.
 
 The twelfth-moment upper bounds are $m_J=1.0657205$, $m_N=0.2783155$.
 Put $\ell=999/1000$ and, for $k=36,72$,
-\begin{equation}\label{eq:seed72-tail}
+
  B(k)=3\mathcal C(m_N,v_N^{12},k/12),\quad
  R_A(k)=B(k)+(m_J-\ell^{12})^{k/12}
-\end{equation}
+
 (with $m_J>\ell^{12}$).  If all $J$ eigenvalues had modulus at most
-$\ell$, Lemma~\ref{lem:cappedmass} would give
+$\ell$, Lemma~lem:cappedmass would give
 $Z_{72}(b_0)\le\mathcal C(m_J,\ell^{12},6)+B(72)<1$, with strict margin
 above $0.0693$; the trial inequality contradicts this.  So some
 $\lambda_0$ in $J$ has $|\lambda_0|>\ell$; removing it leaves twelfth
 moment at most $m_J-\ell^{12}$ in $J$, and with the three $N$ sectors
 $R_A(k)$ bounds the remaining full $k$th moment.  Thus
-\begin{equation}\label{eq:seed72-pq}
-\begin{aligned}
- 1-S(36,b_0)&\le p_0:=1-\Bigl(1+\frac{R_A(36)}{\ell^{36}}\Bigr)^{-2},\\
- 1-T(72,b_0)&\le q_0:=1-\bigl(v_J^{72}+R_A(72)\bigr)^{-2}.
-\end{aligned}
-\end{equation}
+
+
+ 1-S(36,b_0)&\le p_0:=1-(1+\frac{R_A(36)}{\ell^{36}})^{-2},\\
+ 1-T(72,b_0)&\le q_0:=1-(v_J^{72}+R_A(72))^{-2}.
+
+
 The first retains $\lambda_0^{72}$; the second uses $Z_{72}(2b_0)>1$ and
 $Z_{72}(b_0)\le v_J^{72}+R_A(72)$.  Numerically $p_0<0.047916$,
 $q_0<0.181521$, but the updates use their exact rational definitions.
 
-Apply Lemma~\ref{lem:rounded-update} six times, rounding each new defect
+Apply Lemma~lem:rounded-update six times, rounding each new defect
 up to a multiple of $10^{-7}$ and using the rounded spatial defect in
 the physical update.  With $f(u)=u^2/[2(1-u)^2]$ and
 $\lceil x\rceil_7=10^{-7}\lceil10^7x\rceil$:
 \[
- p_{j+1}=\bigl\lceil f\bigl(1-(1-p_j)^2(1-q_j)\bigr)\bigr\rceil_7,
+ p_{j+1}=\bigl\lceil f(1-(1-p_j)^2(1-q_j))\bigr\rceil_7,
  \quad
- q_{j+1}=\bigl\lceil f\bigl(1-(1-q_j)^2(1-p_{j+1})\bigr)\bigr\rceil_7 .
+ q_{j+1}=\bigl\lceil f(1-(1-q_j)^2(1-p_{j+1}))\bigr\rceil_7 .
 \]
 Exact rational evaluation gives
 \[
-\begin{array}{c|cc}
+{c|cc}
  j&p_j&q_j\\ \hline
  1&151249/2500000&433453/2500000\\
  2&343303/5000000&1632381/10000000\\
@@ -999,25 +999,25 @@ Exact rational evaluation gives
  4&632939/10000000&1055161/10000000\\
  5&375793/10000000&445941/10000000\\
  6&84513/10000000&27493/5000000
-\end{array}
+
 \]
 Each update lies in $[0,1)$, where $f$ increases, so upward rounding
 preserves the bounds.  Length and inverse temperature have multiplied by
 $2^6$: $36\cdot64=2304$ and $(49/4)\cdot64=784$.  The last row proves
 the proposition.
-\end{proof}
 
-\subsection{A periodic interface for boundary estimates}
 
-\begin{corollary}[Periodic inputs for boundary estimates]
-\label{cor:boundary-inputs}
-Let $X_b$ be the transfer operator of Proposition~\ref{prop:transfer}
+## A periodic interface for boundary estimates
+
+[Periodic inputs for boundary estimates]
+
+Let $X_b$ be the transfer operator of Proposition~prop:transfer
 with $a=700741/500000$, and put
 \[
- \begin{gathered}
+ 
  b_0=49/4,\quad b_1=49/2,\quad \ell=999/1000,\\
  U=100139/100000,\quad V=872/1000,\quad m_J=1.0657205,\quad m_N=.2783155 .
- \end{gathered}
+ 
 \]
 At $b=b_0$ the full spatial list is the $D_2$-invariant list $J$ plus
 three identical lists $N$.  Every $J$ eigenvalue has modulus below $U$
@@ -1027,56 +1027,56 @@ $m_N$; some $J$ eigenvalue has modulus above $\ell$.  Moreover
 $1-S(72,b_1)\le151249/2500000$.  For $n=72,120$, $E_0(n)+na<0$, so a
 physical ground Boltzmann factor of $Z_n(b)$ exceeds one for every
 $b>0$.
-\end{corollary}
 
-\begin{proof}
-The decomposition is Lemma~\ref{lem:sectors} with $J=I+2O$; the filters,
+
+Proof. 
+The decomposition is Lemma~lem:sectors with $J=I+2O$; the filters,
 twelfth-moment bounds and dominant eigenvalue are proved at the start of
-Proposition~\ref{prop:seed2304}.  The first row of the rounded update
+Proposition~prop:seed2304.  The first row of the rounded update
 table gives the display at $(72,49/2)$; the variational assertion is
-Lemma~\ref{lem:trial-inputs}.
-\end{proof}
+Lemma~lem:trial-inputs.
+
 
-\section{Proof of the gap theorem}\label{sec:assembly}
+# Proof of the gap theorem
 
 The two initializations feed the same purity theorem.  The finite inputs
-they use are proved in Appendices~\ref{sec:thermal120}--\ref{sec:trials};
+they use are proved in Appendices~sec:thermal120--sec:trials;
 those proofs are part of the argument.
 
-\begin{proof}[Proof of Theorem~\ref{thm:main}]
-Proposition~\ref{prop:transfer} identifies each partition function with
+Proof. [Proof of Theorem~thm:main]
+Proposition~prop:transfer identifies each partition function with
 a moment of a self-adjoint spatial transfer operator, so $S$ and $T$ of
-Section~\ref{sec:bootstrap} are well defined.  The $H_L$ are self-adjoint
+Section~sec:bootstrap are well defined.  The $H_L$ are self-adjoint
 and non-scalar, so the bootstrap criterion applies.
 
-Proposition~\ref{prop:seed60} gives
+Proposition~prop:seed60 gives
 $S(60,105/4)>7/8$ and $T(120,105/4)>7/8$.  Apply
-Proposition~\ref{prop:bootstrap} with
+Proposition~prop:bootstrap with
 $(n_0,b_0,u_0,C)=(60,105/4,1/8,79/10)$; its parameter inequalities hold
-by Section~\ref{sec:bootstrap}, and $Cu_0=79/80$.  Hence the ground
+by Section~sec:bootstrap, and $Cu_0=79/80$.  Hence the ground
 state is unique and $\gamma_L>\frac4{105}\log(80/79)$ for every even
-$L\ge60$, proving \eqref{eq:gap60}.
+$L\ge60$, proving (eq:gap60).
 
-Proposition~\ref{prop:seed2304} gives both defects at most $1/100$ at
+Proposition~prop:seed2304 gives both defects at most $1/100$ at
 the pair with $(n_0,b_0)=(2304,784)$.  Apply the same theorem with
 $u_0=1/100$, $C=5$; since $Cu_0=1/20$,
 \[
- \gamma_L>\frac{\log20}{784}\qquad(L\ge2304\text{ even}),
+ \gamma_L>(\log20)/(784)\qquad(L\ge2304 even),
 \]
-proving \eqref{eq:gap2304}.  The limit inferior over even lengths gives
-$\Delta_1\ge\log(20)/784>0$.  Finally, Lemma~\ref{lem:representation}
+proving (eq:gap2304).  The limit inferior over even lengths gives
+$\Delta_1\ge\log(20)/784>0$.  Finally, Lemma~lem:representation
 carries every spectral conclusion to any simultaneously similar spin-one
 realization, via the tensor-power similarity.
-\end{proof}
 
-The bounds become uniform on \emph{all} even lengths as follows: the
+
+The bounds become uniform on all even lengths as follows: the
 second bound covers $L\ge2304$, and the finitely many even $L$ with
 $4\le L\le2302$ are finite-dimensional self-adjoint Hamiltonians, each
 with a positive gap above its full ground sector.  This yields
-$\inf_{L\ge4,\,L\text{ even}}\gamma_L>0$, though it gives neither a
+$\inf_{L\ge4,\,L even}\gamma_L>0$, though it gives neither a
 numerical value nor simplicity at those small lengths.
 
-\subsection{An infinite-volume consequence}
+## An infinite-volume consequence
 
 The finite-volume estimate also controls local excitations in a
 thermodynamic limit, using the limiting argument of
@@ -1087,75 +1087,75 @@ $\omega(I)=1$, $\omega(A^*A)\ge0$.  Put
 $[H,A]=\sum_{j\in\Z}[\mathbf S_j\cdot\mathbf S_{j+1},A]$, only finitely
 many terms nonzero.
 
-\begin{corollary}\label{cor:local-limit}
-For the self-adjoint Hamiltonians \eqref{eq:main-H}, the normalized
+
+For the self-adjoint Hamiltonians (eq:main-H), the normalized
 ground states of the even periodic rings have a subsequence, as
-$L\to\infty$, converging on every local operator to a state $\omega$;
+$L\to∞$, converging on every local operator to a state $\omega$;
 each such limit obeys
-\begin{equation}\label{eq:local-limit-gap}
- \omega(A^*[H,A])\ge\frac{\log20}{784}\bigl(\omega(A^*A)-|\omega(A)|^2\bigr)
-\end{equation}
+
+ \omega(A^*[H,A])\ge(\log20)/(784)(\omega(A^*A)-|\omega(A)|^2)
+
 for every local operator $A$.
-\end{corollary}
 
-\begin{proof}
-Place the even ring of length $L$ on $\{-L/2,\dots,L/2-1\}$ with its
+
+Proof. 
+Place the even ring of length $L$ on $\{-L/2,...,L/2-1\}$ with its
 closing bond at the endpoints.  Compactness of the density matrices on
 each finite interval and a diagonal subsequence give convergence on all
 local operators; the compatible limits form a positive normalized
-functional $\omega$.  For $L\ge2304$, Theorem~\ref{thm:main} gives a
+functional $\omega$.  For $L\ge2304$, Theorem~thm:main gives a
 unique ground state $\psi_L$ and gap above $\delta=\log(20)/784$.
-Writing $\omega_L(A)=\langle\psi_L,A\psi_L\rangle$, the spectral
+Writing $\omega_L(A)=<\psi_L,A\psi_L>$, the spectral
 inequality on the orthogonal complement of $\psi_L$ gives
 \[
- \omega_L(A^*[H_L,A])\ge\delta\bigl(\omega_L(A^*A)-|\omega_L(A)|^2\bigr).
+ \omega_L(A^*[H_L,A])\ge\delta(\omega_L(A^*A)-|\omega_L(A)|^2).
 \]
 For fixed local $A$ and large $L$, the closing bond commutes with $A$ and
 $[H_L,A]=[H,A]$; passing to the local limit proves the claim.
-\end{proof}
+
 
 In particular $\omega$ is a ground state (no local perturbation lowers
-its energy).  For $\omega(A)=0$, \eqref{eq:local-limit-gap} is the
+its energy).  For $\omega(A)=0$, (eq:local-limit-gap) is the
 locally unique gapped property of
 \cite[arXiv v4, Definition~11]{Tasaki2025}, with gap at least
 $\log(20)/784$.  The argument does not identify limits of different
 subsequences, nor uniqueness among all infinite-volume ground states.
 
 \appendix
-\section{Thermal calculation at inverse temperature $21/2$}\label{sec:thermal120}
+# Thermal calculation at inverse temperature $21/2$
 
-We prove the $b=21/2$ table of Lemma~\ref{lem:thermal-inputs}.  The
+We prove the $b=21/2$ table of Lemma~lem:thermal-inputs.  The
 calculation uses the physical Hamiltonians at $n=6,8,10$ with twists
 $1,P,C$; all arithmetic is integral or rational, complex numbers being
 written in $\Z[\omega]$ with $\omega=e^{2\pi i/3}$.
 
-\subsection{Finite matrices and their columns}
+## Finite matrices and their columns
 
 Fix $b=21/2$ and one length, write $H=H_n(g)$.  The three twists have
 angles $\theta=0,\pi,2\pi/3$ about the weight-basis axis.  Set
-\begin{equation}\label{eq:thermal120-matrices}
- W=I-\frac{H_n(g)+(3n/2)I}{16},\qquad B=16W .
-\end{equation}
-Lemma~\ref{lem:energy} gives $\norm W\le1$, $\norm B\le16$.  In a fixed
+
+ W=I-(H_n(g)+(3n/2)I)/(16),\qquad B=16W .
+
+Lemma~lem:energy gives $\norm W\le1$, $\norm B\le16$.  In a fixed
 total-weight sector the vectors are words
 $x\in\{-1,0,1\}^n$ of fixed $\sum_jx_j$, the diagonal of $B$ is
 \[
- B_{x,x}=16-\frac{3n}{2}-\sum_{j=0}^{n-1}x_{j-1}x_j ,
+ B_{x,x}=16-(3n)/(2)-\sum_{j=0}^{n-1}x_{j-1}x_j ,
 \]
 and for each $j$ the move $y_j=x_j-\delta$, $y_k=x_k+\delta$
 ($k=j+1\bmod n$, $\delta=\pm1$, letters in $\{-1,0,1\}$) has entry $-1$,
 except at the seam $j=n-1,k=0$ where it is $-e^{i\theta\delta}$ (the
-phase \eqref{eq:seam-phase}).  On a coordinate $u+v\omega$ the cyclic
+phase (eq:seam-phase)).  On a coordinate $u+v\omega$ the cyclic
 twist acts by
-\begin{equation}\label{eq:thermal120-phases}
+
  -\omega(u+v\omega)=v+(v-u)\omega,\qquad
  -\omega^{-1}(u+v\omega)=(u-v)+u\omega,
-\end{equation}
+
 so every matrix-vector product is integer arithmetic in two coordinates.
 
-Only some columns are needed.  Let $s(x)=(x_{n-1},x_0,\dots,x_{n-2})$.
+Only some columns are needed.  Let $s(x)=(x_{n-1},x_0,...,x_{n-2})$.
 The seam formula gives $H_{s(x),s(y)}=e^{i\theta(y_{n-1}-x_{n-1})}H_{x,y}$,
-so $|x\rangle\mapsto e^{-i\theta x_{n-1}}|s(x)\rangle$ commutes with $H$.
+so $|x>\mapsto e^{-i\theta x_{n-1}}|s(x)>$ commutes with $H$.
 Reversal of the word and global negation of letters both send $H$ to its
 complex conjugate, and composing either permutation with conjugation
 gives an antiunitary symmetry.  Each symmetry preserves the norm of the
@@ -1168,7 +1168,7 @@ the full Frobenius norm of the exact exponential.  No equivariance of the
 rounded columns is needed: each computed representative is compared with
 its own exact column at its own multiplicity.
 
-\subsection{A rational polynomial and its error}
+## A rational polynomial and its error
 
 Write
 \[
@@ -1176,10 +1176,10 @@ Write
 \]
 so $Z_n(b,g)=e^{x_n}\norm{E}_F^2$ (Frobenius norm).  For $0\le j\le256$
 let
-\begin{equation}\label{eq:thermal120-probabilities}
+
  p_j=\frac{84^j/j!}{\sum_{l=0}^{256}84^l/l!},\qquad
  P(W)=\sum_{j=0}^{256}p_jW^j .
-\end{equation}
+
 These are mean-$84$ Poisson probabilities conditioned to $\le256$; for
 a mean-$84$ Poisson variable $V$,
 \[
@@ -1189,71 +1189,71 @@ a mean-$84$ Poisson variable $V$,
 and since $\norm{W^j}\le1$ conditioning changes the operator average by
 at most twice this probability (Fox--Glynn coefficient argument
 \cite[Proposition~1]{FoxGlynn1988}):
-\begin{equation}\label{eq:thermal120-poisson-error}
+
  \norm{P(W)-E}<2^{-116}.
-\end{equation}
+
 
 Put $Q=2^{56}$, $q_j=\lfloor Qp_j\rfloor$.  From $z=0$, for
-$j=256,\dots,0$:
-\begin{equation}\label{eq:thermal120-horner}
- z\leftarrow\operatorname{fl}(Bz/16)+q_je_r ,
-\end{equation}
-with $\operatorname{fl}$ the floor on each real coordinate (on $u,v$
+$j=256,...,0$:
+
+ z←fl(Bz/16)+q_je_r ,
+
+with $fl$ the floor on each real coordinate (on $u,v$
 separately for $u+v\omega$).  The ideal suffix at step $j$ is
 $Q\sum_{l=j}^{256}p_lW^{l-j}e_r$ of norm at most $Q$, and one
-coordinate floor adds less than $2\sqrt{d_0}$ in a sector of dimension
+coordinate floor adds less than $2√(d_0)$ in a sector of dimension
 $d_0$ while the coefficient floor adds at most one; contraction of $W$
 bounds the error at every stage by
-\begin{equation}\label{eq:thermal120-column-error}
- 257(2\sqrt{3^n}+1)\le125159.
-\end{equation}
+
+ 257(2√(3^n)+1)\le125159.
+
 The zero coefficients above $q_{172}$ may be skipped without changing
 this count (all $257$ steps are still charged).
 
 The repeated computed-column list, divided by $Q$ and multiplied by
-$e^{x_n/2}$, differs from $\sqrt{Z_n(b,g)}$ by at most
-\begin{equation}\label{eq:thermal120-scaled-error}
- e^{x_n/2}\sqrt{3^n}\Bigl(\frac{257(2\sqrt{3^n}+1)}Q+2^{-116}\Bigr)
+$e^{x_n/2}$, differs from $√(Z_n(b,g))$ by at most
+
+ e^{x_n/2}√(3^n)(\frac{257(2√(3^n)+1)}Q+2^{-116})
  <4\cdot10^{-7},
-\end{equation}
-because $\sqrt{3^n}\le243$, $x_n/2<6$, $e^{x_n/2}<3^6$, and
+
+because $√(3^n)\le243$, $x_n/2<6$, $e^{x_n/2}<3^6$, and
 $3^6\cdot243(125159/2^{56}+2^{-116})<4\cdot10^{-7}$.
 
-\subsection{Exact evaluation by packed integers}
+## Exact evaluation by packed integers
 
 For efficiency the recurrence runs on batches of at most $192$ columns,
-storing a digit list $y_0,\dots,y_{w-1}$ as
-$\operatorname{pack}(y)=\sum_{t=0}^{w-1}y_t2^{64t}$ (arbitrary precision).
+storing a digit list $y_0,...,y_{w-1}$ as
+$pack(y)=\sum_{t=0}^{w-1}y_t2^{64t}$ (arbitrary precision).
 Integer linear arithmetic preserves this identity before the floor even
 with carries.  For either coefficient, $|u|,|v|\le2|u+v\omega|$, so by
-\eqref{eq:thermal120-column-error} every coordinate of $Bz$ is at most
-\begin{equation}\label{eq:thermal120-lane-bound}
+(eq:thermal120-column-error) every coordinate of $Bz$ is at most
+
  32(Q+125159)=2305843009217699040<2^{63}.
-\end{equation}
+
 Let $s_w=\sum_{t=0}^{w-1}2^{64t}$ and
-$\mathrm{bias}=2^{63}s_w$, $\mathrm{mask}=(2^{60}-1)s_w$,
-$\mathrm{bias16}=2^{59}s_w$.  For $Y=\operatorname{pack}(y)$ obeying
-\eqref{eq:thermal120-lane-bound}, the operation
+$bias=2^{63}s_w$, $mask=(2^{60}-1)s_w$,
+$bias16=2^{59}s_w$.  For $Y=pack(y)$ obeying
+(eq:thermal120-lane-bound), the operation
 \[
  \texttt{(((Y+bias)>{}>4)\&mask)-bias16}
 \]
-equals $\operatorname{pack}((\lfloor y_t/16\rfloor)_t)$.  Adding the
+equals $pack((\lfloor y_t/16\rfloor)_t)$.  Adding the
 bias makes every base-$2^{64}$ digit lie in $[0,2^{64})$; the global
 shift moves four low bits of each higher lane into the four high bits of
 the previous lane; the mask deletes exactly those crossing bits, keeping
 $\lfloor(y_t+2^{63})/16\rfloor$ in lane $t$; subtracting $2^{59}$ gives
 $\lfloor y_t/16\rfloor$, also for negative $y_t$.  Hence the packed
-recurrence equals \eqref{eq:thermal120-horner}.  Final coordinates obey
+recurrence equals (eq:thermal120-horner).  Final coordinates obey
 $2(Q+125159)<2^{63}$, so biasing and unpacking recovers every integer
 exactly; for $u+v\omega$ the squared modulus is $u^2-uv+v^2$, and summing
 these integers with representative multiplicities gives the integer
 $t_{n,g}$.
 
-\subsection{Exact totals and trace enclosures}
+## Exact totals and trace enclosures
 
 The integer recurrence gives:
-\begin{center}
-\begin{tabular}{ccl}
+
+{ccl}
 \toprule
 $n$&$g$&$t_{n,g}$\\
 \midrule
@@ -1267,102 +1267,102 @@ $n$&$g$&$t_{n,g}$\\
 10&$P$&120458568770462253326886628639\\
 10&$C$&167487042402286114495695779656\\
 \bottomrule
-\end{tabular}
-\end{center}
+
+
 Enclose the scalar factor by
 \[
- L_n=\sum_{j=0}^{100}\frac{x_n^j}{j!},\qquad
+ L_n=\sum_{j=0}^{100}(x_n^j)/(j!),\qquad
  U_n=L_n+2\frac{x_n^{101}}{101!}.
 \]
 Since $0<x_n<12$ and later terms have ratio at most $x_n/102<1/2$,
 $L_n<e^{x_n}<U_n$.  For each center $c_{n,g}$ of the $b=21/2$ table,
 exact rational comparison gives
-\begin{equation}\label{eq:thermal120-rational-enclosure}
+
  c_{n,g}-2\cdot10^{-6}
  <\frac{L_nt_{n,g}}{Q^2}
  <\frac{U_nt_{n,g}}{Q^2}
  <c_{n,g}+2\cdot10^{-6}.
-\end{equation}
+
 These put every scaled norm below $4$, so by
-\eqref{eq:thermal120-scaled-error} replacing its square by the true trace
+(eq:thermal120-scaled-error) replacing its square by the true trace
 costs less than $(8+4\cdot10^{-7})4\cdot10^{-7}$.  Together with
-\eqref{eq:thermal120-rational-enclosure},
+(eq:thermal120-rational-enclosure),
 \[
  |Z_n(21/2,g)-c_{n,g}|
  <2\cdot10^{-6}+(8+4\cdot10^{-7})4\cdot10^{-7}<10^{-5}.
 \]
 This proves the $b=21/2$ table.
 
-\section{Thermal calculation at inverse temperature $49/4$}\label{sec:thermal72}
+# Thermal calculation at inverse temperature $49/4$
 
 We prove the $b=49/4$ table, using integer approximations to columns of a
 physical matrix exponential.  Throughout
 \[
- b=\frac{49}{4},\qquad J=280,\qquad Q=2^{55},\qquad 4\le n\le12,
+ b=(49)/(4),\qquad J=280,\qquad Q=2^{55},\qquad 4\le n\le12,
 \]
 with twists the identity and rotation by $\pi$ about $z$ (the latter has
 the same partition function as $P$ by a global rotation).
 
-\subsection{The physical matrix and its rational approximation}
+## The physical matrix and its rational approximation
 
-In the weight basis a word $w=(w_0,\dots,w_{n-1})$, $w_i\in\{-1,0,1\}$,
+In the weight basis a word $w=(w_0,...,w_{n-1})$, $w_i\in\{-1,0,1\}$,
 has conserved total weight.  On each weight block set
-\begin{equation}\label{eq:thermal72-matrix}
- R=I-\frac{\frac32nI+H}{16},\qquad D=32R ,
-\end{equation}
+
+ R=I-(\frac32nI+H)/(16),\qquad D=32R ,
+
 an integer matrix with diagonal
 $D_{w,w}=32-3n-2\sum_{i=0}^{n-1}w_{i-1}w_i$, an entry $-2$ for an allowed
 opposite unit step at letters $i-1,i$, and $+2$ on the twisted seam
-$i=0$ (indices mod $n$).  Lemma~\ref{lem:energy} gives
+$i=0$ (indices mod $n$).  Lemma~lem:energy gives
 \[
  0\le\tfrac32nI+H\le\tfrac52nI,\qquad
- \spec(R)\subseteq[1-5n/32,1]\subseteq[-\tfrac78,1],
+ \spec(R)⊆[1-5n/32,1]⊆[-\tfrac78,1],
 \]
 so $R$ is a self-adjoint contraction and
 \[
- F=\exp\!\bigl[-\tfrac b2(\tfrac32nI+H)\bigr]=\exp[98(R-I)] .
+ F=\exp\![-\tfrac b2(\tfrac32nI+H)]=\exp[98(R-I)] .
 \]
 On the full physical space (direct sum over weight blocks),
-\begin{equation}\label{eq:thermal72-trace}
- Z_n(b,g)=e^{x_n}\norm{F}_F^2,\qquad x_n=bn\bigl(\tfrac32-a\bigr).
-\end{equation}
+
+ Z_n(b,g)=e^{x_n}\norm{F}_F^2,\qquad x_n=bn(\tfrac32-a).
+
 Define the conditioned Poisson probabilities
-\begin{equation}\label{eq:thermal72-coefficients}
+
  p_j=\frac{v_j}{\sum_{\ell=0}^Jv_\ell},\quad
- v_j=98^j\frac{J!}{j!},\quad 0\le j\le J .
-\end{equation}
+ v_j=98^j(J!)/(j!),\quad 0\le j\le J .
+
 Since $\norm R\le1$, discarding the Poisson tail and renormalizing
 changes the exponential by at most twice the tail probability
 (Fox--Glynn):
 \[
  \norm{F-\sum_{j=0}^Jp_jR^j}
- \le2e^{-98}\sum_{j=281}^\infty\frac{98^j}{j!}
+ \le2e^{-98}\sum_{j=281}^∞(98^j)/(j!)
  \le2^{-280}e^{98}<2^{-84}<Q^{-1},
 \]
 using $2^j\ge2^{281}$ in the tail and $e^{-98}\sum_{j\ge0}196^j/j!=e^{98}$,
 then $e<4$.
 
-\subsection{Integer columns and their error}
+## Integer columns and their error
 
-For a unit basis column $e_r$, start at $X=0$ and for $j=J,\dots,0$ do
-\begin{equation}\label{eq:thermal72-horner}
- X\leftarrow\Bigl\lfloor\frac{DX}{32}\Bigr\rfloor+c_je_r,\qquad
+For a unit basis column $e_r$, start at $X=0$ and for $j=J,...,0$ do
+
+ X←\Bigl\lfloor(DX)/(32)\Bigr\rfloor+c_je_r,\qquad
  c_j=\lfloor Qp_j\rfloor,
-\end{equation}
+
 with coordinatewise floor; all quantities are integers, and since
 $c_j=0$ for $j>191$ the initial zero steps may be omitted.  Compare with
 the ideal suffix $Y_j=Q\sum_{\ell=j}^Jp_\ell R^{\ell-j}e_r$,
 $\norm{Y_j}_2\le Q$.  In a block of dimension $d_0$ a vector floor adds
-less than $\sqrt{d_0}$ and a coefficient floor less than one, so
-contraction bounds the accumulated error by $281(\sqrt{d_0}+1)$.  With
-\begin{equation}\label{eq:thermal72-errors}
- d_n=\lfloor\sqrt{3^n}\rfloor+1,\quad
+less than $√(d_0)$ and a coefficient floor less than one, so
+contraction bounds the accumulated error by $281(√(d_0)+1)$.  With
+
+ d_n=\lfloor√(3^n)\rfloor+1,\quad
  E_n=281(d_n+1)+1,\quad \mathcal E_n=d_nE_n,
-\end{equation}
+
 every computed column obeys
-\begin{equation}\label{eq:thermal72-column-error}
+
  \norm{X-QFe_r}_2\le E_n .
-\end{equation}
+
 The bound charges all $281$ ideal steps (including the omitted ones).
 
 The recursion is exactly signed-$64$-bit arithmetic: every coordinate is
@@ -1375,7 +1375,7 @@ contraction establishes the next coordinate bound; the induction does not
 assume the overflow-freeness it proves.  Final squares and sums use
 arbitrary-precision integers.
 
-\subsection{Representative columns}
+## Representative columns
 
 One column per orbit suffices.  For positive total weight use the orbit
 under cyclic shifts and reversal and give the representative twice the
@@ -1390,38 +1390,38 @@ negation preserves every entry.  For the twisted chain a bare shift moves
 the seam; left rotation by $q$ moves it to $(k-1,k)$, $k=-q\bmod n$, and
 the diagonal unitary
 \[
- G_k|w\rangle=(-1)^{\sum_{j=0}^{k-1}w_j}|w\rangle,\quad G_0=I,
+ G_k|w>=(-1)^{\sum_{j=0}^{k-1}w_j}|w>,\quad G_0=I,
 \]
 flips the hopping signs exactly at the two boundary bonds of that arc,
 restoring the seam.  The resulting signed shift commutes with $H$, so
 exact exponential columns at rotated words have equal norms; the
 untwisted chain needs no correction.
 
-Let $X_r$ be the output of \eqref{eq:thermal72-horner} at representative
+Let $X_r$ be the output of (eq:thermal72-horner) at representative
 $r$ and
-\begin{equation}\label{eq:thermal72-total}
+
  W_{n,g}=\sum_r\nu_r\sum_wX_r(w)^2 .
-\end{equation}
+
 Rounding need not preserve the signed symmetries, so form abstract direct
 sums repeating each exact (resp.\ computed) representative column $\nu_r$
 times: the first has squared norm $Q^2\norm{F}_F^2$, the second $W_{n,g}$.
-By \eqref{eq:thermal72-column-error},
-\begin{equation}\label{eq:thermal72-frobenius}
- \bigl|\sqrt{W_{n,g}}-Q\norm{F}_F\bigr|\le\sqrt{3^n}E_n<\mathcal E_n,
-\end{equation}
+By (eq:thermal72-column-error),
+
+ |\sqrt{W_{n,g}}-Q\norm{F}_F|\le√(3^n)E_n<\mathcal E_n,
+
 which proves the full trace estimate without equivariance of the rounded
 columns.
 
-\subsection{Exact totals and rational enclosures}
+## Exact totals and rational enclosures
 
-Equations \eqref{eq:thermal72-coefficients},
-\eqref{eq:thermal72-horner}, \eqref{eq:thermal72-total} give (second
+Equations (eq:thermal72-coefficients),
+(eq:thermal72-horner), (eq:thermal72-total) give (second
 column: no twist; third: $\pi$ twist):
-\begin{center}
+
 \begingroup
 \footnotesize
-\setlength{\tabcolsep}{4pt}
-\begin{tabular}{r|rr}
+
+{r|rr}
 \(n\)&\(W_{n,I}\)&\(W_{n,P}\)\\ \hline
 4&1298092848946206529211955779616040&683496640248050713756440676071\\
 5&9095379218684502088743241789&9205948219074287936685289758037\\
@@ -1432,25 +1432,25 @@ column: no twist; third: $\pi$ twist):
 10&19772960374215472827775892486&5030484777222468978572235564\\
 11&841347687722481981930750335&2928767918985354021900689432\\
 12&1266666171463993322695232916&524785463625387865619045258
-\end{tabular}
+
 \endgroup
-\end{center}
+
 
 Turn these integers into the $b=49/4$ table.  Let
 \[
  r_{n,g}=\lfloor\sqrt{W_{n,g}}\rfloor,\quad
- s_n=\sum_{j=0}^{100}\frac{x_n^j}{j!},\quad
+ s_n=\sum_{j=0}^{100}(x_n^j)/(j!),\quad
  t_n=\frac{x_n^{100}}{100!}.
 \]
 Since $0\le x_n<15$, later omitted terms have ratio at most $15/101$ and
 the tail is at most $15t_n/86<t_n$, so $s_n\le e^{x_n}\le s_n+t_n$.
-Equations \eqref{eq:thermal72-trace} and \eqref{eq:thermal72-frobenius}
+Equations (eq:thermal72-trace) and (eq:thermal72-frobenius)
 give
-\begin{equation}\label{eq:thermal72-enclosure}
+
  L_{n,g}=\frac{s_n\max(0,r_{n,g}-\mathcal E_n)^2}{Q^2},\quad
  U_{n,g}=\frac{(s_n+t_n)(r_{n,g}+1+\mathcal E_n)^2}{Q^2},\quad
  L_{n,g}\le Z_n(b,g)\le U_{n,g},
-\end{equation}
+
 all rational/integer with the integer square root fixed by
 $r^2\le W<(r+1)^2$.  For the integer centers $C_{n,g}$ of the $b=49/4$
 table, direct evaluation yields
@@ -1462,7 +1462,7 @@ each strict inequality with margin above $13/10^6$.  This gives a
 reproducible finite verification of all eighteen enclosures and proves the
 $b=49/4$ table.
 
-\section{Two variational inputs}\label{sec:trials}
+# Two variational inputs
 
 The initializations need a lower bound on the untwisted partition function
 at lengths $72$ and $120$.  One fixed triple of integer matrices defines
@@ -1470,43 +1470,43 @@ periodic matrix-product vectors at both lengths with energy per bond below
 $-a=-700741/500000$.  A block decomposition reduces the computation to
 powers of integer matrices of order at most $162$.
 
-\subsection{Norm and energy contractions}
+## Norm and energy contractions
 
 For $N\ge4$ and real $D\times D$ matrices $A_s$ ($s=-1,0,1$) define, in
 the orthonormal spin-one weight basis,
-\begin{equation}\label{eq:trial-vector}
- \psi_N(s_0,\dots,s_{N-1})=\Tr(A_{s_0}\cdots A_{s_{N-1}}),
-\end{equation}
+
+ \psi_N(s_0,...,s_{N-1})=\Tr(A_{s_0}... A_{s_{N-1}}),
+
 the periodic matrix-product representation of
 \cite[Section~2.1, Equations~(2)--(3)]{PerezGarcia2007}.  Put
-\begin{align}
- B_{st}&=A_sA_t,\quad T=\sum_{s=-1}^1A_s\otimes A_s,
- \label{eq:trial-transfer}\\
- O&=\sum_{s,t=-1}^1st\,B_{st}\otimes B_{st}
+
+ B_{st}&=A_sA_t,\quad T=\sum_{s=-1}^1A_s ⊗  A_s,
+ \\
+ O&=\sum_{s,t=-1}^1st\,B_{st} ⊗  B_{st}
  +\sum_{\substack{s=-1,0\\t=0,1}}
- \bigl(B_{st}\otimes B_{s+1,t-1}
- +B_{s+1,t-1}\otimes B_{st}\bigr).
- \label{eq:trial-insertion}
-\end{align}
+ (B_{st} ⊗  B_{s+1,t-1}
+ +B_{s+1,t-1} ⊗  B_{st}).
+ 
+
 All traces are ordinary, unnormalized.
 
-\begin{lemma}\label{lem:trial-contraction}
+
 Let $N\ge4$, $D\ge1$ and $A_{-1},A_0,A_1\in M_D(\R)$; define
-$\psi_N,T,O$ by \eqref{eq:trial-vector}--\eqref{eq:trial-insertion} and,
+$\psi_N,T,O$ by (eq:trial-vector)--(eq:trial-insertion) and,
 for the periodic spin-one Hamiltonian $H_N$, set
 $V_N=\Tr(T^N), U_N=\Tr(T^{N-2}O)$.  Then
 $\norm{\psi_N}^2=V_N$ and
-$\langle\psi_N,H_N\psi_N\rangle=NU_N$.  In particular, if $V_N>0$ and
+$<\psi_N,H_N\psi_N>=NU_N$.  In particular, if $V_N>0$ and
 $U_N<-aV_N$, then $E_0(N)<-Na$ and $Z_N(b)>1$ for every $b>0$.
-\end{lemma}
 
-\begin{proof}
-Expanding $T^N$ and using $\Tr(X\otimes Y)=\Tr(X)\Tr(Y)$, the sum of
-squares of the (real) amplitudes \eqref{eq:trial-vector} is $V_N$; no
+
+Proof. 
+Expanding $T^N$ and using $\Tr(X ⊗  Y)=\Tr(X)\Tr(Y)$, the sum of
+squares of the (real) amplitudes (eq:trial-vector) is $V_N$; no
 self-adjointness or positivity of $T$ is assumed.  In the weight basis a
 bond has diagonal $st$ on $(s,t)$ and off-diagonal $1$ from $(s,t)$ to
 $(s+1,t-1)$ for $s=-1,0$, $t=0,1$ (from
-$h=S^z\otimes S^z+(S^+\otimes S^-+S^-\otimes S^+)/2$ and ladder entries
+$h=S^z ⊗  S^z+(S^+ ⊗  S^-+S^- ⊗  S^+)/2$ and ladder entries
 $\sqrt2$).  Inserting this bond into the two amplitude layers gives
 exactly $O$; summing the other indices gives $U_N$ for one bond, and
 cyclicity of the amplitude trace makes $\psi_N$ translation invariant, so
@@ -1514,31 +1514,31 @@ every bond including the seam contributes equally.  For $V_N>0$ the
 variational principle gives $E_0(N)\le NU_N/V_N<-Na$, so the shifted
 ground energy is negative and its term in $\Tr e^{-b(H_N+NaI)}$ exceeds
 one for every $b>0$.
-\end{proof}
 
-\subsection{One integer matrix triple}
 
-Set $D=26$, index eight types $\alpha=1,\dots,8$ by
-$(\ell_1,\dots,\ell_8)=(1,1,1,1,3,3,3,5)$, and order virtual labels
+## One integer matrix triple
+
+Set $D=26$, index eight types $\alpha=1,...,8$ by
+$(\ell_1,...,\ell_8)=(1,1,1,1,3,3,3,5)$, and order virtual labels
 $(\alpha,d)$ first by $\alpha$ then by
-$d=-\ell_\alpha,-\ell_\alpha+2,\dots,\ell_\alpha$.  The matrices $A_s$
-use the diagonal parameters $D_\alpha$ of Table~\ref{tab:trial-diagonal}
-and the parameters $P_{\alpha\beta}$ of Table~\ref{tab:trial-pairs},
+$d=-\ell_\alpha,-\ell_\alpha+2,...,\ell_\alpha$.  The matrices $A_s$
+use the diagonal parameters $D_\alpha$ of Table~tab:trial-diagonal
+and the parameters $P_{\alpha\beta}$ of Table~tab:trial-pairs,
 defined only when $\ell_\beta=\ell_\alpha+2$.
 
-\begin{table}[ht]
+[ht]
 \centering
-\begin{tabular}{c|rrrrrrrr}
+{c|rrrrrrrr}
 $\alpha$&1&2&3&4&5&6&7&8\\ \hline
 $D_\alpha$&$-289$&$-84$&$-9$&33&$-22$&27&71&$-11$
-\end{tabular}
-\caption{Diagonal parameters, common to both lengths.}
-\label{tab:trial-diagonal}
-\end{table}
 
-\begin{table}[ht]
+Caption: Diagonal parameters, common to both lengths.
+
+
+
+[ht]
 \centering
-\begin{tabular}{c|r@{\qquad}c|r@{\qquad}c|r}
+{c|r@{\qquad}c|r@{\qquad}c|r}
 $(\alpha,\beta)$&$P_{\alpha\beta}$&
 $(\alpha,\beta)$&$P_{\alpha\beta}$&
 $(\alpha,\beta)$&$P_{\alpha\beta}$\\ \hline
@@ -1547,85 +1547,85 @@ $(1,6)$&$-35$&$(3,5)$&$-6$&$(4,7)$&$-32$\\
 $(1,7)$&$-28$&$(3,6)$&$-25$&$(5,8)$&1\\
 $(2,5)$&$-23$&$(3,7)$&$-20$&$(6,8)$&2\\
 $(2,6)$&16&$(4,5)$&$-34$&$(7,8)$&$-16$
-\end{tabular}
-\caption{Parameters joining virtual types whose $\ell$ differ by $2$.}
-\label{tab:trial-pairs}
-\end{table}
+
+Caption: Parameters joining virtual types whose $\ell$ differ by $2$.
+
+
 
 Entry rules.  Row $(\alpha,d)$, column $(\beta,e)$, with $\ell=\ell_\alpha$,
 $k=\ell_\beta$, $s\in\{-1,0,1\}$.  The entry is zero unless
-\begin{equation}\label{eq:trial-support}
- e=d+2s,\qquad |k-\ell|\le2,\qquad (k=\ell\Longrightarrow\alpha=\beta).
-\end{equation}
+
+ e=d+2s,\qquad |k-\ell|\le2,\qquad (k=\ell⇒\alpha=\beta).
+
 For an allowed entry set
 \[
- p=\begin{cases}D_\alpha,& k=\ell,\\ P_{\alpha\beta},& k=\ell+2,\\
- -P_{\beta\alpha},& k=\ell-2,\end{cases}
+ p=D_\alpha,& k=\ell,\\ P_{\alpha\beta},& k=\ell+2,\\
+ -P_{\beta\alpha},& k=\ell-2,
 \]
 $r=(d+\ell)/2$, and the entry $pf$ where
-\begin{equation}\label{eq:trial-entry}
-\begin{array}{c|ccc}
+
+{c|ccc}
  &s=-1&s=0&s=1\\ \hline
 k=\ell+2&2(\ell+1-r)(\ell+2-r)&2(r+1)(\ell-r+1)&(r+1)(r+2)\\
 k=\ell&2(\ell-r+1)&d&-(r+1)\\
 k=\ell-2&2&-2&1
-\end{array}
-\end{equation}
+
+
 lists the values of $f$.  These rules do not depend on $N$.
 
-\subsection{Finite contractions and variational bounds}
+## Finite contractions and variational bounds
 
 Evaluate the contractions at $N=72$ and $N=120$.  The support rule
-\eqref{eq:trial-support} makes this a short block calculation: on paired
+(eq:trial-support) makes this a short block calculation: on paired
 virtual labels $((\alpha,d),(\beta,e))$ both $T$ and $O$ preserve $d-e$
 (the two layers shift by the same $2s$ for $T$, and by the same total
 physical weight $s+t$ for $O$, also in each off-diagonal term).  The
 difference blocks are exhaustive with dimensions
-\begin{equation}\label{eq:trial-blocks}
-\begin{array}{c|rrrrrrrrrrr}
+
+{c|rrrrrrrrrrr}
 d-e&-10&-8&-6&-4&-2&0&2&4&6&8&10\\ \hline
 \dim&1&8&32&80&136&162&136&80&32&8&1
-\end{array},
-\end{equation}
+,
+
 summing to $676=26^2$, each block once.
 
 The whole integer computation: form $A_s$, $B_{st}$, $T$, $O$ from the
-tables and \eqref{eq:trial-transfer}, \eqref{eq:trial-insertion},
-\eqref{eq:trial-support}, \eqref{eq:trial-entry}; restrict to each
+tables and (eq:trial-transfer), (eq:trial-insertion),
+(eq:trial-support), (eq:trial-entry); restrict to each
 difference block giving $T_\delta,O_\delta$; compute powers by
 \[
  P_0=I,\quad P_{2j}=P_j^2\ (j\ge1),\quad P_{2j+1}=P_j^2T_\delta\ (j\ge0),
 \]
 then accumulate
-\begin{equation}\label{eq:trial-integer-algorithm}
+
  U_N=\sum_\delta\sum_{i,j}(P_{N-2})_{ij}(O_\delta)_{ji},\quad
  V_N=\sum_\delta\sum_{i,j}(P_{N-2})_{ij}(T_\delta^2)_{ji},
-\end{equation}
+
 using only arbitrary-precision integers.  For $N=72$ the power is $70$;
 for $N=120$ use $T^{118}=T^{64}T^{32}T^{16}T^4T^2$ and
 $T^{120}=T^{64}T^{32}T^{16}T^8$ within each block.  The resulting exact
 integer comparisons are
-\begin{equation}\label{eq:trial-integer-results}
+
  V_N>0,\qquad -c_NV_N\le10^{12}U_N<(-c_N+1)V_N,
  \qquad
- \begin{array}{c|r}
+ {c|r}
  N&c_N\\ \hline
  72&1401482112601\\
  120&1401482105174
- \end{array}.
-\end{equation}
+ .
+
+
 
-\begin{lemma}\label{lem:trial-inputs}
 For the untwisted periodic spin-one Heisenberg Hamiltonian and
 $a=700741/500000$, $E_0(72)<-72a$ and $E_0(120)<-120a$; consequently
 $Z_{72}(b)>1$ and $Z_{120}(b)>1$ for every $b>0$.
-\end{lemma}
 
-\begin{proof}
-For each row of \eqref{eq:trial-integer-results},
+
+Proof. 
+For each row of (eq:trial-integer-results),
 $(-c_N+1)/10^{12}<-700741/500000$, so the corresponding explicit matrices
-have $V_N>0$ and $U_N/V_N<-a$; apply Lemma~\ref{lem:trial-contraction}.
-\end{proof}
+have $V_N>0$ and $U_N/V_N<-a$; apply Lemma~lem:trial-contraction.
+
 
 The support rule places these trial vectors in total weight zero, but the
 variational bound is for the minimum of the full physical spectrum; the
@@ -1633,30 +1633,30 @@ only symmetry used in the contraction is cyclic translation.  The inputs
 hold at every positive inverse temperature, so each initialization uses
 them at its own temperature.
 
-\begin{thebibliography}{99}
+{99}
 \bibitem[Haldane(1981)]{Haldane1981} F.~D.~M. Haldane, Ground state properties of antiferromagnetic chains with unrestricted spin, ILL preprint SP-81/95 (1981); reproduced as arXiv:1612.00076.
-\bibitem[Haldane(1983a)]{Haldane1983PLA} F.~D.~M. Haldane, Continuum dynamics of the 1-D Heisenberg antiferromagnet, Phys.\ Lett.\ A \textbf{93}, 464--468 (1983).
-\bibitem[Haldane(1983b)]{Haldane1983PRL} F.~D.~M. Haldane, Nonlinear field theory of large-spin Heisenberg antiferromagnets, Phys.\ Rev.\ Lett.\ \textbf{50}, 1153--1156 (1983).
-\bibitem[Lieb, Schultz and Mattis(1961)]{LiebSchultzMattis1961} E. Lieb, T. Schultz and D. Mattis, Two soluble models of an antiferromagnetic chain, Ann.\ Phys.\ \textbf{16}, 407--466 (1961).
-\bibitem[Affleck and Lieb(1986)]{AffleckLieb1986} I. Affleck and E.~H. Lieb, A proof of part of Haldane's conjecture on spin chains, Lett.\ Math.\ Phys.\ \textbf{12}, 57--69 (1986).
-\bibitem[Affleck, Kennedy, Lieb and Tasaki(1987)]{AKLT1987} I. Affleck, T. Kennedy, E.~H. Lieb and H. Tasaki, Rigorous results on valence-bond ground states in antiferromagnets, Phys.\ Rev.\ Lett.\ \textbf{59}, 799--802 (1987).
-\bibitem[Affleck, Kennedy, Lieb and Tasaki(1988)]{AKLT1988} I. Affleck, T. Kennedy, E.~H. Lieb and H. Tasaki, Valence bond ground states in isotropic quantum antiferromagnets, Comm.\ Math.\ Phys.\ \textbf{115}, 477--528 (1988).
-\bibitem[Yarotsky(2006)]{Yarotsky2006} D.~A. Yarotsky, Ground states in relatively bounded quantum perturbations of classical lattice systems, Comm.\ Math.\ Phys.\ \textbf{261}, 799--819 (2006); arXiv:math-ph/0412040.
-\bibitem[White and Huse(1993)]{WhiteHuse1993} S.~R. White and D.~A. Huse, Numerical renormalization-group study of low-lying eigenstates of the antiferromagnetic $S=1$ Heisenberg chain, Phys.\ Rev.\ B \textbf{48}, 3844--3852 (1993).
-\bibitem[Buyers et al.(1986)]{Buyers1986} W.~J.~L. Buyers, R.~M. Morra, R.~L. Armstrong, M.~J. Hogan, P. Gerlach and K. Hirakawa, Experimental evidence for the Haldane gap in a spin-1 nearly isotropic antiferromagnetic chain, Phys.\ Rev.\ Lett.\ \textbf{56}, 371--374 (1986).
-\bibitem[Batista and Ortiz(2001)]{BatistaOrtiz2001} C.~D. Batista and G. Ortiz, Generalized Jordan--Wigner transformations, Phys.\ Rev.\ Lett.\ \textbf{86}, 1082--1085 (2001); arXiv:cond-mat/0008374.
-\bibitem[Tasaki(2025)]{Tasaki2025} H. Tasaki, Ground state of the $S=1$ antiferromagnetic Heisenberg chain is topologically nontrivial if gapped, Phys.\ Rev.\ Lett.\ \textbf{134}, 076602 (2025); arXiv:2407.17041 (v4).
-\bibitem[Fannes, Nachtergaele and Werner(1992)]{FNW1992} M. Fannes, B. Nachtergaele and R.~F. Werner, Finitely correlated states on quantum spin chains, Comm.\ Math.\ Phys.\ \textbf{144}, 443--490 (1992).
-\bibitem[P\'erez-Garc\'ia et al.(2007)]{PerezGarcia2007} D. P\'erez-Garc\'ia, F. Verstraete, M.~M. Wolf and J.~I. Cirac, Matrix product state representations, Quantum Inf.\ Comput.\ \textbf{7}, 401--430 (2007); arXiv:quant-ph/0608197.
-\bibitem[Knabe(1988)]{Knabe1988} S. Knabe, Energy gaps and elementary excitations for certain VBS-quantum antiferromagnets, J.\ Stat.\ Phys.\ \textbf{52}, 627--638 (1988).
-\bibitem[Nachtergaele(1996)]{Nachtergaele1996} B. Nachtergaele, The spectral gap for some spin chains with discrete symmetry breaking, Comm.\ Math.\ Phys.\ \textbf{175}, 565--606 (1996); arXiv:cond-mat/9410110.
-\bibitem[Gosset and Mozgunov(2016)]{GossetMozgunov2016} D. Gosset and E. Mozgunov, Local gap threshold for frustration-free spin systems, J.\ Math.\ Phys.\ \textbf{57}, 091901 (2016); arXiv:1512.00088.
+\bibitem[Haldane(1983a)]{Haldane1983PLA} F.~D.~M. Haldane, Continuum dynamics of the 1-D Heisenberg antiferromagnet, Phys.\ Lett.\ A 93, 464--468 (1983).
+\bibitem[Haldane(1983b)]{Haldane1983PRL} F.~D.~M. Haldane, Nonlinear field theory of large-spin Heisenberg antiferromagnets, Phys.\ Rev.\ Lett.\ 50, 1153--1156 (1983).
+\bibitem[Lieb, Schultz and Mattis(1961)]{LiebSchultzMattis1961} E. Lieb, T. Schultz and D. Mattis, Two soluble models of an antiferromagnetic chain, Ann.\ Phys.\ 16, 407--466 (1961).
+\bibitem[Affleck and Lieb(1986)]{AffleckLieb1986} I. Affleck and E.~H. Lieb, A proof of part of Haldane's conjecture on spin chains, Lett.\ Math.\ Phys.\ 12, 57--69 (1986).
+\bibitem[Affleck, Kennedy, Lieb and Tasaki(1987)]{AKLT1987} I. Affleck, T. Kennedy, E.~H. Lieb and H. Tasaki, Rigorous results on valence-bond ground states in antiferromagnets, Phys.\ Rev.\ Lett.\ 59, 799--802 (1987).
+\bibitem[Affleck, Kennedy, Lieb and Tasaki(1988)]{AKLT1988} I. Affleck, T. Kennedy, E.~H. Lieb and H. Tasaki, Valence bond ground states in isotropic quantum antiferromagnets, Comm.\ Math.\ Phys.\ 115, 477--528 (1988).
+\bibitem[Yarotsky(2006)]{Yarotsky2006} D.~A. Yarotsky, Ground states in relatively bounded quantum perturbations of classical lattice systems, Comm.\ Math.\ Phys.\ 261, 799--819 (2006); arXiv:math-ph/0412040.
+\bibitem[White and Huse(1993)]{WhiteHuse1993} S.~R. White and D.~A. Huse, Numerical renormalization-group study of low-lying eigenstates of the antiferromagnetic $S=1$ Heisenberg chain, Phys.\ Rev.\ B 48, 3844--3852 (1993).
+\bibitem[Buyers et al.(1986)]{Buyers1986} W.~J.~L. Buyers, R.~M. Morra, R.~L. Armstrong, M.~J. Hogan, P. Gerlach and K. Hirakawa, Experimental evidence for the Haldane gap in a spin-1 nearly isotropic antiferromagnetic chain, Phys.\ Rev.\ Lett.\ 56, 371--374 (1986).
+\bibitem[Batista and Ortiz(2001)]{BatistaOrtiz2001} C.~D. Batista and G. Ortiz, Generalized Jordan--Wigner transformations, Phys.\ Rev.\ Lett.\ 86, 1082--1085 (2001); arXiv:cond-mat/0008374.
+\bibitem[Tasaki(2025)]{Tasaki2025} H. Tasaki, Ground state of the $S=1$ antiferromagnetic Heisenberg chain is topologically nontrivial if gapped, Phys.\ Rev.\ Lett.\ 134, 076602 (2025); arXiv:2407.17041 (v4).
+\bibitem[Fannes, Nachtergaele and Werner(1992)]{FNW1992} M. Fannes, B. Nachtergaele and R.~F. Werner, Finitely correlated states on quantum spin chains, Comm.\ Math.\ Phys.\ 144, 443--490 (1992).
+\bibitem[P\'erez-Garc\'ia et al.(2007)]{PerezGarcia2007} D. P\'erez-Garc\'ia, F. Verstraete, M.~M. Wolf and J.~I. Cirac, Matrix product state representations, Quantum Inf.\ Comput.\ 7, 401--430 (2007); arXiv:quant-ph/0608197.
+\bibitem[Knabe(1988)]{Knabe1988} S. Knabe, Energy gaps and elementary excitations for certain VBS-quantum antiferromagnets, J.\ Stat.\ Phys.\ 52, 627--638 (1988).
+\bibitem[Nachtergaele(1996)]{Nachtergaele1996} B. Nachtergaele, The spectral gap for some spin chains with discrete symmetry breaking, Comm.\ Math.\ Phys.\ 175, 565--606 (1996); arXiv:cond-mat/9410110.
+\bibitem[Gosset and Mozgunov(2016)]{GossetMozgunov2016} D. Gosset and E. Mozgunov, Local gap threshold for frustration-free spin systems, J.\ Math.\ Phys.\ 57, 091901 (2016); arXiv:1512.00088.
 \bibitem[Banerjee, Guo and Chowdhury(2026)]{BanerjeeGuoChowdhury2026} S. Banerjee, H. Guo and D. Chowdhury, Bootstrap certification of string order in quantum spin chains, arXiv:2609.22420 (2026).
-\bibitem[Suzuki(1985)]{Suzuki1985} M. Suzuki, Transfer-matrix method and Monte Carlo simulation in quantum spin systems, Phys.\ Rev.\ B \textbf{31}, 2957--2965 (1985).
-\bibitem[Aizenman and Nachtergaele(1994)]{AizenmanNachtergaele1994} M. Aizenman and B. Nachtergaele, Geometric aspects of quantum spin states, Comm.\ Math.\ Phys.\ \textbf{164}, 17--63 (1994); arXiv:cond-mat/9310009.
-\bibitem[Fox and Glynn(1988)]{FoxGlynn1988} B.~L. Fox and P.~W. Glynn, Computing Poisson probabilities, Comm.\ ACM \textbf{31}, 440--445 (1988).
-\bibitem[Bochev and Markov(1989)]{BochevMarkov1989} P. Bochev and S. Markov, A self-validating numerical method for the matrix exponential, Computing \textbf{43}, 59--72 (1989).
-\bibitem[Goldsztejn and Neumaier(2014)]{GoldsztejnNeumaier2014} A. Goldsztejn and A. Neumaier, On the exponentiation of interval matrices, Reliable Computing \textbf{20}, 53--72 (2014).
-\end{thebibliography}
-
-\end{document}
+\bibitem[Suzuki(1985)]{Suzuki1985} M. Suzuki, Transfer-matrix method and Monte Carlo simulation in quantum spin systems, Phys.\ Rev.\ B 31, 2957--2965 (1985).
+\bibitem[Aizenman and Nachtergaele(1994)]{AizenmanNachtergaele1994} M. Aizenman and B. Nachtergaele, Geometric aspects of quantum spin states, Comm.\ Math.\ Phys.\ 164, 17--63 (1994); arXiv:cond-mat/9310009.
+\bibitem[Fox and Glynn(1988)]{FoxGlynn1988} B.~L. Fox and P.~W. Glynn, Computing Poisson probabilities, Comm.\ ACM 31, 440--445 (1988).
+\bibitem[Bochev and Markov(1989)]{BochevMarkov1989} P. Bochev and S. Markov, A self-validating numerical method for the matrix exponential, Computing 43, 59--72 (1989).
+\bibitem[Goldsztejn and Neumaier(2014)]{GoldsztejnNeumaier2014} A. Goldsztejn and A. Neumaier, On the exponentiation of interval matrices, Reliable Computing 20, 53--72 (2014).
+
+
+