1$ put $h_0=q_0^{m-1}$ as in
\cref{eq:trans-powers}; when $m=1$ choose a power $h_0=p^{\nu_0}>1$
fixing the same finite constants. In either case set
$\nu_0=\log_p h_0$.
\begin{proposition}[The fixed normalized transfer]
\label[proposition]{prop:trans-cartier}
At the finite marking stage of \Cref{prop:trans-volume}, the operator
\begin{equation}
S(f)=\frac{\Cartier^{\nu_0}(f\eta)}{\eta}\quad(f\in R)
\label{eq:trans-S}
\end{equation}
is continuous, $\kk$-linear, and $G$-equivariant. It satisfies
$S(b^{h_0}f)=bS(f)$. For $m>1$, the maps on $R$ induced by nonzero
translation augmentations $\mathsf N_{q_0^a}\to\kk$, after the root
identification, are nonzero scalar multiples of $S^a$. For $m=1$ one
can choose the toral frame so that
\begin{equation}
S\Fr^{\nu_0}=1.
\label{eq:trans-height-one-split}
\end{equation}
Extend $S$ to $B'$ by $S(f)=S(ef)$, with image in $eB'$. There is a
fixed integer $c\geq0$ such that, for every integer $D$,
\begin{equation}
S(x^{-D}A')\subset x^{-\lceil D/h_0\rceil-c}A'.
\label{eq:trans-pole-bound}
\end{equation}
Every sufficiently large $D_0$ makes
$\mathcal P=x^{-D_0}A'$ stable under $S$. Every fixed bounded-pole
lattice, including any compact family of cochains with values in it,
is carried into $\mathcal P$ by all sufficiently large iterates.
The volume, its inverse, the whole trace-pairing matrices and their
inverses have one fixed pole bound $c'$. In the normalized basis
$b_i^{1/h}$, $h=h_0^a$, their transported matrices have pole losses at
most $c'/h$. The normalized Cartier maps are adjoint to the inclusions
of root Laurent representatives under the residue pairings with the
transported volumes.
\end{proposition}
\begin{proof}
The formula and \Cref{prop:trans-volume} give equivariance and
$h_0^{-1}$-linearity. This is $\kk$-linearity because $h_0$ fixes the
finite field. Continuity follows by grouping finitely many residue
exponents in the $h_0$-basis expansion; multiplication by the fixed
volume and its inverse is continuous on bounded-pole steps.
The intermediate volume factors cancel under composition, so
$S^a(f)=\Cartier^{a\nu_0}(f\eta)/\eta$ for every $a\geq1$.
Suppose first that $m>1$. Put
$s_q=\prod_iD_i^{q-1}\in\Lambda_q$. A $\Lambda$-linear functional
$\mathsf N_q\to\kk$ is evaluation at a socle element of $\Lambda_q$.
Its space is the one-dimensional line generated by evaluation at
$s_q$. Make $U$ pro-$p$. The action on this line is a continuous
character to $\kk^\times$, a group of order prime to $p$, so it is
trivial. The maps therefore descend with their natural actions.
Successive coinduction composes the basic socle evaluations into
evaluation at
\[
\prod_{j=0}^{a-1}s_{q_0}(D_1^{q_0^j},\ldots,D_d^{q_0^j})
=\prod_iD_i^{q_0^a-1},
\]
which is nonzero in $\Lambda_{q_0^a}$. Thus these composites do not
vanish. The coherence of \Cref{prop:trans-roots} identifies their
coefficient maps with the root-twisted composites of
$T_{\eta,h_0}$. In selfmap notation these are $S^a$.
\Cref{prop:trans-volume} identifies any other nonzero augmentation
with a nonzero constant multiple; the constants introduce no
semilinear twist because all chosen powers fix $\kk$.
Suppose now that $m=1$. We use the order-$p$ torsor
$C=R^{1/p}$ under the fixed group $\mu_p^r$ from
\Cref{prop:trans-volume}. Its character decomposition is strongly
graded by $(\Z/p\Z)^r$, with neutral component $R$ and invertible
character components
\citep[Theorem~12.12 and Remark~12.13]{milne2017}.
The strong grading uses the torsor hypothesis: after a faithfully
flat trivialization, each character component is free of rank one
and multiplication between components is an isomorphism. These
properties descend to $R$.
Zariski locally on $\Spec R$, choose generators $z_i$ of the
fundamental character components. Strong grading makes each $z_i$
a unit, with $b_i=z_i^p\in R^\times$. The monomials $z^\alpha$,
$0\leq\alpha_i(c+1)/(1-h_0^{-1})$. The same inequality implies
$\lceil D_0/h_0\rceil+c\leq D_0$ and, for each fixed $D$, eventually
$D_a\leq D_0$. The estimates apply to the whole lattice, uniformly
over any compact parameter set. A compact bounded-pole cochain
family uses one such $D$, so the assertion about cochains follows as
well.
For the trace and volume assertion, set
\[
\theta=d\log x\wedge dy_1\wedge\cdots\wedge dy_{r-1}.
\]
Write $\eta=a_R\theta$ with $a_R\in R^\times$. Extend its coefficient
to the unit $a=a_R+(1-e)\in B'^\times$ and use $a\theta$ on the whole
algebra. The trace form of the finite \'{e}tale algebra is perfect;
therefore the matrices
\[
\bigl(\Tr_{B'/B}(b_i b_j)\bigr)_{ij},\qquad
\bigl(\Tr_{B'/B}(a b_i b_j)\bigr)_{ij}
\]
and their inverses have entries in $B$. The multiplication matrices
of $e,a,a^{-1}$ do also. Taking a maximum bounds all their poles by
one $c'$. Transport by the root isomorphism replaces every matrix
entry by its $h$th root. Its pole bound in the original $x$-valuation
is consequently $c'/h$. The volume at this level is
\[
\eta_h=a^{1/h}\,d\log x^{1/h}\wedge
dy_1^{1/h}\wedge\cdots\wedge dy_{r-1}^{1/h}.
\]
This is transport along an isomorphism, not differential pullback
under an inseparable map.
Finally take a finite Laurent principal-part representative $w$ on
one root grid and a bounded-pole coefficient on the next grid, and
pair them by the coefficient residue of their product times
$\eta_h$, after the finite \'{e}tale trace. In the logarithmic
$x$-coordinate the residue selects exponent zero; in each ordinary
$y$-coordinate it selects exponent $-1$. \Cref{eq:trans-cartier-coordinates} therefore gives
\begin{equation}
\langle w,T_{h,hh_0}(f)\rangle_h
=\langle \iota w,f\rangle_{hh_0},
\label{eq:trans-residue-adjoint}
\end{equation}
where $T_{h,hh_0}$ is the $h$-root of $T_{\eta,h_0}$ and $\iota$ is
inclusion of the same Laurent expression on the finer grid.
For instance the ordinary one-variable test is
$h_0i+j=-1$ on both sides; the logarithmic test is $h_0i+j=0$.
The coefficient field is fixed by $h_0$, so taking the selected
coefficient introduces no field twist. Finite \'{e}tale trace
commutes with this calculation, since its root matrix is the
transported trace matrix. Multiplication by the volume coefficient
and its inverse cancels as in
\cref{eq:trans-cartier-functional}. Thus the scalar monomial check
proves \cref{eq:trans-residue-adjoint} in the whole basis and then
after $e$. Continuity extends the identity whenever a convergent
Laurent expression defines a residue functional. This is the
adjoint identity used below; no trace for the purely inseparable
root extension is involved.
\end{proof}
\begin{lemma}[One bound for a fixed finite diagram]
\label{lem:trans-diagram-bound}
Fix a finite Yoneda diagram of translation representations, descend
it at a finite marking stage, and fix a cohomological degree. Its
successive boundary maps can be represented by an operator on
cocycles that loses at most one fixed $x$-pole order. Under
\Cref{prop:trans-roots}, all of its coinduced diagrams use the roots
of this same operator and its chosen splittings.
\end{lemma}
\begin{proof}
Every term and image bundle is finite locally free on the affine
scheme $\Spec R$. Each surjection onto such an image has an
underlying $R$-linear section. Choose these finitely many sections
once. Embed their finite projective modules in finite free modules
and choose finitely generated whole $A$-lattices; each section is
then a finite matrix over the localization and has a fixed pole
loss. The group action on a fixed lattice has a uniform pole bound,
by the finite torsor realization and the bounded-step continuity of
\Cref{lem:cts-exact,prop:mark-whole-model}. Since $g(x)/x$ is an
integral unit, the same bound applies to every shift of that lattice.
The finitely many group differentials and chosen sections computing
the composite boundary thus have a common total pole loss. This
constructs the required operator on continuous cocycles, with their
bounded-pole convention.
The natural identity \cref{eq:trans-root-functor} carries the entire
diagram, including its arrows, to its root diagram. Transport each
of the already chosen sections by the same root isomorphism.
Computing the boundary with those sections is exactly the root of
the original computation. Hence the increasing ranks of the
coinduced representations require no new choices of matrices or
new pole estimate. This statement concerns realization of a fixed
diagram; comparisons of extension classes after one common
auxiliary shrink are supplied in \Cref{sec:pro-transfer}.
\end{proof}
==== END Finite-generation-for-the-Kn-local-sphere//07-natural-transfers.tex ====
==== BEGIN Finite-generation-for-the-Kn-local-sphere//08-laurent-model.tex ====
\section{The Laurent model for analytic compact supports}
\label{sec:laurent}
We now express the compact supports of the geometric calculation as
convergent Laurent series. The output is an explicit module with the
actual stabilizer action and finite cohomology and homology. Its
finite-field form will carry the residue map that is transpose to the
Cartier transfer, including series with unbounded root denominators.
Fix $1\leq m0}\bigr)^s,
\qquad |J|=J_1+\cdots+J_s.
\]
If $s=0$, the second factor has one element and $|J|=0$.
For $L>\delta>0$ define
\begin{equation}\label{eq:laurent-weight}
w_{L,\delta}(I,J)=
\begin{cases}
LI-\delta|J|,&I\geq0,\\
\delta I-\delta|J|,&I<0.
\end{cases}
\end{equation}
Let $\mathscr L_{L,\delta}(\mathcal D)$ consist of the sums
\[
f=\sum_{(I,J)\in\mathcal E}a_{I,J}x^Iy^{-J},
\qquad a_{I,J}\in R_{\mathcal D},
\]
such that the numbers
$\|a_{I,J}\|_{\sup}\exp(-w_{L,\delta}(I,J))$ tend to zero outside
finite subsets of $\mathcal E$. Equip this space with the maximum of
these numbers as norm. It is a complete nonarchimedean normed module:
coefficientwise limits of a Cauchy sequence have uniformly small tails,
which proves both the required decay and convergence in the norm.
Finite sums are dense. Define
\[
\mathscr L(\mathcal D)=\colim_{L,\delta}
\mathscr L_{L,\delta}(\mathcal D).
\]
The transitions increase $L$ and decrease $\delta$. They are norm
nonincreasing, since these changes increase every weight. Rational pairs
$L>\delta>0$, or the sequence $(L,\delta)=(j,j^{-1})$ with $j\geq2$,
are cofinal. The colimit here and below has the complete-step convention
of \cref{sec:continuous}; a parameter family belongs to one step.
Multiplication by an element of $B$ is multiplication of Laurent series
followed by discarding every monomial whose exponent in some $y_j$ is
nonnegative. This prescription is well defined in the complete steps.
Indeed, if $a\in x^{-c}A$, every monomial of $a$ has exponents
$(A_0,B_0)$ with $A_0\geq-c$ and all $(B_0)_j\geq0$. Whenever its
product survives the projection,
\begin{equation}\label{eq:laurent-matrix-bound}
w_{L,\delta}(I+A_0,J-B_0)
\geq w_{L,\delta}(I,J)-Lc.
\end{equation}
This follows because the increasing piecewise linear function
$I\mapsto LI$ for $I\geq0$, $I\mapsto\delta I$ for $I<0$, has slopes
between $\delta$ and $L$. At a fixed root grid, multiplying one
monomial by $a$ gives a convergent series: after projection only finitely
many $y$-exponents survive below the original pole orders, and the
remaining $x$-orders tend to infinity. The bound extends multiplication
from finite sums to arbitrary sums, proves its continuity, and justifies
associativity by dense finite-sum approximation. A matrix with entries
in $x^{-c}A$ has the same bound, up to the maximum norm of its finitely
many entries.
Consequently $e$ is a continuous chain-compatible idempotent on the
whole ambient Laurent module. We use the notation
\[
\mathscr W_{\mathcal D}
=e\bigl(\mathscr L(\mathcal D)\otimes_A A'\bigr),
\qquad
W_{\mathcal D}
=e\bigl(\mathscr L(\mathcal D;\kk)\otimes_A A'\bigr),
\qquad W=W_{\{*\}},
\]
where $\mathscr L(\mathcal D;\kk)$ denotes the same sums with
coefficients in $C(\mathcal D,\kk)$. The tensor notation means the
finite sum on the displayed basis, with the multiplication action just
defined; it introduces no additional completion. The image of $e$ in
each step is closed, since it is the kernel of $1-e$, and is therefore
complete.
For finite-field coefficients the decay condition has a useful strong
consequence. For every real $M$, a family in one step has only finitely
many nonzero coefficients with $I\leq M$, uniformly on $\mathcal D$.
Indeed, every nonzero coefficient has supremum norm one, whereas
\[
I\leq M\quad\Longrightarrow\quad
w_{L,\delta}(I,J)\leq L\max(M,0).
\]
Infinitely many such coefficients would contradict decay. Each of the
remaining finitely many coefficient functions is locally constant.
In particular bounded-$x$ truncation produces a locally constant family
of finite principal parts, even when the original exponents have
unbounded $p$-power denominators. For a one-point parameter the steps
are separable: their finite sums have coefficients in the finite field
and indices in the countable set $\mathcal E$. Thus the complete steps
of $W$ are Polish additive groups. A condition that coefficients vanish
outside a prescribed subset, for example $I\geq a>0$, is closed on each
such step.
\subsection{The support complex and coefficient descent}
Let $Q_k=|\kk|$. The operator $\varphi$ used in this subsection raises
coefficients in $F$ to their $Q_k$th powers and fixes $x^I$, $y^{-J}$,
and every $b_\nu$. It fixes the structure constants of $A'$ and the
matrix of $e$, since they are defined over $\kk$. This is
\emph{coefficient-only} Frobenius. For a complex $K$ with this operator
write
\[
K^{\varphi=1}=\operatorname{fib}(\varphi-1:K\longrightarrow K).
\]
\begin{proposition}[Laurent support comparison]\label[proposition]{prop:laurent-model}
With the uniform compact-support convention of
\cref{lem:tower-supports}, there are natural quasi-isomorphisms
\begin{equation}\label{eq:laurent-descent}
\RGamma_c(Z_U,\cO^\flat;\mathcal D)
\simeq\mathscr W_{\mathcal D}[-r],
\qquad
\RGamma_c(Z_U,\cO^\flat;\mathcal D)^{\varphi=1}
\simeq W_{\mathcal D}[-r].
\end{equation}
They are compatible with finite marking maps, the idempotent $e$, and
the actions defined over $\kk$. The support cohomology is therefore
concentrated in cohomological degree $r$, both before and after
coefficient descent. Every fixed normalized root basis
$b_1^{1/h},\ldots,b_N^{1/h}$ gives the same module and the same
complete-step category.
\end{proposition}
\begin{proof}
We first calculate on $X$ with scalar coefficients. Compact bounds
are cofinal among boxes
\[
K(a,b,\rho)=
\{a\leq|x|\leq b,\ |y_j|\leq\rho\ (1\leq j\leq s)\},
\qquad 01$, a root has norm $|b|^{1/Q_k}$. These choices have
continuous local branches: around a root $a_0$ for $b_0$, add the
small solution for $b-b_0$. Near a point with $|b_0|\geq1$ take
$|b-b_0|<1$, so the same bound is retained; on $|b|<1$ use the
displayed series itself. For a continuous function on a compact
profinite $\mathcal D$, a finite clopen refinement of these local
charts therefore gives a continuous solution with
$\|a\|_{\sup}\leq\|b\|_{\sup}$.
Apply this construction separately to every Laurent coefficient.
The weighted norms do not increase, so all the chosen coefficients
assemble to a family in the original complete step. Uniformly small
tails make that assembled family continuous even though the finite
clopen partitions used for different coefficients may differ.
Solving on the whole finite sum and then applying $e$ proves
surjectivity on $\mathscr W_{\mathcal D}$. Its kernel is exactly
$W_{\mathcal D}$, since the fixed elements of $F$ are $\kk$ and $e$
is fixed. This proves the second quasi-isomorphism.
Finally, relative Frobenius identifies each fixed root version of
$A'[1/x]$ with its base change to $B^{1/h}$. Thus
$b_\nu^{1/h}$ is a basis over the perfected base. Any two fixed
such bases are related by invertible matrices over a finite root
version of $B$, with bounded $x$-poles and no negative $y$-powers.
The bound \cref{eq:laurent-matrix-bound}, rescaled to that root grid,
makes both basis changes continuous. If a fixed matrix before
taking roots has pole bound $c$, its $h$-root has bound $c/h$.
Moreover, when $h\mid h'$, each $b_\nu^{1/h}$ expands integrally
in the basis $b_\mu^{1/h'}$: it is the $(h'/h)$th power of a basis
element, and the multiplication laws of the root model are integral.
These observations prove both the basis assertion and compatibility
with the stated operations.
\end{proof}
\subsection{Uniform continuity of the group action}
\begin{lemma}\label[lemma]{lem:laurent-action}
The $G$-action on $W$ and on $\mathscr W_{\mathcal D}$ is jointly
continuous from a complete step, with a compact set of group and
parameter values, into a complete step. It is uniformly
equicontinuous there. The same holds for multiplication by the
finite marked function algebra, fixed root-basis changes, and the
finite matrices occurring in continuous group resolutions.
Absolute Frobenius is an invertible additive operator on these
modules. Its sufficiently divisible powers fixing $\kk$ commute
with $G$ and act by chain automorphisms on the group complexes over
$\kk$.
\end{lemma}
\begin{proof}
We check the scalar coordinate changes first. An integral formal
automorphism preserving $(x)$ factors into three types:
\[
x\longmapsto xu(x,y),\quad y\longmapsto y;
\qquad x\longmapsto x,\quad y\longmapsto y+c(x);
\qquad x\longmapsto x,\quad y\longmapsto v(x,y),
\]
where $u$ is an integral unit, $c(x)\in x\kk[[x]]^s$, and the last
map preserves $(y)$ and has invertible linear Jacobian in $y$ over
$\kk[[x]]$. To obtain the factorization, first remove the $x$-unit
substitution by its formal inverse. For the residual map fixing
$x$, subtract the value of its $y$-coordinates at $y=0$; the
remaining map fixes $(y)$ and its $y$-Jacobian is invertible.
All inverse maps are integral. These operations are continuous on
formal jets, uniformly in a compact family.
Fix a root grid $1/h$ and a monomial $x^Iy^{-J}$. For each of the
three types every surviving output monomial $x^{I'}y^{-J'}$ satisfies
\begin{equation}\label{eq:laurent-action-order}
I'\geq I,\qquad |J'|\leq |J|+(I'-I).
\end{equation}
For the $x$-unit substitution, the expansion of $u^I$ on the root
grid has only nonnegative additional $x$- and $y$-orders, giving
the stronger bound $|J'|\leq|J|$. For translation, write
$X=x^{1/h}$ and $Y_j=y_j^{1/h}$. Expanding
$(Y_j+c_j(x)^{1/h})^{-hJ_j}$, an increase $a_j/h$ in its pole
requires the factor $c_j(x)^{a_j/h}$, whose $x$-order is at least
$a_j/h$. Summing over $j$ gives
\cref{eq:laurent-action-order}.
For the third type use finite principal-parts duality, which also
avoids choosing a preferred expansion of a general linear
combination of the $y_j$. On the grid just fixed the negative
$Y$-powers form
\[
H^s_{(Y)}\bigl(\kk[[X,Y_1,\ldots,Y_s]]\bigr),
\]
with coefficients extended in $X$ as needed. A principal part
$Y^{-j}$ pairs with $Y^{j-1}\,dY_1\cdots dY_s$ by coefficient
extraction. This is a perfect pairing between every finite
principal-part truncation and the corresponding quotient of the
power-series ring. If $v$ preserves $(Y)$, then its inverse and
the determinant of its inverse Jacobian are integral, and
\[
(v^{-1})^*(Y^{j'-1}\,dY_1\cdots dY_s)
\]
has total $Y$-degree at least $|j'|-s$. It cannot pair nontrivially
with $Y^{-j}$ when $|j'|>|j|$. Every coefficient remains in
$\kk[[X]]$. Thus here $I'\geq I$ and $|J'|\leq|J|$.
The pairing description is the usual change-of-variables map on
the finite \v Cech complex: it is first checked on monomial
fractions by coefficient extraction and then on their finite
principal-part span. Hence it represents the geometric support
pullback. The case $s=0$ requires no such step.
The two inequalities in \cref{eq:laurent-action-order} are stable
under composition. They imply
\[
w_{L,\delta}(I',J')\geq w_{L,\delta}(I,J)
\qquad(L>\delta>0).
\]
When both $x$-exponents are negative this uses the slope $\delta$;
when both are nonnegative it uses $L\geq\delta$; when they cross
zero the excess is at least $(L-\delta)I'$. The output of a fixed
monomial is convergent. For translations, after $I'$ becomes
nonnegative the weight increases by at least $L-\delta$ per
additional unit of pole, and at a fixed grid only finitely many
terms precede that crossing. For a map preserving $(y)$, the
total $y$-pole order is bounded and its remaining $x$-series
converges. The $x$-unit case has the same property.
These expansions also occur on actual analytic collars. For
example
\[
(y+x)^{-1}=\sum_{j\geq0}(-x)^jy^{-j-1}
\]
converges on $|x|<|y|$, and its term weights are
$(L-\delta)j-\delta$. Any compact support bound can be enlarged
so that its $y$-radius exceeds its $x$-radius. The same enlargement
works for every integral $c(x)$ because $|c(x)|\leq|x|$.
For maps preserving $(y)$ the ideal and its inverse have the same
total-radius bounds; finite \v Cech refinements give the
principal-parts pullback above. Thus the algebraic formulas agree
with the canonical support action used in
\cref{prop:laurent-model}.
All coefficients of these integral maps have norm at most one.
The weight estimate therefore gives a uniform operator bound on
each complete scalar step. For a fixed monomial, every
bounded-weight output truncation involves finitely many monomials
on its fixed root grid and depends on finitely many formal jets.
It consequently varies continuously with the group element.
For an arbitrary convergent sum, discard a uniformly small tail
and apply this assertion to its finite remainder. This proves
joint continuity and equicontinuity, including all compact
parameters. Operator-norm continuity in the group element is
neither asserted nor needed.
On the whole finite model, the group action is the scalar pullback
just treated followed by a finite basis matrix. The integral
model of \cref{prop:mark-whole-model} and compactness give a uniform
pole bound for those matrices and their inverses. Their entries
vary continuously in the bounded-lattice topology. Apply
\cref{eq:laurent-matrix-bound}; then pass to the invariant image
of $e$. This proves the same assertions for the marked module.
That bound also proves the claims about multiplication and root
bases.
For completeness, these estimates allow integration against
compact free resolution terms as in \cref{lem:cts-comparison}.
If a compact family has image $K_0$ in a complete linearly
topologized $\kk$-step, the closed $\kk$-linear span of $K_0$ is
compact. Modulo any open linear subgroup its image is the span
of a finite set over the finite field, hence finite; this proves
total boundedness, and completeness gives compactness. Enlarge
the step first to contain the compact group translates if
necessary. Summation against compact distributions, and the
resolution comparison homotopies, therefore remain inside a
complete step. No boundary image is replaced by its closure.
Finally, absolute Frobenius raises coefficients and basis
elements to their $p$th powers \emph{and scales every exponent by
$p$}. The relative-Frobenius basis identifications in
\cref{prop:laurent-model} and the rescaled weight condition show
that this operation and its inverse act continuously between
steps. It commutes with the geometric action. A power fixing
$\kk$ is $\kk$-linear, so it commutes with the differentials and
homotopies of resolutions over $\kk$. This operation is distinct
from the coefficient-only $\varphi$ in
\cref{eq:laurent-descent}.
\end{proof}
\subsection{Finiteness of cohomology and homology}
\begin{corollary}\label[corollary]{cor:laurent-finite}
At every sufficiently deep product marking level used in
\cref{cor:ind-finite}, both $H^a_{\cts}(G,W)$ and
$H_i^{\cts}(G,W)$ are finite-dimensional over $\kk$ for every
$a,i\geq0$. Since $\kk$ is finite, these are finite groups.
\end{corollary}
\begin{proof}
Put $K=\RGamma(G,\RGamma_c(Z_U,\cO^\flat))$, with no external
parameter. By \cref{cor:ind-finite}, every $H^j(K)$ is
finite-dimensional over $F$. By \cref{lem:laurent-action} the
complete-step comparisons in \cref{lem:cts-comparison} apply.
The finite-type resolution in each degree commutes with taking
the fiber of $\varphi-1$. Thus
\begin{equation}\label{eq:laurent-group-descent}
K^{\varphi=1}\simeq\RGamma(G,W)[-r].
\end{equation}
One can equally form this fiber on bounded-step bar cochains:
the parameter-uniform surjectivity proved above applies to the
compact bar parameters, and the two descriptions agree.
We recall explicitly the finite-dimensional semilinear argument.
If $V$ is an $F$-vector space of dimension $d$ and $\psi$ is an
invertible $Q_k$-semilinear map, choose coordinates
$\psi(z)=Az^{[Q_k]}$ with $A$ invertible. For any target $t$,
the equations $Az^{[Q_k]}-z=t$ are, after multiplication by
$A^{-1}$, monic equations with pairwise coprime leading
monomials $z_1^{Q_k},\ldots,z_d^{Q_k}$. Monomial reduction gives
a quotient algebra of dimension $Q_k^d$, with basis
$\prod z_i^{a_i}$ for $0\leq a_i1$, if necessary, so that $h_0$-power Frobenius fixes $\kk$.
Write
\[
A=\kk[[x,y_1,\ldots,y_{r-1}]],\qquad
B'=A'[1/x],\qquad B_U=eB',
\]
where $A'$ is the whole finite free model, with a fixed integral basis
$b_1,\ldots,b_t$, and $e$ is its $G$-invariant idempotent on the open.
We use the normalized $\kk$-linear Cartier transfer $S$ of
\cref{prop:trans-cartier}; on $B'$ it means $f\mapsto S(ef)$.
Thus its output lies in $eB'$, and it is zero on $(1-e)B'$.
There is a constant $c_S\geq0$, independent of the nonnegative integer
$D$, such that
\begin{equation}
S(x^{-D}A')\subseteq
x^{-\lceil D/h_0\rceil-c_S}A'.
\label{eq:cutoff-pole-recurrence}
\end{equation}
All coefficient maps are $G$-equivariant and are continuous on a
bounded pole lattice into the indicated lattice. In particular they
act on the cochain and chain complexes of \cref{sec:continuous}.
Choose an integer $D_0$ sufficiently large that
\begin{equation}
D_0>\frac{c_S+1}{1-h_0^{-1}},\qquad
\mathcal P=x^{-D_0}A'.
\label{eq:cutoff-lattice-choice}
\end{equation}
We will increase $D_0$ once more for a residue bound below. The lattice
$\mathcal P$ is compact, metrizable, $G$-stable, and $S$-stable.
Moreover, for every integer $D\geq0$ there exists $a_0(D)$ such that
\begin{equation}
S^a(x^{-D}A')\subseteq\mathcal P
\quad\text{for all }a\geq a_0(D).
\label{eq:cutoff-eventual-integrality}
\end{equation}
Indeed iteration of \cref{eq:cutoff-pole-recurrence}, with the rounding
absorbed by $c_S+1$, gives the upper bound
\[
h_0^{-a}D+(c_S+1)\frac{1-h_0^{-a}}{1-h_0^{-1}}
\]
for the pole order. The strict inequality in
\cref{eq:cutoff-lattice-choice} proves
\cref{eq:cutoff-eventual-integrality}. This conclusion is uniform on
each indicated lattice and on compact families of its elements; its
exponent is allowed to depend on $D$.
\subsection{Normalized bases and the positive Laurent subspace}
Put $h=h_0^a$, $x_h=x^{1/h}$, $y_{j,h}=y_j^{1/h}$, and
$b_{i,h}=b_i^{1/h}$. We regard all these root rings inside a common
perfected coefficient ring. The $b_{i,h}$ are the
\emph{normalized basis at level $h$}; they form a basis of
$B'^{1/h}$ over $B^{1/h}$ and of the corresponding analytic coefficient
module over the perfected base. This is an actual root basis, not a
new choice of monomials made separately for each element.
The direction of the change of basis is important. If $h'=h h_0^v$,
then $b_{i,h}$ expands on the $b_{j,h'}$ with coefficients in
$A^{1/h'}$. To see this, expand $b_i^{h_0^v}$ on the integral basis of
$A'$ and take its $h'$th roots. Consequently this change of basis
introduces neither negative x-orders nor negative y-orders. The
opposite change of basis can have x-poles, but at each fixed level its
matrix has bounded x-poles and no negative y-orders. The topology and
cofinal complete steps supplied by \cref{prop:laurent-model} are
independent of these fixed changes of basis.
Let $\eta$ be the invariant volume of \cref{prop:trans-volume}. Extend
it arbitrarily by a volume generator on the complementary component of
$B'$. At level $h$ write its transported version as
\[
\eta_h=\theta_h\,d\log x_h\wedge
dy_{1,h}\wedge\cdots\wedge dy_{r-1,h},
\qquad \theta_h\in (B'^{1/h})^\times.
\]
The extension on the complementary component need not be invariant;
all expressions eventually paired will lie in the $e$-component.
Finite étaleness makes the trace pairing perfect. The matrix
\begin{equation}
\mathcal T_h=
\bigl(\Tr_{B'^{1/h}/B^{1/h}}
(b_{i,h}b_{j,h}\theta_h)\bigr)_{i,j}
\label{eq:cutoff-trace-matrix}
\end{equation}
and its inverse act on the negative-y Laurent quotient.
By increasing a fixed integer $c\geq1$, we may assume that their
coefficients, and all fixed multiplication matrices used with them,
have x-poles at most $c/h$ and no negative y-orders. In fact these are
the root transports of fixed matrices at level one. Increase $D_0$ so
that
\begin{equation}
D_0>c.
\label{eq:cutoff-residue-margin}
\end{equation}
The choice still satisfies \cref{eq:cutoff-lattice-choice}.
For a compact $\kk$-vector space $V$ write
$V^\vee=\Hom_{\kk,\cts}(V,\kk)$ with the discrete topology.
Composing with $\Tr_{\kk/\Fp}$ identifies this with the usual
finite-field Pontryagin dual. Define
\begin{equation}
Q=\colim\bigl(
\mathcal P^\vee\xrightarrow{S^\vee}\mathcal P^\vee
\xrightarrow{S^\vee}\cdots\bigr),
\label{eq:cutoff-Q}
\end{equation}
and give $Q$ the discrete topology. The dual of $\mathcal P$ is
countable: a continuous functional depends on only finitely many
coefficients in its whole finite basis, and $\kk$ and the monomial
index set are finite and countable, respectively. Thus $Q$ is
countable. The actions on these discrete duals are continuous, since
the original action on the compact lattice is jointly continuous.
We recall explicitly the Laurent convention from
\cref{prop:laurent-model}. An element of $W$ is an $e$-supported
expression on the whole basis with monomials
\[
x^I y_1^{-J_1}\cdots y_{r-1}^{-J_{r-1}},
\qquad I\in\Z[1/p],\quad
J_j\in\Z[1/p]_{>0},
\]
whose coefficients are in $\kk$ and tend to zero in some weighted
complete step
\begin{equation}
w_{L,\delta}(I,J)=
\begin{cases}
LI-\delta|J|,&I\geq0,\\
\delta I-\delta|J|,&I<0,
\end{cases}
\quad L>\delta>0,
\qquad |J|=\sum_jJ_j.
\label{eq:cutoff-weight}
\end{equation}
The norm of a nonzero monomial is $\exp(-w_{L,\delta}(I,J))$.
When $r=1$ there are no y-variables, and all references to their
negative parts are omitted. Multiplication by an analytic coefficient
is followed by projection to the part strictly negative in every
y-variable. Root denominators in an element of $W$ need not be
bounded.
\begin{definition}
An element $w\in W$ belongs to $W_+$ if, in some normalized basis
$b_{i,h}$, every nonzero coefficient monomial of $w$ has
$I\geq\epsilon$ for some real $\epsilon>0$. The bound is uniform
over its finitely many basis components. This condition imposes no
bound on the denominators of the exponents in those components.
\end{definition}
Positivity persists on every later normalized basis, by the integral
change of basis described above. Hence the definition makes $W_+$ a
vector subspace: two elements may be compared at one later level and
with the smaller of their two positive bounds. The absolute
Frobenius operator
\[
\Phi:W\longrightarrow W,\qquad w\longmapsto w^{h_0},
\]
is a $\kk$-linear automorphism, as established on the support model
in \cref{prop:laurent-model}. It scales all exponents and transports
the actual root basis. Both $\Phi$ and $\Phi^{-1}$ preserve $W_+$.
This operator is distinct from the coefficient-only Frobenius used
to obtain $W$ in \cref{eq:laurent-descent}.
Our aim is to identify $Q$ with $W/W_+$. At root level $h$, the
compact test lattice and the trace matrices have pole bounds of order
$1/h$. Hence a Laurent expression with a fixed positive x-gap is
invisible to all sufficiently late residue tests. Conversely, a series
with finite-field coefficients has only finitely many nonzero terms
below any fixed x-order. Truncating those terms will define the residue
class even when the remaining series has unbounded root denominators.
After constructing this quotient, we will prove that $W_+$ has zero
group homology. Absolute Frobenius supplies the contraction, and
countability will make boundaries open in each complete cycle space.
Together these facts turn the contraction into an actual boundary
identity.
\subsection{The residue map and its kernel}
Let $W_{\mathrm{fin}}$ be the subspace of elements whose root
denominators are bounded; equivalently, the element can be expressed
in a normalized basis at some level $h$ with all exponents in
$h^{-1}\Z$. It can still be an infinite convergent series. For
$w\in W_{\mathrm{fin}}$ at this level and
$p_h\in\mathcal P^{1/h}$ define
\begin{equation}
\lambda_h(w)(p_h)=
\res_{x_h,y_h}
\Tr_{B'^{1/h}/B^{1/h}}(w p_h\eta_h).
\label{eq:cutoff-residue-pairing}
\end{equation}
In logarithmic x-coordinates the residue extracts x-exponent zero and
y-exponent $-1$ in every $y_{j,h}$. This is also the ordinary formal
residue after replacing $d\log x_h$ by $dx_h/x_h$.
There are only finitely many nonzero terms with $I\leq M$ in any
$\kk$-series satisfying \cref{eq:cutoff-weight}, for every real $M$.
Indeed their weights are bounded above by $\max(LM,0)$, whereas a
weighted null series has only finitely many terms below any given
weight bound. This uses finiteness of $\kk$: a nonzero coefficient
has norm one. Applying the observation with the pole bounds for
$p_h$ and $\mathcal T_h$ shows that
\cref{eq:cutoff-residue-pairing} uses only finitely many terms of $w$
and finitely many coefficients of $p_h$. It is therefore a
well-defined continuous functional on $\mathcal P^{1/h}$.
Powering identifies $\mathcal P^{1/h}$ with $\mathcal P$ as a
compact $\kk$-vector space. Under this identification the map
between consecutive compact lattices is
\[
T_h:\mathcal P^{1/(h h_0)}\longrightarrow\mathcal P^{1/h},
\qquad T_h(v)=\bigl(S(v^{h h_0})\bigr)^{1/h}.
\]
The Cartier-residue identity gives
\begin{equation}
\lambda_{h h_0}(w)=T_h^\vee\lambda_h(w).
\label{eq:cutoff-residue-transition}
\end{equation}
For completeness, in one ordinary coordinate with $\eta=dx$, Cartier
takes $x^j$ to $x^{(j+1)/h_0-1}$ when the displayed exponent is an
integer and to zero otherwise. Pairing this with $x^I$ gives the same
coefficient as pairing $x^I$ at the next normalized root level with
the original monomial. With $d\log x$ the condition is divisibility
of $j$ by $h_0$ instead. Taking products of these coefficient
identities proves the assertion in several coordinates. Trace
commutes with the étale root transport, and multiplication by
$\theta_h$ gives \cref{eq:cutoff-residue-transition} for the volume
used here; this is the compatibility in
\cref{prop:trans-cartier}. Thus the $\lambda_h$ define a map
$\pi_{\mathrm{fin}}:W_{\mathrm{fin}}\to Q$.
\begin{proposition}[The discrete residue quotient]
\label{prop:cutoff-residue}
The finite-level pairings extend uniquely to an exact sequence of
$\kk[G]$-modules
\begin{equation}
0\longrightarrow W_+\longrightarrow W
\xrightarrow{\ \pi\ }Q\longrightarrow0.
\label{eq:cutoff-residue-sequence}
\end{equation}
The map $\pi$ is continuous on every complete coefficient step into
the discrete countable module $Q$, including on compact parameter
families. It is equivariant for the actual group actions on the
support and compact-dual models. All these assertions allow
arbitrary root denominators in $W$.
\end{proposition}
\begin{proof}
First work at a bounded root level $h$. In the normalized whole
basis, multiplication by \cref{eq:cutoff-trace-matrix} converts
\cref{eq:cutoff-residue-pairing} into the scalar residue test on each
basis coefficient. Testing against all elements of
$x_h^{-D_0}A^{1/h}$ detects every strictly negative-y monomial of this
product whose x-order is at most $D_0/h$. There is no undetected
smaller y-pole at this level: every positive $J_j$ in the root grid is
at least $1/h$. Thus
\begin{equation}
\lambda_h(w)=0
\quad\Longrightarrow\quad
\ord_x(w)>\frac{D_0-c}{h}
\quad\text{in the normalized basis at level }h.
\label{eq:cutoff-zero-test}
\end{equation}
Here one multiplies the detected product by $\mathcal T_h^{-1}$,
which loses at most $c/h$ in x-order. These are invertible matrices
on the negative-y quotient: their entries and those of their inverses
have no negative y-powers. Consequently projection to negative
y-powers does not invalidate their inverse identity. This justifies
using the inverse matrix in \cref{eq:cutoff-zero-test}.
Conversely, suppose that $w$ has x-order at least $\epsilon>0$ in
the normalized basis at level $h$. At a later level $h'$ the bound
is still at least $\epsilon$. The trace/volume product then has
x-order at least $\epsilon-c/h'$. If
$h'>(D_0+c)/\epsilon$, it pairs to zero with
$\mathcal P^{1/h'}$. In particular every bounded-root element of
$W_+$ maps to zero in $Q$. If a bounded-root element maps to zero in
$Q$, its functional is zero at some later level of the direct system;
\cref{eq:cutoff-zero-test,eq:cutoff-residue-margin} then put it in
$W_+$. We have proved
\begin{equation}
\ker(\pi_{\mathrm{fin}})=W_{\mathrm{fin}}\cap W_+.
\label{eq:cutoff-finite-kernel}
\end{equation}
To prove surjectivity, take a functional at any stage of
\cref{eq:cutoff-Q}. On the whole free lattice its finite coefficient
expression is represented by finite scalar principal parts. Applying
the inverse trace/volume matrix gives a bounded-root representative
$v$ for \cref{eq:cutoff-residue-pairing}; it lies in the whole Laurent
module because that matrix has a fixed x-pole bound and no negative
y-powers. Replace $v$ by $ev$. These two functionals agree after one
transpose transition: the image of the corresponding transfer lies
in $eB'$, where multiplication by $e$ is the identity. Thus $ev$
represents the same element of the colimit and belongs to
$W_{\mathrm{fin}}$. This argument uses the whole trace matrix and
only then projects by $e$; it does not specialize an idempotent to
the boundary or presume a free model for its component there.
We next extend the map to $W$. Express $w\in W$ on one fixed whole
normalized basis. Truncate to the finitely many terms of x-order
$I\leq M$, obtaining $v_0$. Let $c_e$ be a fixed x-pole bound for
the matrix of $e$ in that basis. Taking $M>c_e+1$ gives
\[
v=ev_0\in W_{\mathrm{fin}},\qquad
w-v=e(w-v_0)\in W_+.
\]
The finitely many terms of $v_0$ have a common root denominator, and
$e$ has a bounded root denominator at this fixed basis level, so the
first inclusion holds. Define $\pi(w)=\pi_{\mathrm{fin}}(v)$.
Any two such choices differ by a bounded-root element of $W_+$;
\cref{eq:cutoff-finite-kernel} proves independence of the choice.
If $\pi(w)=0$, the bounded-root representative $v$ belongs to $W_+$,
so $w$ also belongs to $W_+$. This proves exactness.
For continuity, fix a complete weighted step and a normalized basis.
A sufficiently small norm ball has all its nonzero monomials of
weight greater than some $a>0$. Such monomials necessarily have
$I>a/L$, because $w_{L,\delta}(I,J)\leq LI$ when $I\geq0$ and is
nonpositive when $I<0$. The ball is therefore contained in $W_+$.
The kernel of the linear map to discrete $Q$ is open in this step.
The same argument in supremum norms works for a compact parameter
space: only finitely many bounded-x monomials remain uniformly in
the parameter, and each retained $\kk$-coefficient is locally
constant. Its image in $Q$ is finite.
It remains to identify the group action, rather than just the kernel
as a vector space. Work first at finite root level, and put
$A_h=\kk[[x_h,y_h]]$, $\mathfrak m_h=(x_h,y_h)$, and
$\Omega_h=\widehat\Omega^r_{A_h/\kk}$.
Write $\alpha=\Tr(wp_h\eta_h)$ as an ordinary top form, including
the factor $x_h^{-1}$ from $d\log x_h$, with its negative-y
\v Cech convention and its ordered-coordinate signs.
Choose $N$ so that $x_h^N\alpha$ has nonnegative x-orders. Its
truncation modulo $x_h^N$ is a finite principal-part class
\[
\xi_N\in H^{r-1}_{(y_h)}(\Omega_h/x_h^N\Omega_h)
=H^{r-1}_{\mathfrak m_h}(\Omega_h/x_h^N\Omega_h).
\]
The equality holds because $x_h$ is nilpotent on the quotient.
The connecting map for multiplication by $x_h^N$ on $\Omega_h$
sends this class to the all-negative ordinary principal part of
$\alpha$ in $H^r_{\mathfrak m_h}(\Omega_h)$, with the coordinate
order fixing the \v Cech sign. This identifies the finite
truncation with an intrinsic local-cohomology class. If
$g(x_h)=u x_h$, the naturality square has $g$ on the source copy of
$\Omega_h$ and $u^{-N}g$ on the middle copy. Consequently the
connecting map sends $u^{-N}g\xi_N$ to the $g$-translate of the
class of $\alpha$, as required.
These maps are the maps on the finite support \v Cech model of
\cref{prop:laurent-model}. In particular a translation
$y_h\mapsto y_h+c(x_h)$ gives finite generalized-fraction
expansions modulo $x_h^N$, since $c(x_h)$ is nilpotent there.
The two-ended x-convention $(f_+,-f_-)$ ensures that multiplication
crossing x-order zero is ordinary Laurent multiplication.
For a convergent bounded-root expression, truncation above all fixed
x-pole bounds, including the group basis matrix bounds, changes
neither residue before or after the given action. Thus the same
naturality applies to every expression being paired.
The generalized-fraction transformation law and the independence of
regular parameters for formal residue on
$H^r_{\mathfrak m_h}(\Omega_h)$ hold also in characteristic $p$
\citep[Lemmas~(7.2)(b) and~(7.3), pp.~60--67]{lipmanResidues1984}.
Here $A_h$ is a complete regular local algebra over the perfect
field $\kk$ with residue field $\kk$, so all hypotheses of that
result hold. The finite étale trace is natural, the action preserves
$(x)$ and the whole lattice, and the transported volume is invariant
on the $e$-component. These facts give
\[
\lambda_h(gw)(p_h)=\lambda_h(w)(g^{-1}p_h)
\qquad(g\in G).
\]
This proves equivariance on bounded-root expressions and is compatible
with \cref{eq:cutoff-residue-transition}. Finite-root expressions
are dense after a complete-step enlargement. Both the group action
and $\pi$ are continuous into enlarged steps and the discrete
quotient by \cref{lem:laurent-action} and the preceding paragraph.
Passing to the limit proves equivariance on all of $W$. In particular
$W_+$ is $G$-stable. Its positive complete steps also satisfy the
uniform action condition of \cref{def:cts-steps}. Indeed, for a step
with x-gap $\epsilon$, pass to a later normalized basis $h'$.
The scalar substitutions preserve x-order by
\cref{eq:laurent-action-order}; the remaining group basis matrices
have one uniform pole bound $c_G/h'$, because they are root transports
of the matrices on the original whole model. Choose $h'$ with
$c_G/h'<\epsilon/2$. The entire compact group family then has x-gap
at least $\epsilon/2$, and \cref{lem:laurent-action} puts it
continuously into one common complete positive step. The same
argument applies to compact parameter families. Compact-envelope
integration from \cref{lem:cts-comparison} therefore defines the
completed group-ring action on $W_+$. The map $\pi$ commutes with
that action: approximate a distribution by finite group-ring sums
in a compact envelope and use continuity of $\pi$ into $Q$.
This proof uses finite principal-part residue
invariance; it does not presume a separate duality theorem for
completed functions at infinite root level.
\end{proof}
\subsection{Contraction and an open boundary subgroup}
The residue sequence already makes the homology of its kernel
countable. Indeed, take a resolution by finite free completed group-ring
modules in every degree, as in \cref{lem:cts-comparison}. Its coefficient
chain complex has terms $V^{a_i}$, with each $a_i$ finite, for a
coefficient module $V$. Thus \cref{eq:cutoff-residue-sequence} gives a
termwise exact sequence of chain complexes. The complex for the
countable module $Q$ is degreewise countable, whereas $H_i(G,W)$ is
finite by \cref{cor:laurent-finite}. The long exact sequence gives
\begin{equation}
H_i(G,W_+)\text{ is countable for every }i.
\label{eq:cutoff-positive-countable}
\end{equation}
We must strengthen this to vanishing. On a complete positive coefficient
step, the cycles form a Polish group, and the subgroup consisting of
actual boundaries has countable index by
\cref{eq:cutoff-positive-countable}. We will show that this subgroup
is analytic, so a Baire-category argument makes it open. Frobenius
contraction then puts an iterate of every cycle in that open subgroup;
inverse Frobenius supplies a primitive for the original cycle. We first
establish the contraction and the required openness criterion.
\begin{lemma}[Contraction in one complete positive step]
\label[lemma]{lem:cutoff-contraction}
For every integer $\nu\geq0$ and every tuple $w\in W_+^\nu$, there
are an integer $a_*\geq0$, a complete weighted step written in the
original whole basis, and
$\epsilon,\alpha>0$ such that all $\Phi^{a_*+a}w$ belong to the
closed subspace with x-order at least $\epsilon$, and
\begin{equation}
\|\Phi^{a_*+a}w\|\leq
\exp(-\alpha h_0^a)\quad(a\geq0).
\label{eq:cutoff-contraction}
\end{equation}
The statement applies without a bound on the root denominators of
the coefficient series.
\end{lemma}
\begin{proof}
The empty tuple is immediate. Otherwise, since the tuple is finite,
choose one normalized basis at level $h_0^{a_*}$ on which all
components have a common positive x-gap. Applying $\Phi^{a_*}$ clears this
\emph{basis} denominator. It need not clear the root denominators
in the series. In the original basis the resulting tuple $v$ still
has a positive x-gap, since all multiplication laws in $A'$ are
integral.
Choose a common weighted step $(L_1,\delta)$ for the finitely many
series of $v$, with $I\geq\epsilon>0$. Their original weights are
bounded below.
Increasing $L_1$ to $L$ adds $(L-L_1)I$ to every weight. Choose $L$
large enough that all nonzero terms now have weight at least
$\alpha>0$. They still form null series in this new step. Under
$h_0^a$-powering the coefficient exponents are multiplied by $h_0^a$,
so these weights are at least $\alpha h_0^a$. Each
$b_i^{h_0^a}$ expands on the original basis with coefficients in
$A$. These coefficients add nonnegative x- and y-powers;
projection to the strictly negative-y part can only discard terms
or improve the weight. Their coefficients have norm at most one.
This proves \cref{eq:cutoff-contraction}. The x-gap is multiplied
by $h_0^a$, hence remains at least $\epsilon$ in the same complete
step.
\end{proof}
\begin{lemma}[A countable-index analytic subgroup]
\label[lemma]{lem:cutoff-polish}
Let $Z$ be a Polish topological group and $B\subseteq Z$ an analytic
subgroup in the sense of descriptive set theory: $B$ is a continuous
image of a Polish space. If $Z/B$ is countable, then $B$ is open.
\end{lemma}
\begin{proof}
An analytic subset of a Polish space has the Baire property
\citep[Theorem~21.6]{kechris1995}. If $B$ were meagre, its countably
many cosets would make $Z$ meagre in itself, contrary to the Baire
theorem. Thus $B$ is nonmeagre. Pettis's theorem
\citep[Theorem~9.9]{kechris1995} says that the product of a
nonmeagre set with the Baire property and its inverse contains a
neighborhood of the identity. For a subgroup this product is $B$
itself, proving the assertion.
\end{proof}
\begin{lemma}
\label{lem:cutoff-positive-acyclic}
For the completed-resolution group homology of
\cref{sec:continuous},
\[
H_i(G,W_+)=0\qquad(i\geq0).
\]
\end{lemma}
\begin{proof}
Use the finite free resolution and the countability statement
\cref{eq:cutoff-positive-countable} above. We first construct the
complete cycle spaces to which \cref{lem:cutoff-polish} applies.
Take a normalized basis level, rational
weights $L>\delta>0$, and a rational positive cutoff
$\epsilon>0$. In the whole weighted null-series space require
x-order at least $\epsilon$ and the equation $ew=w$. The first
condition is a closed coordinate condition; the second is closed
because $e$ and the identity are continuous into a common enlarged
complete step. This gives a complete separable metrizable
$\kk$-vector space $E\subset W_+$. Separability follows from the
countable exponent index and finite coefficient field. These
spaces form a countable collection covering $W_+$: the basis levels
are countable, and rational weights and positive cutoffs can be
chosen cofinally. Each inclusion between two specified coefficient
steps is continuous into some common enlarged step.
Fix $i$ and one such $E$. The cycles
\[
Z_E=\{z\in E^{a_i}: dz=0\}
\]
form a closed subspace of a Polish group. In fact the differential
is continuous from this finite product into a common complete step
by \cref{lem:laurent-action,lem:cts-comparison}. Let
\[
B_E=Z_E\cap d(W_+^{a_{i+1}}).
\]
Its index in $Z_E$ is countable by
\cref{eq:cutoff-positive-countable}. It is analytic for the
following explicit reason. For each complete positive primitive
step $E'$, the set
\[
\{(z,u)\in Z_E\times(E')^{a_{i+1}}:du=z\}
\]
is closed: compare the two sides in a common enlarged complete
step. Projecting this closed subset of a Polish product onto
$Z_E$ gives an analytic set. There are countably many choices of
$E'$, and their projected union is exactly $B_E$. Thus $B_E$ is
an analytic subgroup, and \cref{lem:cutoff-polish} makes it open.
This argument does not require the global boundary image in $W_+$
to be closed or the inductive topology to be strict.
Now let $z$ be any cycle in $W_+^{a_i}$. Absolute Frobenius is
$\kk$-linear and $G$-equivariant. It commutes with the completed
group-ring differential: this holds for finite group-ring sums and
then for their convergent actions on the complete steps. Apply
\cref{lem:cutoff-contraction} and choose the rational weights and
cutoff within its bounds. The forward iterates after the initial
basis clearing lie in one $Z_E$ and tend to zero there. Since
$B_E$ is open, some iterate $\Phi^a z$ is $du$ with
$u\in W_+^{a_{i+1}}$. Both $\Phi$ and its inverse preserve $W_+$
and commute with $d$. Hence $z=d(\Phi^{-a}u)$. Every cycle
bounds, as required.
\end{proof}
\begin{theorem}[Finite stable transfer image]
\label{thm:cutoff-stable}
For every $i\geq0$ the compact vector space
$M_i=H^i(G,\mathcal P)$ satisfies
\begin{equation}
I_i:=\bigcap_{a\geq0}S^aM_i\quad\text{is finite}.
\label{eq:cutoff-stable}
\end{equation}
No uniform bound on its size as the prime, height, degree, or finite
marking level varies is asserted.
\end{theorem}
\begin{proof}
The preceding acyclicity and
\cref{eq:cutoff-residue-sequence} identify $H_i(G,Q)$ with
$H_i(G,W)$, hence make it finite. Compact/discrete duality and the
finite free resolution give
\[
H_i(G,Q)
=\colim_{S^\vee}H_i(G,\mathcal P^\vee)
=\colim_{S^\vee}M_i^\vee.
\]
Filtered colimits commute with kernels and cokernels of vector-space
maps, so no derived interchange is involved here. Dualizing gives
\[
H_i(G,Q)^\vee=\varprojlim_S M_i.
\]
This inverse limit is finite. Its projection to the first term has
image $I_i$. To check surjectivity onto that image description, note
that every $S^aM_i$ is compact. For $x\in I_i$, the nonempty compact
sets
\[
\{y\in S^aM_i:Sy=x\}
\]
are nested. Their intersection gives a preimage in $I_i$.
Thus $S:I_i\to I_i$ is surjective, and successive choices of
preimages in $I_i$ lift $x$ to the inverse limit. It follows that
$I_i$ is finite. We have used a surjection from the inverse limit
onto the stable image; we have not assumed them equal before proving
finiteness.
\end{proof}
\subsection{Compact power-series modules and localization}
The stable image is now finite in compact lattice cohomology. To pass
to the intersection of its images in localized cohomology, we will need
two additional inputs: next-height finiteness, which controls boundary
strips, and countability of a consecutive transfer-image quotient.
The next lemma isolates the compact algebra used in this passage.
\begin{lemma}
\label[lemma]{lem:cutoff-compact-operator}
Let $M$ be a profinite $\kk$-vector space and let $S:M\to M$ be a
continuous linear map. Assume that
$I=\bigcap_{a\geq0}S^aM$ and $M/SM$ are finite. Then $S$ is an
automorphism of $I$, and $V=M/I$ is a finitely generated
$\kk[[z]]$-module with $z$ acting by $S$. Its original topology is
the z-adic topology. The locally nilpotent subgroup
\[
T_S(M)=\bigcup_{a\geq0}\ker(S^a:M\to M)
\]
is finite and closed. In particular $\ker S$ is finite.
\end{lemma}
\begin{proof}
The compact preimage argument in the preceding proof gives
$S(I)=I$, and finiteness makes this restriction invertible. In
$V=M/I$ the nested compact subspaces $S^aV$ have zero intersection.
They shrink \emph{uniformly} to zero: for every neighborhood $O$
of zero there is an $a_0$ such that $S^aV\subset O$ for every
$a\geq a_0$. Otherwise the compact sets
$S^aV\cap(V\setminus O)$ would have nonempty intersection.
For $f=\sum_{j\geq0}c_jz^j$ define
\[
f v=\lim_{t\to\infty}\sum_{j=0}^{t-1}c_jS^jv.
\]
Every sufficiently late finite tail belongs to an arbitrarily
specified open linear subspace, uniformly for $v\in V$.
Completeness therefore supplies the limit. Polynomial module
identities pass to these uniform limits and give a continuous
$\kk[[z]]$-action.
Choose lifts $v_1,\ldots,v_s$ of a basis of the finite space
$V/SV=M/SM$. Given $v=v^{(0)}$, recursively choose coefficients
$c_{ij}\in\kk$ and $v^{(j+1)}\in V$ such that
\[
v^{(j)}=\sum_{i=1}^s c_{ij}v_i+Sv^{(j+1)}.
\]
After $t$ steps the error is $S^tv^{(t)}$, which tends uniformly
to zero. Thus
$v=\sum_i(\sum_jc_{ij}z^j)v_i$; the continuous map
$\kk[[z]]^s\to V$ is surjective. Each successive quotient
$S^jV/S^{j+1}V$ is an image of $V/SV$. Hence every $V/S^aV$ is
finite, and its compact kernel $S^aV$ is open. Uniform shrinking
makes these kernels a neighborhood basis, proving the topology
assertion.
The Noetherian module $V$ has a stabilizing ascending sequence
$\ker z\subseteq\ker z^2\subseteq\cdots$. Its union is a
finitely generated submodule killed by some $z^t$, hence finite over
the finite ring $\kk[[z]]/(z^t)$. The map from $T_S(M)$ to this
union is injective, since a locally nilpotent element of $I$ is
zero. Therefore $T_S(M)$ is finite and closed. In fact this map
is surjective: if $S^a x\in I$, subtract the unique element of $I$
with the same $S^a$-image to obtain a nilpotent lift. The contraction
and the power-series action in this argument concern $M/I$; they
are not asserted on the finite summand on which $S$ is invertible.
\end{proof}
Return to $M_i=H^i(G,\mathcal P)$ and set
\[
Y_i=H^i(G,B'),\qquad X_i=H^i(G,B_U).
\]
Let $j_i:M_i\to Y_i$ be localization and let
$f_i:M_i\to X_i$ be localization followed by projection by $e$.
For the remainder of this section assume the next-height finiteness
hypothesis of \cref{lem:mark-strips}. That lemma says that $j_i$
has countable kernel and cokernel for every fixed lattice shift.
It need not say this about $f_i$ before taking a positive transfer
image: the complementary component of $B'$ must first be removed.
For every $a\geq1$ there is a map
\begin{equation}
f_{i,a}:S^aM_i\longrightarrow S^aX_i
\quad\text{with countable kernel and cokernel}.
\label{eq:cutoff-image-comparison}
\end{equation}
Here is the verification. The map
$S^aM_i\to S^aY_i$ has kernel contained in $\ker j_i$.
Its cokernel is an image of $Y_i/j_i(M_i)$ under $S^a$, and is
therefore countable. For $a\geq1$, $S^aY_i$ lies in the
$e$-summand, where projection identifies it with $S^aX_i$.
This proves \cref{eq:cutoff-image-comparison} without imposing a
countable-kernel assertion on the uniterated projection.
\begin{proposition}[The compact localized intersection]
\label[proposition]{prop:cutoff-compact}
Fix $i\geq0$ and $N\geq1$. Suppose
\begin{equation}
S^NX_i/S^{N+1}X_i\quad\text{is countable}.
\label{eq:cutoff-consecutive-hypothesis}
\end{equation}
Then $S^NM_i/S^{N+1}M_i$ is finite, and
$(S^NM_i)/I_i$ is a finitely generated $\kk[[z]]$-module with
$z=S$. The operator $S$ on $S^NX_i$ has countable kernel and
cokernel. Moreover $\ker(f_i|_{S^NM_i})$ is finite and closed,
$f_i$ is injective on $I_i$, and
\begin{equation}
\bigcap_{a\geq0}\im(S^aM_i\longrightarrow X_i)
=f_i(I_i)\cong I_i.
\label{eq:cutoff-localized-intersection}
\end{equation}
In particular the intersection is finite. No topology on $X_i$
and no closed-image assertion for its cochain differential is
required.
\end{proposition}
\begin{proof}
Put $A_N=S^NM_i$, $Z_N=S^NX_i$, and $f=f_i|_{A_N}$.
The induced map
\[
A_N/SA_N\longrightarrow Z_N/SZ_N
\]
has countable kernel. Indeed, the subgroup represented by
$\{a\in A_N:f(a)\in SZ_N\}$ maps to
$SZ_N/f(SA_N)$, which is countable by
\cref{eq:cutoff-image-comparison} at $N+1$; the kernel of this
map is an image of $\ker f$, countable by the comparison at $N$.
Its image in $Z_N/SZ_N$ is countable by
\cref{eq:cutoff-consecutive-hypothesis}. Thus $A_N/SA_N$ is
countable. It is a compact Hausdorff group, because $SA_N$ is a
compact image and hence closed. A countable compact Hausdorff
group is finite: its countable cover by closed singletons, together
with Baire, forces a singleton to be open; the group is then
discrete and compact. This proves finiteness of $A_N/SA_N$.
The stable intersection for $S$ acting on $A_N$ is $I_i$.
Apply \cref{thm:cutoff-stable,lem:cutoff-compact-operator}.
This gives the asserted finite generation and makes both
$\ker(S|_{A_N})$ and $T_S(A_N)$ finite.
We first obtain countability of the kernel on $Z_N$ without using
closedness of $\ker f$. Write $Z_0=f(A_N)$ and
$C_N=Z_N/Z_0$, which is countable. An element of
$\ker(S|_{Z_0})$ lifts to an $a\in A_N$ with
$Sa\in\ker f$. The latter kernel is countable and each
nonempty fiber of $S:A_N\to A_N$ is finite. Consequently
$S^{-1}(\ker f)$, and hence $\ker(S|_{Z_0})$, is countable.
Mapping $\ker(S|_{Z_N})$ to $C_N$ proves its countability.
The cokernel is countable already by
\cref{eq:cutoff-consecutive-hypothesis}.
It remains to prove the stronger assertion about $\ker f$, for
which countability alone would not suffice. Let
$\alpha\in\ker f\subseteq S^NM_i$. Choose a
$\mathcal P$-valued cocycle $c$ such that $S^Nc$ represents
$\alpha$. Since $N\geq1$, this representative is already
$e$-supported after localization. If $i>0$, vanishing in $X_i$
supplies a bounded-pole primitive $b$ with
\[
db=S^Nc
\]
in the cochain complex for $B_U$, viewed inside that for $B'$.
The convention of \cref{lem:cts-exact,lem:cts-comparison} means
that this one primitive belongs to some whole lattice
$x^{-D}A'$ uniformly on its compact cochain parameters.
By \cref{eq:cutoff-eventual-integrality}, all sufficiently high
$S^ab$ are $\mathcal P$-valued. The chain-map identity gives
$d(S^ab)=S^a(S^Nc)$ there. Thus $S^a\alpha=0$ in $M_i$.
When $i=0$, vanishing of the already $e$-supported localized cocycle
means that the cocycle itself is zero, since
$\mathcal P\hookrightarrow B'$ is injective. This proves local
$S$-nilpotence of $\ker f$ in every degree. The exponent may
depend on its chosen bounded-pole primitive; no uniform exponent
was assumed.
We now have $\ker f\subseteq T_S(A_N)$, so $\ker f$ is finite
and closed. Its intersection with $I_i$ is zero, because $S$
acts invertibly on $I_i$. For an element $\xi$ belonging to all
the images in \cref{eq:cutoff-localized-intersection}, discard
the first $N$ terms and consider
\[
E_a=\{v\in S^aA_N:f(v)=\xi\},\qquad a\geq0.
\]
These sets are nonempty and nested. Each is a coset of
$\ker f\cap S^aA_N$, hence finite and closed in the compact
space $A_N$. Their intersection is nonempty. Any point in it
belongs to $I_i$ and maps to $\xi$. This proves the nontrivial
inclusion in \cref{eq:cutoff-localized-intersection}; the reverse
inclusion is immediate. It also explains why no Hausdorff topology
on localized cohomology was used.
\end{proof}
The sequence of implications is now available at every fixed allowed
marking level. The finite stable image comes from the analytic
\emph{transpose} quotient, whereas the final compact argument
concerns the original bounded-pole cochains. In particular none of
the arguments in this section identifies incomplete ordinary
cohomology on the open with the ordinary cohomology of its analytic
completion.
==== END Finite-generation-for-the-Kn-local-sphere//09-residue-cutoff.tex ====
==== BEGIN Finite-generation-for-the-Kn-local-sphere//10-pro-transfer.tex ====
\section{Pro-objects, finite extensions, and transfer countability}
\label{sec:pro-transfer}
We now pass from the finite stable transfer image to the cohomology of an
individual finite marking level. All coefficient fields in this section
are finite. In particular, a countable-dimensional coefficient space is
a countable set, and a finite-dimensional coefficient space is a finite
set. Both facts will be used.
Fix $1\leq m1$, the proof has two steps. First we establish
\cref{eq:pro-consecutive} in each degree with an exponent independent
of the sufficiently deep marking level. The compact comparison above then
makes $F^i_\nu$ finite. This does not yet control all of $X^i_\nu$:
a finite stable intersection alone places no bound on the part lost
under iteration.
The second step rules out an uncountable remainder. The uniform
finite-isotropy bound leaves only finitely many cohomological degrees.
If countability fails, choose the largest degree $b$ in which
uncountable groups persist at arbitrarily deep marking levels. Put
$d=(m-1)(n-m)$, the dimension of the translation distribution algebra.
We will construct a finite $d$-fold translation extension which, for one fixed
root order $h_*$ and every sufficiently deep level $U_\nu$, induces an
operation
\[
\varepsilon_\nu:
H^{b-d}_{\cts}(G,B_{U_\nu}^{1/h_*})\longrightarrow X^b_\nu
\]
with countable cokernel. If $b-d<0$, its source is zero and countability
already follows.
Otherwise the next-height boundary hypothesis gives a subspace of the
source with countable quotient whose classes have positive-order cocycle
representatives. A second fixed $d$-fold extension, now a self-extension
of the trivial translation coefficient, supplies a boundary operator
$\mathcal B$ on ordinary marked cochains. The high-transfer comparison
will identify its coinduced operations, after inclusion from the fixed
root source and transfer back to $B_{U_\nu}$, with nonzero scalar
multiples of $\varepsilon_\nu$. This equality will hold for
every high transfer at each sufficiently deep fixed level.
For a positive representative $w$, powering drives its order to
infinity, while the boundary operator $\mathcal B$ loses only a fixed
pole order at that level. Its high-power boundary representatives
therefore lie in $\mathcal P_\nu$. The factorization then puts the
fixed class $\varepsilon_\nu[w]$ in every sufficiently late compact
transfer image, hence in $F^b_\nu$. This intersection is finite. Since
the positive-representative subspace has countable quotient, the whole
image of $\varepsilon_\nu$ is countable. Its countable cokernel now
contradicts the choice of $b$.
The category introduced next records this obstruction by making
countable spaces zero while retaining each sufficiently deep marking
level. Exact pro-completion will first control the transfer images and
then construct the top extension operation. A finite equivariant Ext
comparison will put all its high-transfer factorizations on one common
tail of actual marking levels. When $m=1$, the splitting
$S\Fr^{\log_p h_0}=1$ replaces the positive-dimensional translation
algebra; that case is treated at the end of the section.
\subsection{The category recording a sufficiently deep tail}
Let $\mathcal V$ be the category of $\kk$-vector spaces and let
$\mathcal V_{\leq\aleph_0}$ be its full subcategory of
countable-dimensional spaces. This is a Serre subcategory: subspaces,
quotients, and extensions of countable-dimensional spaces are
countable-dimensional. Put
\[
\mathcal A_0=\mathcal V/\mathcal V_{\leq\aleph_0}.
\]
The quotient functor is exact. A vector space becomes zero in
$\mathcal A_0$ exactly when it is countable-dimensional, and a linear
map becomes an isomorphism exactly when its kernel and cokernel are
countable-dimensional.
Define $\mathcal A$ to be the category of tail families in
$\mathcal A_0$. Its objects are sequences $(Y_\nu)_{\nu\geq0}$ and
\[
\operatorname{Hom}_{\mathcal A}(Y,Z)
=\mathop{\operatorname{colim}}_{\nu_0}
\prod_{\nu\geq\nu_0}
\operatorname{Hom}_{\mathcal A_0}(Y_\nu,Z_\nu).
\]
Composition is componentwise after restricting to a common tail.
Kernels and cokernels are computed componentwise on a tail; a finite
diagram can always be placed on a common tail. These descriptions
prove that $\mathcal A$ is abelian. They also show that an object of
$\mathcal A$ is zero exactly when all its components vanish in
$\mathcal A_0$ after some index. In particular, an equality in
$\mathcal A$ that involves a fixed finite diagram means an equality
modulo countable-dimensional spaces at all sufficiently deep actual
levels. We do not replace these families by a direct limit of their
underlying vector spaces.
Suppose first that $m>1$, and set
\[
\Lambda=\kk[[D_1,\ldots,D_d]],\qquad d=(m-1)(n-m)>0,
\qquad \mathfrak m=(D_1,\ldots,D_d).
\]
Let $\mathcal C$ denote the abelian category of finite-length
$\Lambda$-modules. For $E\in\mathcal C$, the translation torsor
defines the associated coefficient bundle $V_{E,U_\nu}$ for all
sufficiently large $\nu$. Here a plain finite module can be given
trivial auxiliary action after shrinking $U_\nu$: its action factors
through a finite quotient of $\Lambda$, and a sufficiently deep
marking group acts trivially on that quotient. The same choice works
for every arrow in a fixed finite diagram. Consequently
\[
\mathcal C^j(E)
=\bigl(C^j_{\mathrm{cts}}(G,V_{E,U_\nu})\bigr)_\nu
\quad\text{and}\quad
T^i(E)=H^i\bigl(\mathcal C^\bullet(E)\bigr)
\]
are well-defined in $\mathcal A$, independently of omitted initial
terms. By \cref{lem:cts-exact,prop:trans-roots}, each $\mathcal C^j$
is an exact additive functor. Thus $T^\bullet$ has the long exact
sequences associated to short exact sequences in $\mathcal C$.
There is a uniform integer $c$ for which
\begin{equation}
\label{eq:pro-degree-bound}
T^i(E)=0\qquad(i>c, E\in\mathcal C),
\end{equation}
by \cref{prop:mark-finite-isotropy,prop:cts-isotropy-bound}.
As usual, all these functors vanish in negative cohomological degrees.
Choose $q_0$ as in \cref{prop:trans-roots}, with all powers used below
fixing $\kk$, and write $q_a=q_0^a$. The ideals
$(D_1^{q_a},\ldots,D_d^{q_a})$ are cofinal with the powers of
$\mathfrak m$. Put
\[
\Lambda_q=\Lambda/(D_1^q,\ldots,D_d^q).
\]
To identify the transition maps, use the perfect pairing of
\cref{sec:transfers} on the plain $\Lambda$-modules:
\[
\alpha_q:\Lambda_q\xrightarrow{\sim}\mathsf N_q,
\qquad
\alpha_q(a)(b)=
[D_1^{q-1}\cdots D_d^{q-1}](ab).
\]
Here the brackets extract the indicated monomial coefficient.
For allowed powers $q=st$, the regular quotient $\Lambda_q\to\Lambda_s$ becomes
under these pairings the coinduction of the translation augmentation
$\mathsf N_t\to\kk$ from the $s$-power subalgebra. Indeed, the
successive coefficient extractions select exponent
$(s-1)+s(t-1)=q-1$ in each variable. By
\cref{prop:trans-roots,prop:trans-cartier}, its coefficient-bundle map
is the corresponding root of a Cartier transfer. Thus the inverse
system of regular quotients records the classes that persist under
repeated transfer.
These pairings forget the auxiliary action; the natural actions on the
coinduced diagrams remain those of \cref{prop:trans-roots}. The
whole-diagram root identification, followed by powering on
coefficients, gives an isomorphism of inverse systems
\begin{equation}
\label{eq:pro-stationary}
\{T^i(\Lambda_{q_a})\}_{a\geq0}
\simeq
\{T^i(\kk)\xleftarrow{S}T^i(\kk)
\xleftarrow{S}T^i(\kk)\xleftarrow{S}\cdots\}.
\end{equation}
The maps on the left are induced by the quotient maps of $\Lambda$.
Choose the scalar identifications recursively along this sequence so
that its transition maps are exactly $S$. This is possible because
\cref{prop:trans-volume,prop:trans-cartier} make each discrepancy a
nonzero constant. Each fixed finite part of this comparison is
realized on a sufficiently deep marking tail. Thus
\cref{eq:pro-stationary} is an identity in
$\operatorname{Pro}(\mathcal A)$; it does not assert that the natural
actions on every $\mathsf N_q$ are simultaneously trivial at one
finite marking level.
\subsection{Exact completion and stabilization of the actual images}
We record the categorical facts with the precision needed for a
uniform stabilization index.
\begin{lemma}
\label[lemma]{lem:pro-constants}
For an abelian category $\mathcal B$, the constant objects in
$\operatorname{Pro}(\mathcal B)$ are closed under kernels and
cokernels of maps between them, and under extensions.
If a decreasing system of subobjects $J_a\subset X$ represents a
constant subobject $I\subset X$ in
$\operatorname{Pro}(\mathcal B)$, then $J_a=I$ for all sufficiently
large $a$.
\end{lemma}
\begin{proof}
The embedding by constant objects is fully faithful and exact, which
gives the kernel and cokernel statements. For extensions it is enough
to give the dual argument in $\operatorname{Ind}(\mathcal B)$.
Suppose
\[
0\longrightarrow A\longrightarrow E\longrightarrow B
\longrightarrow0
\]
is exact with $A$ and $B$ constant. Write $E$ as a filtered system
of objects $E_j$ of $\mathcal B$. The images of the maps
$E_j\to B$ are objects of $\mathcal B$, and their filtered colimit
is $B$. The defining Hom formula for ind-objects says that a map
from a constant object to a filtered colimit factors through one
term. Applied to $\operatorname{id}_B$, it shows that
$E_j\to B$ is an epimorphism for some $j$. Let
$K_j=\ker(E_j\to B)$. The induced map $K_j\to A$ is a map in
$\mathcal B$. The pushout of
$K_j\hookrightarrow E_j$ along $K_j\to A$ is $E$: the natural map
from that pushout has identity maps on the kernel $A$ and quotient
$B$, hence is an isomorphism. This pushout is a cokernel between
objects of $\mathcal B$, so is constant. Dualizing proves extension
closure in the pro-category.
For the second assertion, the morphism from the constant object $I$
to $\{J_a\}$ is a compatible family of maps $I\to J_a$. Since its
composite with $J_a\hookrightarrow X$ is the fixed inclusion, these
are inclusions identifying $I$ as a subobject of every $J_a$.
The system $\{J_a/I\}$ is pro-zero. Thus for any chosen $a$ some
later transition $J_b/I\to J_a/I$ is zero. This transition is
monic, so $J_b/I=0$. All still later subobjects contain $I$ and are
contained in $J_b=I$, proving the assertion.
\end{proof}
For a finitely generated $\Lambda$-module $L$, let
\[
\widehat L_{\mathrm{pro}}
=\{L/\mathfrak m^aL\}_{a\geq1}
\in\operatorname{Pro}(\mathcal C).
\]
This completion functor is exact. Indeed, for
$0\to L'\to L\to L''\to0$, the levelwise exact sequences use
$L'/(L'\cap\mathfrak m^aL)$ as their first terms. Artin--Rees
makes the filtrations $L'\cap\mathfrak m^aL$ and
$\mathfrak m^aL'$ cofinal, identifying these first terms with
$\widehat L'_{\mathrm{pro}}$.
This is the same Artin--Rees and cofinal-filtration argument that
proves exactness of ordinary completion in \cite[Tag 00MA]{stacks};
here it identifies the completed sequences as pro-objects.
An exact functor between abelian categories extends exactly to their
pro-categories: after a common reindexing, a finite diagram has
levelwise kernels and cokernels, and the functor preserves these.
Apply this to each $\mathcal C^j$. Define
\[
\overline{\mathcal C}^{\,\bullet}(L)
=\mathcal C^\bullet(\widehat L_{\mathrm{pro}}),
\qquad
\overline T^{\,i}(L)
=H^i\bigl(\overline{\mathcal C}^{\,\bullet}(L)\bigr).
\]
Thus
$\overline T^{\,i}(L)=\{T^i(L/\mathfrak m^aL)\}_a$ in
$\operatorname{Pro}(\mathcal A)$, and short exact sequences of
finitely generated modules give long exact sequences. If $L$ has
finite length, its completion is constant, so
$\overline T^{\,i}(L)$ is the constant object $T^i(L)$.
\begin{proposition}[Uniform image stabilization]
\label[proposition]{prop:pro-stabilization}
For every $i$, the pro-object $\overline T^{\,i}(\Lambda)$ is
constant, and its canonical projection to $T^i(\kk)$ is monic.
It is annihilated by $\mathfrak m$. Moreover, there is an integer
$N_i\geq1$, independent of the sufficiently deep marking level,
such that
\[
S^{N_i}X^i_\nu/S^{N_i+1}X^i_\nu
\quad\text{is countable-dimensional for all sufficiently large $\nu$}.
\]
\end{proposition}
\begin{proof}
We descend on $i$, starting above the bound in
\cref{eq:pro-degree-bound}. Assume the assertion of constancy has
been proved for $\overline T^{\,j}(\Lambda)$ with $j>i$.
The ideal $\mathfrak m$ has a finite resolution by finite free
$\Lambda$-modules, given by the positive part of the Koszul
resolution of $\kk$. Induction on resolution length shows that
$\overline T^{\,j}(L)$ is constant for every $j>i$ and every $L$
with a finite free resolution. The case of a free $L$ is the
descending induction hypothesis and finite additivity. For
$0\to L'\to F\to L\to0$ with $F$ finite free and $L'$ of shorter
resolution length, the long exact sequence gives
\begin{multline*}
0\longrightarrow
\coker\bigl(\overline T^{\,j}(L')\to\overline T^{\,j}(F)\bigr)
\longrightarrow\overline T^{\,j}(L)\\
\longrightarrow
\ker\bigl(\overline T^{\,j+1}(L')\to\overline T^{\,j+1}(F)\bigr)
\longrightarrow0.
\end{multline*}
For $j>i$ the outer terms are constant by the induction on length
and \cref{lem:pro-constants}; extension closure gives the middle
term. Taking $L=\mathfrak m$ and $j=i+1$ proves the required
constancy of $\overline T^{\,i+1}(\mathfrak m)$.
The exact sequence $0\to\mathfrak m\to\Lambda\to\kk\to0$
now identifies the image of
\[
\overline T^{\,i}(\Lambda)\longrightarrow T^i(\kk)
\]
with the kernel of a map between the two constant objects
$T^i(\kk)$ and $\overline T^{\,i+1}(\mathfrak m)$.
Call this constant subobject $I^i$. Under
\cref{eq:pro-stationary}, the image system is
\[
J_a=\operatorname{im}\bigl(S^a:T^i(\kk)\to T^i(\kk)\bigr),
\qquad J_{a+1}\subset J_a.
\]
The second part of \cref{lem:pro-constants} supplies one finite
$N_i$ with $J_a=I^i$ for all $a\geq N_i$. Increase $N_i$ to at
least one. Equality of these subobjects in $\mathcal A$ says
exactly that \cref{eq:pro-consecutive} holds for this $N_i$ at
every sufficiently deep actual level. Its depth is uniform
because only this one consecutive-image comparison is involved.
By \cref{prop:cutoff-compact}, the endomorphism induced by $S$ on
$J_{N_i}=I^i$ has countable kernel and cokernel at these levels.
It is therefore an automorphism in $\mathcal A$. Replacing the
stationary inverse system by its $N_i$th images gives an isomorphic
pro-object. This replacement has underlying object $I^i$ and
invertible transition $S|_{I^i}$, so is constant. Explicitly, its
map from the constant object $I^i$ to level $a$ is
$(S|_{I^i})^{-a}$ followed by inclusion. At the initial level the
projection is the inclusion $I^i\hookrightarrow T^i(\kk)$.
This proves the claimed monomorphism and completes the descending
induction.
Finally, multiplication by any element of $\mathfrak m$ followed
by $\Lambda\to\kk$ is zero. The resulting endomorphism of
$\overline T^{\,i}(\Lambda)$ has zero composite with the monic
projection just proved. It is zero. Thus $\mathfrak m$ annihilates
the pro-object.
\end{proof}
\subsection{Finite Yoneda extensions and the top Koszul operation}
We spell out why operations computed with completed free modules
can be realized by finite coefficient diagrams.
\begin{lemma}[Finite-length extension comparison]
\label[lemma]{lem:pro-finite-ext}
For finite-length $\Lambda$-modules $E,F$, the natural map
\[
\operatorname{Ext}^j_{\mathcal C}(E,F)
\longrightarrow \operatorname{Ext}^j_\Lambda(E,F)
\]
is an isomorphism for every $j$. Here the left side is Yoneda Ext:
its classes are represented by exact diagrams whose middle terms
all have finite length.
\end{lemma}
\begin{proof}
Let $\mathcal D$ be the category of $\mathfrak m$-power-torsion
$\Lambda$-modules. Every finitely generated submodule of an object
of $\mathcal D$ has finite length: finitely many generators are
killed by one power of $\mathfrak m$, and the corresponding
quotient ring is Artinian. Thus
$\mathcal D=\operatorname{Ind}(\mathcal C)$.
Finite endpoints have the same Yoneda extensions in these two
categories. One can see the finite realization directly. Starting
at the right endpoint of an extension in $\mathcal D$, choose
finitely many lifts of its generators, then take the finite-length
submodule that they generate. Its kernel is finite-length. Lift
generators of that kernel into the preceding middle term and
continue. At the last step include the whole left endpoint.
This constructs a finite-length subextension representing the
given class. The same construction can be made with a prescribed
finite subcomplex: include its terms before choosing the next
lifts. To check injectivity, take a finite Yoneda zigzag witnessing
equality. Its directed underlying path has no directed cycles.
Process its vertices in an order compatible with the arrows,
choosing a finite subextension that contains the images of every
already chosen predecessor; at a finite original vertex retain the
whole extension. All arrows then restrict to a finite zigzag.
Hence the map on Ext is both surjective and injective.
Equivalently, this is extension fullness of an abelian
category in its ind-completion
\cite[Theorem 2.2.1]{coulembier2020}.
For comparison with all $\Lambda$-modules, use that the
$\mathfrak m$-power-torsion submodule of an injective module is
itself injective over the Noetherian ring $\Lambda$
\cite[Lemma 47.3.9(2), Tag 08XW]{stacks}.
If $M\in\mathcal D$ embeds in an ordinary injective $I$, that
embedding factors through $I[\mathfrak m^\infty]$. Its cokernel
is still $\mathfrak m$-power torsion. Iterating this construction
gives an ordinary injective resolution entirely in $\mathcal D$.
Each term is also injective in the full abelian subcategory
$\mathcal D$, so the resolution computes both Ext groups, proving
$\operatorname{Ext}_{\mathcal D}^j(E,F)
=\operatorname{Ext}_\Lambda^j(E,F)$ and the lemma.
\end{proof}
An exact finite Yoneda diagram determines an operation on $T^\bullet$
by the composite of its connecting maps. Functoriality of long exact
sequences and invariance under comparisons make this operation depend
only on its Ext class.
\begin{proposition}[A surjective top operation]
\label[proposition]{prop:pro-top-operation}
Suppose $T^\bullet(\kk)$ is not zero, and let $b$ be its largest
nonzero degree. There is an allowed power index $s=q_0^{a_s}$ and a generator
\[
e_s\in\operatorname{Ext}^d_\Lambda(\mathsf N_s,\kk)
\]
whose operation is an epimorphism in $\mathcal A$:
\[
e_s:T^{b-d}(\mathsf N_s)\longrightarrow T^b(\kk).
\]
\end{proposition}
\begin{proof}
A composition series shows that $T^j(E)=0$ for every finite-length
$E$ and $j>b$. In particular
$\overline T^{\,b+1}(\mathfrak m)=0$. The exact sequence for
$0\to\mathfrak m\to\Lambda\to\kk\to0$, together with
\cref{prop:pro-stabilization}, gives an isomorphism
\begin{equation}
\label{eq:pro-top-identification}
Y:=\overline T^{\,b}(\Lambda)\xrightarrow{\ \sim\ }T^b(\kk).
\end{equation}
For an allowed index $s$, identify $\mathsf N_s$ with
$\Lambda_s$ as a plain $\Lambda$-module. Let $K_s^\bullet$
be the Koszul resolution on $D_1^s,\ldots,D_d^s$, in degrees
$[-d,0]$. Apply exact completion and then the exact cochain-term
functors $\mathcal C^j$ to this bounded complex. The augmented
horizontal rows remain exact, so the total complex computes the
constant object $\mathcal C^\bullet(\Lambda_s)$.
Its vertical-cohomology spectral sequence has
\[
E_1^{a,j}(s)=
\overline T^{\,j}(\Lambda)^{\binom d{-a}},
\qquad -d\leq a\leq0,
\qquad
E_1^{a,j}(s)\Longrightarrow T^{a+j}(\Lambda_s).
\]
The finite column interval and \cref{eq:pro-degree-bound} give a
finite filtration in every total degree. By
\cref{prop:pro-stabilization}, $\mathfrak m$ annihilates every
entry on this first page, so all first differentials vanish.
We compare these operations in the forward direction. Under the
pairings $\alpha_s$ above, the natural inclusion
$\mathsf N_s\to\mathsf N_{s'}$, dual to the regular quotient, is
\[
\Lambda_s\longrightarrow\Lambda_{s'},\qquad
1\longmapsto\prod_{j=1}^dD_j^{s'-s}
\qquad(s'>s).
\]
Its Koszul comparison preserves the top exterior term while making
every other column map vanish on vertical cohomology. To see this,
lift the displayed injection to a map
$K_s^\bullet\to K_{s'}^\bullet$.
On the exterior-basis summand indexed by
$I\subset\{1,\ldots,d\}$, that map is multiplication by
\[
\prod_{j\notin I}D_j^{s'-s}.
\]
The Koszul differential removes one index, and this formula
commutes with it because the missing factor changes $D_j^s$
to $D_j^{s'}$. On the first spectral-sequence page the comparison
is the identity in column $-d$ and zero in every other column.
The latter maps remain zero on every subsequent page.
There is no incoming differential at $(-d,b)$. Starting with
$E_2^{-d,b}=Y$, increase $s$ once for each possible page
$r=2,\ldots,d$. Inductively suppose the whole object $Y$
survives to page $r$ at the current index. At a larger index the
comparison remains the identity on this whole source. Naturality
of $d_r$ and the zero comparison on its target column show that
the outgoing $d_r$ at the larger index is zero on all of $Y$.
The earlier differentials are still zero for the same reason.
After these finitely many increases,
$E_\infty^{-d,b}=Y$. The leftmost-column edge of the finite
filtration is therefore an epimorphism
\[
T^{b-d}(\Lambda_s)\twoheadrightarrow Y.
\]
When $d=1$ there are no pages to eliminate, and the same conclusion
holds directly.
The edge followed by \cref{eq:pro-top-identification} is the
operation of the chain map
\[
K_s^\bullet\longrightarrow\Lambda[d]
\longrightarrow\kk[d]
\]
which projects the top exterior term onto $\Lambda$ and then
augments. Applying $\operatorname{Hom}_\Lambda(-,\kk)$ to
$K_s^\bullet$ gives zero differentials; the displayed map is
therefore a generator of
$\operatorname{Ext}^d_\Lambda(\Lambda_s,\kk)\simeq\kk$.
By \cref{lem:pro-finite-ext} it has a finite-length Yoneda
representative. To verify that this representative gives the
same operation, compare the two representing morphisms in the
bounded derived category of finitely generated $\Lambda$-modules,
using their finite free resolutions. They agree there because
they represent the same Ext class. Exact completion and the
exact cochain-term functors preserve quasi-isomorphisms of these
bounded complexes, as is seen by taking the exact horizontal
rows of their cones. Their induced operations thus agree after
totalization. This identifies the edge map with the operation
of the finite diagram and proves the proposition.
\end{proof}
\subsection{One auxiliary shrink for every high transfer}
We next establish the uniformity that is not supplied merely by
forming a germ of marking levels. Let $T$ be the translation group
scheme, so that finite rational $T$-representations are the objects
of $\mathcal C$. For a compact open subgroup $U\subset J$, let
$\mathcal R_U$ be the category of representations of $T\rtimes U$
which are rational for $T$ and discrete continuous for $U$.
The compatibility is the usual semidirect-product compatibility.
\begin{lemma}[Finite forgetting kernel]
\label[lemma]{lem:pro-common-shrink}
Let $U$ be a uniform pro-$p$ marking subgroup, and let $E,F$ be
finite objects of $\mathcal R_U$. Each group
$\operatorname{Ext}^j_{\mathcal R_U}(E,F)$ is finite. There is
one open subgroup $U'\subset U$ on which every element of the
kernel of
\[
\operatorname{Ext}^j_{\mathcal R_U}(E,F)
\longrightarrow\operatorname{Ext}^j_T(E,F)
\]
becomes zero.
\end{lemma}
\begin{proof}
There is an extension-descent spectral sequence
\begin{equation}
\label{eq:pro-equivariant-ext}
H^a_{\mathrm{cts}}\bigl(U,
\operatorname{Ext}^b_T(E,F)\bigr)
\Longrightarrow\operatorname{Ext}^{a+b}_{\mathcal R_U}(E,F).
\end{equation}
Here is a construction verifying the coefficient-category
requirements. Regard $U$ as the proconstant affine group scheme
whose coordinate algebra is the algebra of locally constant
$\kk$-valued functions on $U$. The underlying vector space of
the coordinate coalgebra of $T\rtimes U$ is
$\mathcal O(T)\otimes C_{\mathrm{lc}}(U,\kk)$.
A cofree representation restricts to a cofree $T$-representation:
the semidirect action is changed to ordinary translation on the
$T$ coordinate by conjugating that coordinate by the retained
$U$ coordinate. Its $T$-invariants are a cofree discrete
$U$-representation. Such $U$-representations are acyclic for
invariants, since the locally constant coinduction functor is
exact; lifts through a vector-space surjection are chosen on the
finite image of a locally constant function. Cofree resolutions
therefore give the spectral sequence for the composite of the
two invariant functors. Tensoring with the dual of the finite
representation $E$ identifies that spectral sequence with
\cref{eq:pro-equivariant-ext}.
By \cref{lem:pro-finite-ext}, the translation Ext groups are the
ordinary $\Lambda$-Ext groups of finite-length modules. The
Koszul resolution makes $\operatorname{Ext}^b_\Lambda(\kk,\kk)$
finite-dimensional and zero for $b>d$. Composition series
and the long exact sequences in each variable give the same
two conclusions for all finite-length endpoints.
Their induced $U$-actions are discrete continuous. Indeed a
finite Yoneda representative of a translation Ext class becomes
equivariant after shrinking $U$ to act trivially on its finite
endpoints and on the finite translation quotient through which
its middle terms act; give those middle terms trivial auxiliary
action. This open subgroup fixes the class. Finite-type
resolutions for the analytic group $U$ then make each group on the left of
\cref{eq:pro-equivariant-ext} finite-dimensional. Only finitely
many terms contribute in a fixed total degree. The abutment is
therefore finite-dimensional over the finite field $\kk$, hence
is a finite set.
Every representation of the indicated coalgebra is a union of
finite-dimensional subrepresentations. As in the finite
subdiagram construction in \cref{lem:pro-finite-ext}, an
extension with finite endpoints, and any Yoneda comparison
between such extensions, can be realized by finite diagrams.
Fix a class in the displayed forgetting kernel. Choose a
finite equivariant diagram representing it. Its underlying
$T$-extension is zero, so there is a finite $T$-linear Yoneda
comparison with a representative of zero. Shrink $U$ so that
it acts trivially on all the finite modules of the original
diagram. Shrink further so that its action on the finite
translation quotients through which the comparison modules act
is trivial. Give those comparison modules trivial auxiliary
action. Every comparison arrow is then equivariant, and the
class has become zero. Finally the forgetting kernel is a
finite set. Intersect the finitely many open subgroups just
obtained for its elements. This one intersection kills the
whole kernel. A sufficiently deep normal product congruence
subgroup is contained in it.
\end{proof}
At a fixed marking level $U$, finite diagrams with their given
$T\rtimes U$-actions descend without trivializing those actions
at $U$. Indeed, choose $\ell$ through which their translation
actions factor and a normal open $U'\subset U$ fixing both
$T/[p^\ell]T$ and every term. The subgroup
$[p^\ell]T\rtimes U'$ is normal in $T\rtimes U$: the translation
subgroup is $U$-stable, $U'$ is normal in $U$, and $U'$ acts
trivially on $T/[p^\ell]T$. The quotient of the full marked
lift torsor by $[p^\ell]T\rtimes U'$ is a torsor under the
finite group scheme
$\bigl(T/[p^\ell]T\bigr)\rtimes(U/U')$ over $\Spec B_U$,
by \cref{sec:finite-markings,prop:trans-roots}.
It is therefore a finite faithfully flat cover of that fixed base.
Here $U'$ specifies a cover over $B_U$.
Faithfully flat descent of the vector-space diagram tensored
with that cover gives its finite locally free associated bundles,
arrows, and exactness over $B_U$, with the commuting $G$-action.
This applies also to finite equivariant Yoneda comparisons.
Hence equality in equivariant Ext gives equality of the induced
operations on the actual cohomology of the associated bundles
at that level. Restriction to any smaller $U$ preserves it.
\begin{lemma}[A fixed extension through all transfers]
\label[lemma]{lem:pro-high-transfer}
Fix the index $s$ and generator $e_s$ of
\cref{prop:pro-top-operation}, and choose a generator
$e'_0\in\operatorname{Ext}^d_\Lambda(\kk,\kk)$.
There is one sufficiently deep marking subgroup $U_*$ such
that for every allowed $q\geq s$ the composite
\begin{equation}
\label{eq:pro-composite-extension}
\mathsf N_s\longrightarrow\mathsf N_q
\xrightarrow{\operatorname{Coind}_q(e'_0)}
\mathsf N_q[d]\longrightarrow\kk[d]
\end{equation}
equals a nonzero scalar multiple of $e_s$ in the equivariant
Ext group for $T\rtimes U_*$. The first and last maps use the
natural auxiliary actions, which are retained for every $q$.
\end{lemma}
\begin{proof}
Choose finite Yoneda diagrams for $e_s$ and $e'_0$.
After one initial shrink $U_0$, their plain module diagrams
are equivariant with trivial auxiliary actions, agreeing with
the natural action at the fixed endpoint $\mathsf N_s$.
The power-subalgebra identification commutes with marking
changes by \cref{prop:trans-roots}, so coinduction gives
equivariant diagrams for every $q$ without making the action
on $\mathsf N_q$ trivial. The natural inclusion
$\mathsf N_s\to\mathsf N_q$ is equivariant. The space of
translation maps $\mathsf N_q\to\kk$ is one-dimensional;
the pro-$p$ group $U_0$ acts trivially on this line because
$\kk^\times$ has order prime to $p$. Choose a nonzero map
on that line for the last arrow.
After forgetting $U_0$, the composite in
\cref{eq:pro-composite-extension} is a generator. This can
be checked directly on the power-subalgebra free pairing.
With
$\Lambda^{(q)}=\kk[[D_1^q,\ldots,D_d^q]]$, the coefficient
of $\prod D_i^{q-1}$ gives the perfect pairing identifying
coinduction from $\Lambda^{(q)}$ with extension of scalars.
Extension of scalars carries the Koszul representative of
$e'_0$ to the top projection in the Koszul resolution on
$D_1^q,\ldots,D_d^q$. Under the regular-module
identifications, the inclusion from the smaller block is
multiplication by $\prod D_i^{q-s}$ up to a unit. The
Koszul comparison written in the proof of
\cref{prop:pro-top-operation} has top coefficient one.
Following with augmentation therefore leaves a nonzero top
coefficient in $\kk$. Changes in the perfect-pairing
generators only multiply that coefficient by a unit, whose
augmentation is nonzero. Thus the ordinary Ext class is
$c_qe_s$ for some $c_q\in\kk^\times$.
Subtract $c_qe_s$ from each composite, now in the fixed group
$\operatorname{Ext}^d_{\mathcal R_{U_0}}(\mathsf N_s,\kk)$.
All differences lie in its forgetting kernel. Apply
\cref{lem:pro-common-shrink} to this fixed pair of endpoints.
One subgroup $U_*$ kills the entire kernel, and hence every
difference, independently of $q$.
\end{proof}
\subsection{The fixed boundary estimate and the contradiction}
We make explicit the cocycle estimate used after the common shrink.
Fix a marking level $U\subset U_*$ and one finite Yoneda diagram
for $e'_0$. Applying its associated-bundle functor gives an exact
diagram of finite locally free modules over the affine ring $B_U$.
Each successive surjection in that diagram has a $B_U$-linear
section, since its quotient is finite projective. Choose such
sections once. Successively lifting a cocycle by these sections
and taking group differentials gives a boundary operator
\[
\mathcal B:
Z^j_{\mathrm{cts}}(G,B_U)
\longrightarrow Z^{j+d}_{\mathrm{cts}}(G,B_U)
\]
representing $e'_0$ on cohomology. It is an additive
$\kk$-linear operator; it need not be a morphism of
$B_U$-modules.
There is a constant $C_U$ such that $\mathcal B$ loses at most
$C_U$ of whole-lattice $x$-order, in every one of the bounded
degrees used below. To verify the assertion, realize the finitely
many bundles as summands of finite free modules and choose
finitely many whole lattices in these realizations. Every chosen
section is a finite matrix with entries having bounded poles.
The compact group action has a uniform bound on each of these
lattices. Moreover $g(x)/x$ is an integral unit, so shifting a
lattice by $x^a$ changes none of these bounds. A group
differential is a finite sum of action and face maps; hence
it loses at most a fixed additional pole order. Adding the
losses of the finitely many sections and differentials gives
$C_U$. Continuity of these operations on bounded-step
cochains follows from \cref{lem:cts-exact,lem:cts-comparison}.
For $q=q_0^a\geq s$, put $h=q^{m-1}$.
The entire-diagram identity in \cref{prop:trans-roots} transports
these fixed sections to the coinduced diagram. Thus
\cref{lem:pro-high-transfer} yields, for a cocycle $w$ at the
fixed root level $h_s=s^{m-1}$,
\begin{equation}
\label{eq:pro-boundary-transfer}
e_s[w]
= c_{q,U}^{-1}
S^a\bigl[\mathcal B(w^h)\bigr],
\qquad c_{q,U}\in\kk^\times.
\end{equation}
This is equality in the actual group $H^{j+d}(G,B_U)$.
Here $w$ is first included from $B_U^{1/h_s}$ into
$B_U^{1/h}$, and powering identifies the latter root
coefficient diagram with the original one. Since $h$ fixes
$\kk$ and commutes with $G$, $w^h$ is an ordinary cocycle.
The transfer after taking the boundary is $S^a$ under the
same powering identification. In particular the bound on
the right of \cref{eq:pro-boundary-transfer} is the bound
for the one fixed operator $\mathcal B$, not a new bound
for each increasingly large coinduced diagram.
We also need positive representatives in the source. For any
fixed integer $L>0$, \cref{lem:mark-strips} says that the image
of
\[
H^j_{\mathrm{cts}}(G,x^LA')\longrightarrow
H^j_{\mathrm{cts}}(G,B_U)
\]
has countable cokernel; the map includes the whole model and
then projects by $e$. The idempotent has a fixed pole cost.
Powering by $h_s$ is a $\kk$-linear, $G$-equivariant
isomorphism from $B_U^{1/h_s}$ to $B_U$. Choose $L$ beyond
the idempotent pole cost and pull the preceding image back
under this isomorphism. We obtain a subspace
\begin{equation}
\label{eq:pro-positive-source}
Z_U^j\subset H^j_{\mathrm{cts}}(G,B_U^{1/h_s})
\end{equation}
with countable quotient, whose classes have cocycle
representatives of strictly positive $x$-order on the
normalized root basis. Increasing $L$ prescribes any fixed
positive lower bound on that order. Whole-lattice
representatives are used before projection, so this assertion
does not specialize the idempotent across the boundary.
\begin{proof}[Proof of \cref{thm:pro-countability} for $m>1$]
If all $T^i(\kk)$ vanish, their finitely many potentially
nonzero degrees in \cref{eq:pro-degree-bound} have a common
vanishing tail, which is the desired conclusion. Otherwise
choose the largest nonzero degree $b$ and the epimorphism
$e_s$ from \cref{prop:pro-top-operation}.
If $b-d<0$, its source is zero and already contradicts
$T^b(\kk)\ne0$. We may therefore assume $j=b-d\geq0$.
Shrink the marking tail so that
\cref{lem:pro-high-transfer} holds and the consecutive-image
conclusion of \cref{prop:pro-stabilization} holds in degree
$b$. Fix any one level $U=U_\nu$ in this tail. The set
$F^b_\nu$ of \cref{eq:pro-finite-intersection} is finite.
Take a class in the positive subspace
\cref{eq:pro-positive-source} and a cocycle representative
$w$ as described there. If its positive order is at least
$\epsilon>0$, its $h$th powers have whole-basis order tending
to positive infinity as $h=q^{m-1}$ increases. Indeed first
power out the fixed root denominator $h_s$. The resulting
whole finite model has integral multiplication laws, so
further Frobenius powers multiply the lower order bound;
the fixed projection and basis changes contribute only their
fixed pole costs. The estimate for $\mathcal B$ therefore
puts $\mathcal B(w^h)$ in $\mathcal P_\nu$ for all
sufficiently large $a$. Regard this cochain in the whole
localized model through $B_U=eB'\subset B'$. Its differential
vanishes there because it vanishes in $B_U$. Since
$\mathcal P_\nu$ is $G$-stable and
$\mathcal P_\nu\hookrightarrow B'$ is injective, it is a
$\mathcal P_\nu$-valued cocycle.
By \cref{eq:pro-boundary-transfer}, the fixed class $e_s[w]$
then belongs to
\[
\operatorname{im}\bigl(S^aM^b_\nu\to X^b_\nu\bigr)
\]
for every sufficiently large $a$. Multiplication by the
nonzero constant in that equation does not change this
subspace. These image subspaces are decreasing, so membership
in every sufficiently late one implies membership in their
entire intersection $F^b_\nu$. The threshold may depend on
$w$; no uniform threshold over all cocycles is needed.
Thus $e_s$ maps $Z_U^j$ into a finite-dimensional space.
The quotient of its source by $Z_U^j$ is countable-dimensional,
so the whole image of $e_s$ at this fixed level is
countable-dimensional. This holds at every level in the
chosen tail. Its morphism in $\mathcal A$ is therefore zero.
It was an epimorphism onto the nonzero object $T^b(\kk)$,
a contradiction. Hence all $T^i(\kk)$ vanish, and the
uniform degree bound gives one common tail for all degrees.
\end{proof}
\subsection{The multiplicative-type case}
\begin{proof}[Proof of \cref{thm:pro-countability} for $m=1$]
By \cref{prop:trans-cartier}, the normalized transfer satisfies
\[
S\Fr^{\log_p h_0}=1
\]
on the open coefficient algebra and on its group cochains.
It is therefore surjective on every $X^i_\nu$. In
particular \cref{eq:pro-consecutive} holds, and
\cref{eq:pro-finite-intersection} gives a finite intersection
$F^i_\nu$ at each sufficiently deep marking level.
Choose a sufficiently positive whole-lattice shift $x^LA'$,
with $L$ larger than the fixed projection pole cost. The
image of its cohomology in $X^i_\nu$ has countable cokernel,
by \cref{lem:mark-strips}. If a class $z$ is represented
by a projected cocycle from this lattice, its iterated
Frobenius powers are integral in the whole model after
projection: their order grows, while the idempotent and basis
costs are fixed. They consequently lie in $\mathcal P_\nu$
for every sufficiently large power. The identity splitting
Frobenius gives
\[
[z]=S^a\bigl[z^{h_0^a}\bigr]
\]
in the actual open cohomology. As before, the image
subspaces are decreasing, so this class belongs to
$F^i_\nu$. The image of the positive-lattice cohomology is
therefore finite; its cokernel is countable. Hence
$X^i_\nu$ is countable. The uniform cohomological bound
and the finitely many required choices give a common
sufficiently deep tail for all degrees.
\end{proof}
==== END Finite-generation-for-the-Kn-local-sphere//10-pro-transfer.tex ====
==== BEGIN Finite-generation-for-the-Kn-local-sphere//11-coefficient-finiteness.tex ====
\section{Finiteness of the compact coefficient cohomology}
\label{sec:coefficients}
We now close the induction on the height strata. Throughout this section
$p$ and $n$ are fixed, $G=P_n$, and $\kk$ is a finite field containing the
fields of definition used in the finite marking constructions. Write
\[
A_m=\kk[[u_m,\ldots,u_{n-1}]],\qquad 1\leq m\leq n,
\]
so that $A_n=\kk$. The coefficient class is that of
\Cref{def:mark-coefficients}: integer powers of the periodicity line,
whole finite division-tuple algebras with the permitted Frobenius powers,
and their finite tensor products, together with the stated closure under
finite sums, summands, and finite filtrations. All coefficients over
$A_m$ carry their compact topology.
\begin{theorem}\label{thm:coeff-finite}
For every $1\leq m\leq n$, every coefficient module $M$ in
\Cref{def:mark-coefficients} over $A_m$, and every $i\geq0$, the group
\[
H^i_{\cts}(P_n,M)
\]
is finite. In particular, this holds for every integer periodicity twist
of $A_m$.
\end{theorem}
The proof uses countability on the open stratum and compactness on the
closed formal neighborhood. We first supply the coefficient and descent
steps that connect these two statements. For $m1$. The distribution algebra is
\[
\Lambda=\kk[[D_1,\ldots,D_d]],\qquad d=(m-1)r,
\]
with maximal ideal $\mathfrak m=(D_1,\ldots,D_d)$, as in
\Cref{prop:trans-roots}. A finite translation representation is a
finite-length continuous $\Lambda$-module. Its finite filtration
\[
E\supseteq\mathfrak mE\supseteq\mathfrak m^2E
\supseteq\cdots\supseteq0
\]
has quotients that are finite direct sums of the trivial representation
$\kk$. Having retained this finite diagram at the chosen marking level,
its associated filtration has quotients $B_U^{\oplus a}$ with their
ordinary $G$-actions. Countability of their cohomology and the long exact
sequences of the filtration give countability of
$H^i_{\cts}(G,V_E)$ in every degree.
For $m=1$, the translation group is of multiplicative type. Choose
$H$ from the full cofinal sequence of finite generator-lift quotients,
deep enough that $E$ factors through $H$. Thus its torsor is the full
root algebra of \Cref{prop:mark-roots}, rather than an intermediate
subalgebra of that root extension. Its
distribution algebra
\[
R_H=\mathcal O(H)^\vee=\mathcal O(H^D)
\]
is finite \'etale over $\kk$, because the Cartier dual $H^D$ of a finite
multiplicative-type group is \'etale. Every finite $R_H$-module is
therefore a direct summand of $R_H^{\oplus a}$ for some $a$.
The perfect trace pairing of the finite \'etale algebra identifies
$R_H$ with $R_H^\vee=\mathcal O(H)$ as $R_H$-modules. Thus $E$ is a
direct summand of a finite sum of regular function representations.
This argument works over $\kk$ itself and includes quotients whose
order is divisible by $p$.
For the general semisimplicity statement over the ground field, see
\citet[Theorem~12.30, pp.~241--242]{milne2017}.
Shrink $U$ so that the splitting maps of this finite diagram descend as well.
The associated bundle of such a regular representation is the function
algebra of the corresponding finite lift torsor. By
\Cref{prop:mark-roots} and \eqref{eq:trans-full-torsor}, after enlarging
the level it is
\[
B_U^{1/h},\qquad h=p^a.
\]
The exponent may be chosen to fix $\kk$. Powering gives an additive,
$G$-equivariant homeomorphism
\begin{equation}\label{eq:coeff-root-powering}
B_U^{1/h}\longrightarrow B_U,\qquad z\longmapsto z^h.
\end{equation}
For the bounded-pole topology, this follows either from the finite root
coordinates or by multiplying every root pole bound and parameter order
by $h$; the inverse rescales those bounds. Hence powering identifies
the continuous cochain complexes as additive complexes. It is also
$\kk$-linear for the chosen exponents. It follows that each regular
block, and then its finite sums and summands, has countable cohomology.
All choices involve finitely many levels and finite diagrams. They persist on a
cofinal tail, where \Cref{thm:pro-countability} also applies. This proves
the assertion in both cases.
\end{proof}
\begin{lemma}\label[lemma]{lem:coeff-finite-descent}
Let $M_B$ be a finite locally free $B$-module with the coefficient action
of $G$, and let $U\triangleleft J$ be a finite marking level. If
\[
H^i_{\cts}(G,B_U\otimes_B M_B)
\]
is countable for every $i\geq0$, then $H^i_{\cts}(G,M_B)$ is countable for
every $i\geq0$. The order of $J/U$ need not be invertible in $\kk$.
\end{lemma}
\begin{proof}
Put $H=J/U$ and $N=B_U\otimes_B M_B$. The $G$- and $H$-actions on $N$
commute. Finite \'etale torsor descent identifies the augmented Amitsur
complex with the finite-group cochain resolution
\begin{equation}\label{eq:coeff-marking-amitsur}
M_B\longrightarrow N\longrightarrow C^1(H,N)
\longrightarrow C^2(H,N)\longrightarrow\cdots,
\end{equation}
where the displayed $N$ is in group-cochain degree zero. This augmented
complex is exact. For completeness, after faithfully flat base change
to $B_U$ the torsor becomes the trivial $H$-torsor and its augmented
complex has the usual extra-degeneracy contraction. Exactness therefore
holds before base change as well.
It also holds with the required continuous $G$-cochain parameters.
To make the topology explicit, choose
$\tau\in B_U$ with $\sum_{h\in H}h(\tau)=1$. Such an element exists:
the torsor trace is surjective after the same faithfully flat base
change, so its cokernel vanishes over $B$. The $B$-linear map
\[
\lambda:B_U\longrightarrow B,\qquad
\lambda(z)=\Tr_{B_U/B}(\tau z)
\]
satisfies $\lambda(1)=1$. Applying $\lambda$ to the first algebra
factor contracts the augmented Amitsur complex; the insert-unit
differential gives the contraction identity directly. These are
finite matrices over $B$ on the fixed finite locally free terms, so
they send each lattice to a bounded pole shift and are continuous
there. The contraction need not commute with $G$: exactness of each
row after applying continuous cochains is what is needed. Thus applying $C^a_{\cts}(G,-)$ to
\eqref{eq:coeff-marking-amitsur} remains exact for every $a$.
The first-quadrant double complex
\[
C^a_{\cts}\bigl(G,C^b(H,N)\bigr)
\]
therefore computes $H^*_{\cts}(G,M_B)$, and its other spectral sequence is
\begin{equation}\label{eq:coeff-marking-spectral}
H^b\bigl(H,H^a_{\cts}(G,N)\bigr)
\ \Longrightarrow\ H^{a+b}_{\cts}(G,M_B).
\end{equation}
Finite $H$-cochains are finite products. Their cohomology on a countable
module is countable, regardless of divisibility of $|H|$ by $p$.
Every total-degree diagonal of \eqref{eq:coeff-marking-spectral} is
finite, so its abutment is countable. This proves the claim.
\end{proof}
\begin{proof}[Proof of \Cref{thm:coeff-finite}]
Tensoring finite free modules preserves exact filtrations and retracts,
and a tensor product of basic coefficients is basic. Induction on the
finite constructions in \Cref{def:mark-coefficients} therefore reduces
the asserted closure properties to finite filtrations and retracts.
We induct downwards on $m$. At $m=n$, every basic coefficient is a
finite-dimensional vector space over the finite field $\kk$. A
finite-type projective resolution for $G$ computes its cohomology by a
complex whose term in each degree is a summand of a finite power of this
finite coefficient module; see \Cref{lem:cts-comparison}. Each
cohomology group is therefore finite. This uses finiteness of the
resolution in each degree, not finite cohomological dimension of $G$.
Finite sums, summands, and finite filtrations preserve the conclusion.
Now let $mN$.
For fixed $p,n$, these integers may be chosen independently of $Y$ and
of the internal degree.
These assertions are the $k=n$ case of
\citet[Theorem~4.6 and Proposition~4.13]{heard2023}; the identification
with the $K(n)$-local $E_n$-Adams spectral sequence is made in
\citet[Remark~4.14]{heard2023}. The descendability statement follows
from the Hopkins--Ravenel smash product theorem and its preservation
under localization, as in \citet[Theorem~4.18 and
Proposition~10.10]{mathew2016}; the finite-page vanishing and convergence
are \citet[Corollary~4.4]{mathew2016}. The fixed-point construction and
continuous-cohomology comparison are
\citet[Theorem~1\textup{(iii)--(iv)} and Appendix~A]{devinatzHopkins2004}.
None of these statements imposes a lower bound on $p$ relative to $n$.
Taking $Y=S/p$, the resulting spectral sequence is
\begin{equation}\label{eq:sphere-modp-descent}
E_2^{s,t}
=H^s_{\cts}\bigl(\mathbb G_n,\pi_t(E_n/p)\bigr)
\ \Longrightarrow\
\pi_{t-s}L_{K(n)}(S/p).
\end{equation}
Here $S/p$ is the finite Moore spectrum. Thus the usual continuous
Amitsur comparison is compatible with smashing by $S/p$; equivalently,
apply the finite-dual form of
\citet[Theorem~1\textup{(iv)}]{devinatzHopkins2004} to $D(S/p)$.
This gives the indicated coefficient module, since $E_n$ is even and
$p$ is injective on its homotopy. No commutative multiplication on the
Moore spectrum is required.
\begin{proposition}\label[proposition]{prop:sphere-modp}
For every prime $p$, every $n\geq1$, and every $j\in\mathbb Z$, the group
\[
\pi_jL_{K(n)}(S/p)
\]
is finite.
\end{proposition}
\begin{proof}
Every entry on the second page of \eqref{eq:sphere-modp-descent} is finite
by \Cref{cor:coeff-morava}. The entries on all later pages are
subquotients of those entries. Choose $R,N$ as in the descent theorem.
Only $0\leq s\leq N$ can contribute to the limiting page, and the entries
contributing to the stem $j$ have $t=j+s$. There are thus only finitely
many finite limiting entries in that stem. Strong convergence supplies
a separated exhaustive filtration of the abutment. Above filtration
$N$, all successive quotients vanish, so that tail is constant;
separatedness makes the constant tail zero. The remaining filtration
is finite, with finite successive quotients, so the abutment is finite. The same argument covers negative
$j$, and no evaluation or splitting of additive extensions is needed.
\end{proof}
\subsection{Finite power cofibers and integral recovery}
The mod-$p$ criterion for finite type appears for invertible
$K(2)$-local spectra in \citet[Proposition~3.1]{liFiniteType2021}.
We give the derived-complete form needed here, including the compact
Nakayama step. The argument applies in all integer degrees and imposes
no connectivity hypothesis.
For any spectrum $X$ and integer $a\geq1$, write
$X/p^a=\operatorname{cofib}(p^a:X\to X)$, with the quotient transition
maps $X/p^{a+1}\to X/p^a$. We use derived $p$-completeness in the form
\[
X\simeq\operatorname*{holim}_a X/p^a.
\]
This formulation does not assume ordinary completeness of its individual
homotopy groups.
\begin{lemma}\label[lemma]{lem:sphere-completion}
Let $X$ be a derived $p$-complete spectrum. If $\pi_j(X/p)$ is finite
for every $j\in\mathbb Z$, then $\pi_jX$ is finitely generated over
$\Zp$ for every $j\in\mathbb Z$. Conversely, finite generation of all
$\pi_jX$ over $\Zp$ implies finiteness of all $\pi_j(X/p)$.
\end{lemma}
\begin{proof}
The cofiber exact sequence gives, for every $j$,
\begin{equation}\label{eq:sphere-cofiber-short}
0\longrightarrow \pi_jX/p\pi_jX
\longrightarrow \pi_j(X/p)
\longrightarrow (\pi_{j-1}X)[p]
\longrightarrow0.
\end{equation}
Both end terms are killed by $p$. Thus every finite middle term is a
finite $p$-group; we do not require it to be killed by $p$ itself.
Factoring $p^{a+1}$ as $p\circ p^a$ gives exact triangles
\[
X/p^a\longrightarrow X/p^{a+1}\longrightarrow X/p.
\]
Their homotopy exact sequences inductively show that
$\pi_j(X/p^a)$ is a finite $p$-group for every $a\geq1$ and every $j$.
For fixed $j$, the inverse system of these finite groups is
Mittag--Leffler: its decreasing images in any one finite target
eventually stabilize. Its first derived inverse limit therefore
vanishes. Applying the Milnor exact sequence, in the adjacent degree
as well, and derived completeness gives
\begin{equation}\label{eq:sphere-finite-limit}
\pi_jX\ \cong\ \varprojlim_a\pi_j(X/p^a).
\end{equation}
For clarity, vanishing of the derived limit requires no surjectivity of
the transition maps. The map $1-\mathrm{shift}$ on the product of the
finite groups is surjective: every finite set of its defining equations
can be solved backwards, and compactness of the product supplies a
simultaneous solution. This is also a direct proof of the required
lim-one vanishing.
Put $M=\pi_jX$. The presentation \eqref{eq:sphere-finite-limit} makes
$M$ a compact Hausdorff pro-$p$ group with its canonical continuous
$\Zp$-module structure. On each finite target $\pi_j(X/p^a)$, this scalar structure is
defined by reducing a $p$-adic integer modulo a power of $p$ that kills
that target; the definitions are compatible with the transition
maps. Multiplication by $p$ on $M$ is continuous, so $pM$ is compact
and closed. By \eqref{eq:sphere-cofiber-short}, the quotient $M/pM$ is
finite.
Choose $a_1,\ldots,a_d\in M$ lifting generators of $M/pM$ over
$\mathbb F_p$. For $z\in M$, successively express
\[
z_\ell=\sum_{i=1}^d b_{i,\ell}a_i+pz_{\ell+1},
\qquad z_0=z,\qquad b_{i,\ell}\in\{0,\ldots,p-1\}.
\]
The scalars $c_i=\sum_{\ell\geq0}p^\ell b_{i,\ell}$ converge in $\Zp$.
The residual term after $L$ steps is $p^Lz_L$. It tends to zero in
$M$: any fixed finite target in \eqref{eq:sphere-finite-limit} is
killed by a fixed power of $p$, which kills the image of $p^Lz_L$ for
all sufficiently large $L$, independently of $z_L$. Therefore
$z=\sum_i c_i a_i$. The continuous homomorphism
\[
\Zp^d\longrightarrow M,\qquad (c_i)\longmapsto\sum_i c_i a_i
\]
is surjective. This proves finite generation as an abstract
$\Zp$-module, and not merely density of a finitely generated subgroup.
Conversely, if every $\pi_jX$ is finitely generated over $\Zp$, then
both end terms of \eqref{eq:sphere-cofiber-short} are finite. For the
$p$-torsion term, use that a submodule of a finite module over the
Noetherian ring $\Zp$ is finite as a module, and here it is killed by
$p$. The middle term is consequently finite as well.
\end{proof}
\begin{proof}[Proof of \Cref{thm:main}]
Let $X=L_{K(n)}S_p^\wedge$. A $K(n)$-local spectrum is derived
$p$-complete when $n>0$. To see this directly, the fiber of
$X\to\operatorname*{holim}_aX/p^a$ is
\[
\operatorname*{holim}(\cdots\xrightarrow{p}X\xrightarrow{p}X)
\simeq F(S[1/p],X).
\]
The spectrum $S[1/p]$ is $K(n)$-acyclic, so this mapping spectrum
vanishes by locality. This proves the required completeness without a
connectivity assumption.
The map $S\to S_p^\wedge$ is a mod-$p$ equivalence, hence a
$K(n)$-equivalence: its cofiber has invertible multiplication by $p$,
whereas multiplication by $p$ is zero on Morava $K$-theory. Exactness
of localization therefore identifies
\[
X\simeq L_{K(n)}S,\qquad X/p\simeq L_{K(n)}(S/p).
\]
The latter spectrum has finite homotopy groups in every degree by
\Cref{prop:sphere-modp}. Applying \Cref{lem:sphere-completion} proves the sphere assertion.
For the finite-spectrum formulation, consider the class of finite
$p$-local spectra $F$ for which every
$\pi_j L_{K(n)}(F\wedge S/p)$ is finite. It contains the sphere by
\Cref{prop:sphere-modp} and is closed under suspensions, finite cofiber
sequences, and retracts, by exactness and the homotopy long exact
sequence. It therefore contains every finite $p$-local spectrum.
The spectrum $L_{K(n)}F$ is derived $p$-complete by the same locality
argument, and its cofiber of $p$ is $L_{K(n)}(F\wedge S/p)$.
Applying \Cref{lem:sphere-completion} objectwise proves the full
finite-spectrum conclusion of \Cref{thm:main}.
\end{proof}
\subsection{Ranks and the height-one calculation}
Finite generation gives an abstract decomposition
\[
\pi_jL_{K(n)}S_p^\wedge
\cong\Zp^{\,r_{p,n,j}}
\oplus\bigoplus_{e\geq1}
(\mathbb Z/p^e)^{m_{p,n,j,e}},
\]
with finitely many nonzero torsion multiplicities in each degree. The
argument above establishes the existence of these finite invariants;
it does not determine the torsion multiplicities in general.
\begin{corollary}\label[corollary]{cor:sphere-ranks}
For every prime $p$, every $n\geq1$, and every $j\in\mathbb Z$, the free
rank is
\begin{equation}\label{eq:sphere-ranks}
r_{p,n,j}
=\#\left\{I\subseteq\{1,\ldots,n\}:
\sum_{i\in I}(1-2i)=j\right\}.
\end{equation}
Equivalently, these ranks are the graded dimensions of the exterior
$\Qp$-algebra on generators in degrees $-1,-3,\ldots,-(2n-1)$.
\end{corollary}
\begin{proof}
By \citet[Theorem~A]{bssw2024}, the rationalized homotopy ring is the
indicated exterior algebra. For a finitely generated $\Zp$-module its
$\Qp$-dimension after inverting $p$ is its free rank. The exterior
monomials are indexed by subsets $I$ and have the degrees in
\eqref{eq:sphere-ranks}. This proves the formula.
\end{proof}
\begin{proposition}\label[proposition]{prop:sphere-height-one}
Let $p$ be odd. Then, for every $j\in\mathbb Z$,
\[
\pi_jL_{K(1)}S_p^\wedge\cong
\begin{cases}
\Zp, & j=0\text{ or }j=-1,\\
\mathbb Z/p^{\,1+\nu_p(t)},
& j=2t-1,\quad0\neq t\in(p-1)\mathbb Z,\\
0, & \text{otherwise}.
\end{cases}
\]
The displayed groups include all additive extensions.
\end{proposition}
\begin{proof}
At height one, Morava $E$-theory is $p$-completed periodic complex
$K$-theory, with
\[
\pi_*KU_p^\wedge=\Zp[\beta^{\pm1}],\qquad |\beta|=2.
\]
The stabilizer is
$\Zp^\times=\mu_{p-1}\times(1+p\Zp)$, and the Adams operation
$\psi^a$ acts on $\beta^t$ by $a^t$.
Taking homotopy fixed points by the finite group $\mu_{p-1}$ is exact
on these coefficient modules, because $p-1$ is a unit in $\Zp$.
The resulting Adams summand, denoted $B$, has
\[
\pi_{2t}B=
\begin{cases}\Zp,&(p-1)\mid t,\\0,&(p-1)\nmid t,
\end{cases}
\qquad \pi_{2t+1}B=0.
\]
The element $1+p$ topologically generates $1+p\Zp$. Its two-term
continuous resolution, or the standard Adams-operation fiber sequence
\citep[\S\S1--2]{hopkinsKOne}, gives
\[
L_{K(1)}S_p^\wedge\longrightarrow B
\xrightarrow{\,\psi^{1+p}-1\,}B.
\]
On a retained coefficient in degree $2t$, the map is multiplication
by $(1+p)^t-1$. For $t=0$ it is zero, giving $\Zp$ in degrees $0$
and $-1$. For $t\neq0$ it is injective, and its cokernel is cyclic of
order determined by
\begin{equation}\label{eq:sphere-height-one-valuation}
\nu_p\bigl((1+p)^t-1\bigr)=1+\nu_p(t).
\end{equation}
Indeed, if $p\nmid a$, binomial expansion gives
$(1+p)^a-1\equiv ap\pmod{p^2}$. If $v_p(z)\geq1$ and $p$ is odd,
the term $pz$ in $(1+z)^p-1$ has valuation $1+v_p(z)$ and every other
term has strictly greater valuation. Iterating this observation proves
\eqref{eq:sphere-height-one-valuation} for positive $t$. For negative
$t$, the identity
\[
(1+p)^{-t}-1=-\frac{(1+p)^t-1}{(1+p)^t}
\]
shows that the valuation is unchanged by replacing $t$ with $-t$.
The cokernel for a nonzero retained $t$ lies in degree $2t-1$; there is
no kernel in degree $2t$. Coefficients in other degrees vanish. The
fiber exact sequence has at most one contributing kernel or cokernel
in each stem, so the stated groups involve no unresolved additive
extension.
\end{proof}
==== END Finite-generation-for-the-Kn-local-sphere//12-sphere.tex ====
==== BEGIN Finite-generation-for-the-Kn-local-sphere//main.tex ====
\documentclass[11pt]{article}
\input{preamble}
\title{Finite generation for the \texorpdfstring{$K(n)$}{K(n)}-local sphere}
\author{OpenAI}
\date{September 24, 2026}
\begin{document}
\maketitle
\begin{abstract}
We prove that the homotopy groups of the $K(n)$-local sphere are finitely
generated $\mathbb Z_p$-modules in every integer degree, for every prime $p$
and positive height $n$. Equivalently, the same conclusion holds after
$K(n)$-localizing any finite $p$-local spectrum. This answers the degreewise
finiteness question of Hovey and Hovey--Strickland.
\end{abstract}
\tableofcontents
\clearpage
\part{The finiteness problem and continuous coefficients}\label{part:coefficients}
\input{sections/01-introduction}
\input{sections/02-continuous-cohomology}
\clearpage
\part{Finite markings and the completed tower}\label{part:tower}
\input{sections/03-finite-markings}
\input{sections/04-completed-tower}
\clearpage
\part{Uniform supports and independent tuples}\label{part:supports}
\input{sections/05-kummer-supports}
\input{sections/06-independent-tuples}
\FloatBarrier
\clearpage
\part{Cartier transfers and Laurent supports}\label{part:cartier}
\input{sections/07-natural-transfers}
\input{sections/08-laurent-model}
\clearpage
\part{Residue cutoff and pro-transfer}\label{part:cutoff}
\input{sections/09-residue-cutoff}
\input{sections/10-pro-transfer}
\clearpage
\part{The coefficient induction}\label{part:induction}
\input{sections/11-coefficient-finiteness}
\clearpage
\part{Descent and integral homotopy}\label{part:descent}
\input{sections/12-sphere}
\begingroup
\raggedright
\bibliographystyle{plainnat}
\bibliography{sources/references}
\endgroup
\end{document}
==== END Finite-generation-for-the-Kn-local-sphere//main.tex ====
==== BEGIN Finite-generation-for-the-Kn-local-sphere//preamble.tex ====
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==== END Finite-generation-for-the-Kn-local-sphere//preamble.tex ====
==== BEGIN Finite-generation-for-the-Kn-local-sphere//support-directions.tex ====
\begin{figure}[tbp]
\centering
\begin{tikzpicture}[
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{$\colim_j\mathcal G_j\simeq\operatorname{LC}(P,\mathcal B)$\\[3pt]
Normal degree $0$ survives; slope values replicate.};
\draw[black!20] (0,-3.13) -- (1,-3.13);
\node[heading] at (0,-3.5)
{\textbf{Shrinking supports}\\[3pt]
$T_{j+1}\subset T_j$};
\node (e0) at (.35,-3.92) {$E_j$};
\node (e1) at (.62,-3.92) {$E_{j+1}$};
\draw[transition] (e1) -- node[above,font=\footnotesize]
{support inclusion} (e0);
\node[outcome] at (.74,-3.5)
{$\Rlim_j E_j\simeq\RGamma_Z(X,\mathscr E)$\\[3pt]
$H^0=H^1=0$: the low-degree systems are pro-zero.};
\node[align=center,font=\footnotesize,text width=.40\linewidth]
at (.485,-4.65) {Child-cluster support classes are summed.};
\end{tikzpicture}
\caption{The three limit directions of
\cref{rem:ind-limit-directions}. For retained coefficients $R$,
$A_a=\RGamma(L_a,R)[-2]$ is the lattice comparison model, with
$L_{a+1}=p^{-1}L_a$. On a slope patch $P$, the complex
$\mathcal G_j$ uses neighborhood sections with compact support
along the stratum; its base complex
$\mathcal B=\RGamma_c(Y_t,\mathscr E)$ is retained. The complex
$E_j$ is instead the support fiber on a fixed ambient bound $X$,
with $Z=\bigcap_jT_j$.}
\label{fig:support-directions}
\end{figure}
==== END Finite-generation-for-the-Kn-local-sphere//support-directions.tex ====
==== BEGIN Finite-generation-for-the-Kn-local-sphere//references.bib ====
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==== END Finite-generation-for-the-Kn-local-sphere//references.bib ====